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anonymous

  • 5 years ago

How do you solve these equations they don’t show me in my book. Once I know how to solve these I can solve the others. (X-81)/(x-3) (X5+y5)/(x+y) (a3+6a2+12a+8)/ (a+2) (5a3+8a2-23a-1)/ (5a2-7a-2)

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  1. anonymous
    • 5 years ago
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    first one...(X-81)/(x-3)=0 x=81, 3

  2. anonymous
    • 5 years ago
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    oh there was a divide sign !!!!!!! errrrrrrr

  3. anonymous
    • 5 years ago
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    lets do it again

  4. anonymous
    • 5 years ago
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    (x-9)(x+9)/x-3) (x-3)(x+3)(x+9) /(x-3) (x+3)(x+9)

  5. anonymous
    • 5 years ago
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    ok now third one...

  6. anonymous
    • 5 years ago
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    (a3+6a2+12a+8)/ (a+2) (a+2)(a2+4a+4)/(a+2) (a+2)^2

  7. anonymous
    • 5 years ago
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    now fourth one..

  8. anonymous
    • 5 years ago
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    I think I might have asked the question wrong because and I am confusing you. They want the answer to look something like this (x2 -6x +9)/ (x-3) = (x-3)

  9. anonymous
    • 5 years ago
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    I've done the same too

  10. anonymous
    • 5 years ago
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    not to doubt you but if you doing the same thing give the answer to (x2 +8x-16)/(x+4)

  11. anonymous
    • 5 years ago
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    your question is wrong ..it should have been (x2 +8x+16)/(x+4)= (x+4)

  12. anonymous
    • 5 years ago
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    the answer (x+4) is what I was look for

  13. anonymous
    • 5 years ago
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    thats what I had to solve for

  14. anonymous
    • 5 years ago
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    happy now??

  15. anonymous
    • 5 years ago
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    noo ( again not trying to doubt your abilities) what I was checking was if your answers would look like mine. Now that I see they are what I am asking you to do is tell me the answer to the equations, because I can't see the answers your trying to give.

  16. anonymous
    • 5 years ago
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    Do u want me to do any other ques?

  17. anonymous
    • 5 years ago
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    sure

  18. anonymous
    • 5 years ago
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    which one ?

  19. anonymous
    • 5 years ago
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    I'm haveing alot of trouble with these types of questions (X5+y5)/(x+y)

  20. anonymous
    • 5 years ago
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    okay..do u know long division method ???

  21. anonymous
    • 5 years ago
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    yes

  22. anonymous
    • 5 years ago
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    i feel u can get this one done by that..

  23. anonymous
    • 5 years ago
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    I've tried but the answer keeps coming up wrong

  24. anonymous
    • 5 years ago
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    'keeps coming' means u have tried more than once... haven't u ???

  25. anonymous
    • 5 years ago
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    yes, but I get messed up in all the variables

  26. anonymous
    • 5 years ago
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    i m going to do it on paper...I'll write the answer here...lets see what we going to get...

  27. anonymous
    • 5 years ago
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    okay

  28. anonymous
    • 5 years ago
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    x4-x3y+x2y2-xy3+y3

  29. anonymous
    • 5 years ago
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    is that what u got?

  30. anonymous
    • 5 years ago
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    no, so how did you get there

  31. radar
    • 5 years ago
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    Oldnick, are the X and x the same variable

  32. anonymous
    • 5 years ago
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    ahhh !!! made a lil mistake in the end...ig guess

  33. anonymous
    • 5 years ago
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    no ...i think i was right...@radar whats ur thoughts??

  34. anonymous
    • 5 years ago
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    @radar: yes

  35. anonymous
    • 5 years ago
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    @ankur504: how did you get to your answer?

  36. anonymous
    • 5 years ago
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    long division

  37. radar
    • 5 years ago
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    Is this the problem as written in your text or worksheet?

  38. anonymous
    • 5 years ago
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    @ankur504: yeah I now that give me the proses you used.

