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anonymous

  • 5 years ago

Laplace Transform of 10(1-e^(-3(t-1)u(t-1)?? Need haalp

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  1. anonymous
    • 5 years ago
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    i told you how to solve this yesterday

  2. anonymous
    • 5 years ago
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    i just not sure the difference with 10(1-e^(-3(t))u(t-1) and 10(1-e^(-3(t-1))u(t-1)??

  3. anonymous
    • 5 years ago
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    its pretty much the same except you have to break the exponent into two products because for example e^2t+2=e^2t*e^2 which is similar to what happens in your problem. So the e^2 in my example simply is treated as a constant

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