  39. anonymous
    • 5 years ago
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    I dont know how to type that method here...sorry

  40. radar
    • 5 years ago
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    \[(x ^{5}+y ^{5})/(x+y)\]

  41. anonymous
    • 5 years ago
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    @ankur504: use the equation tool bar

  42. anonymous
    • 5 years ago
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    wait a min..

  43. anonymous
    • 5 years ago
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    @radar: the first variable looks wrong

  44. radar
    • 5 years ago
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    do you mean it is not x^5???

  45. anonymous
    • 5 years ago
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    1 Attachment
  46. radar
    • 5 years ago
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    Please restate the problem

  47. anonymous
    • 5 years ago
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    look at this pic..i havent done the full problem but thats enough to give u an idea

  48. anonymous
    • 5 years ago
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    @radar and @oldnick..what u have to say

  49. anonymous
    • 5 years ago
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    @ankur504: I can't really see what your doing

  50. anonymous
    • 5 years ago
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    i m exhausted...sry ...thats all I could do...my bad (

  51. amistre64
    • 5 years ago
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    so whats our equation that we are longjohning?

  52. radar
    • 5 years ago
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    \[(x+y)(x ^{4}-yx ^{3}+y ^{2}x ^{2}-y ^{3}x+y ^{4})\]

  53. anonymous
    • 5 years ago
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    (X5+y5)/(x+y)

  54. radar
    • 5 years ago
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    amistre64 we are trying to do (x^5+y^5/(x+Y)

  55. anonymous
    • 5 years ago
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    @amistre: could you please have a look at the picture which I've uploaded top see if I m correct or not?

  56. amistre64
    • 5 years ago
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    pic looks good, from what I can read :)

  57. radar
    • 5 years ago
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    I think I put the factors up there the (x+y) would cancel and leave the (x^4..............y^4)

  58. amistre64
    • 5 years ago
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    x^4 -x^3 y --------------------- x+y | x^5 + y^5 -x^5 -x^4 y --------------- -x^4 y +y^5 +x^4y +x^3 y^2 ----------------- +x^3 y^2 +y^5 and it keeps going till you get no x values to plug into it

  59. anonymous
    • 5 years ago
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    @amistre64: I can't understand what you did there.

  60. amistre64
    • 5 years ago
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    its just long division.... the same way you do numbers....but with xs and ys

  61. amistre64
    • 5 years ago
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    les try 27/5 we want a number that is less than but close to 5*x = 27 lets use 5 5. <- when we multiply this to the 5 we "subtract" it from the 27 ------ 5 | 27.00000 - 25 <- 5*5 = 25....but!! 27-25 is what we want for an answer ----- 20 <- this is whats left over and drop down the next "number"

  62. radar
    • 5 years ago
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    oldnick, i suggest you factor the (x^5+y^5) first using the rule \[x ^{n}+y ^{n}\] when n is odd. n is 5 so it is odd.

  63. anonymous
    • 5 years ago
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    thats the problem is that the book gives an example on how to do the equation with (x3 +1)/(x+1). but not with only variables, so I don't now what to do with variables and large numbers.

  64. amistre64
    • 5 years ago
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    5.4 ------ 5 | 27.00000 - 25 ----- 20 <- now we want a number that is 5*x = 20, use 4 :) -20 <- 5*4 = 20...but!! we want 20 - 20 for an answer.. ------- 0

  65. anonymous
    • 5 years ago
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    @radar: whats the xn+yn rule

  66. amistre64
    • 5 years ago
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    the variables that cancel go away...and you add the ones that are alike and bring down the ones that arent....

  67. radar
    • 5 years ago
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    \[(x+y)(x ^{n-1)}-yx ^{n-2}+a ^{2}x ^{n-3}-...+y ^{n-1})\] you can use this then as you see the x+y divides into the x=y giving 1 and you have the long one left which is the answer4

  68. amistre64
    • 5 years ago
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    (x) * ? is close to x^5. lets use x^4 (x+y)x^4 = x^5 + x^4 y so we subtract that to get a new round -(x^5 +x^4 y) = -x^5 -x^4 y x^4 --------------------- x+y | x^5 + y^5 -x^5 -x^4 y <- we subtract it --------------- 0 -x^4 y +y^5 <- the x^5 goes to zero and the only things left that didnt subtract to zero is brought down and worked again

  69. radar
    • 5 years ago
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    Corrections; change a to a y. remember in this case n=5

  70. amistre64
    • 5 years ago
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    (x) * ? is close to -x^4 y. lets use -x^3 y (x+y)-x^3 y = -x^4 y -x^3 y^2 so we subtract that to get a new round -(-x^4 y -x^3 y^2) = x^4 y +x^3 y^2 x^4 -x^3 y --------------------- x+y | x^5 + y^5 -x^5 -x^4 y --------------- -x^4 y +y^5 x^4 y +x^3 y^2 <- subtract it ----------------- 0 + x^3 y^2 +y^5 <-whats left that didnt subtract to zero is brought down and worked again

  71. amistre64
    • 5 years ago
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    thats the easiest way I know to explain it...

  72. amistre64
    • 5 years ago
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    on a keyboard that is :)

  73. radar
    • 5 years ago
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    The keyboard does provide limitation

  74. anonymous
    • 5 years ago
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    I'm not sure if this will help but this is what they want me to do.

  75. amistre64
    • 5 years ago
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    and that is exactly what I showed you ;)

  76. radar
    • 5 years ago
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    Then the amistre64 method (long division) is the way to go

  77. anonymous
    • 5 years ago
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    heres the problem what you showed me I can't understand

  78. amistre64
    • 5 years ago
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    x^5 + y^5 is the same as: x^5 +0x^4y +0x^3 y^2+0x^2 y^3+0x y^4+y^5 if you expand it out...

  79. anonymous
    • 5 years ago
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    right I understand that

  80. amistre64
    • 5 years ago
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    that is just impractical on the keyboard to try to use...

  81. amistre64
    • 5 years ago
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    so instead of using all those 0 place holders... ignore them.

  82. amistre64
    • 5 years ago
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    add together your like terms...and drop the rest down

  83. anonymous
    • 5 years ago
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    okay

  84. anonymous
    • 5 years ago
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    but there are no like terms

  85. amistre64
    • 5 years ago
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    x^5 +0x^4 y + ............+ y^5 -x^5 -x^4 y --------------- -x^4 y + ............. +y^5 right?

  86. anonymous
    • 5 years ago
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    thats where you loss me

  87. amistre64
    • 5 years ago
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    I just included the "like term" for you to see that its just a place holder

  88. radar
    • 5 years ago
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    The sum of equal powers can be factored. different rules for even vs odd powers. Not really different rules, just different patterns.

  89. amistre64
    • 5 years ago
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    y^5 -x^4 y ------- -x^4 y + y^5 thats all there is to it....

  90. amistre64
    • 5 years ago
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    whatever doesn subtract from each other...carries on down ....... do you see that?

  91. amistre64
    • 5 years ago
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    like terms dont combine...so both terms drop down as they are..

  92. anonymous
    • 5 years ago
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    what do the ------ stand for?

  93. amistre64
    • 5 years ago
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    unlike terms dont combine is what it should read... my fingers got lazy on me :)

  94. amistre64
    • 5 years ago
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    thats an equals bar underneath the terms to be added. 4 +5 ---- 9

  95. amistre64
    • 5 years ago
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    we can add across like this: 4+5 = 9 or we can add up and down like this: 4 +5 ---- 9

  96. amistre64
    • 5 years ago
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    when we do long division; we add/subtract in the vertical way.... keeps everything tidy

  97. amistre64
    • 5 years ago
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    yes?no? makes sense? doesnt? i need to hear from you...

  98. amistre64
    • 5 years ago
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    mind reading aint my forte :)

  99. anonymous
    • 5 years ago
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    yes I understand what ---stans for now its just I was trying to figure out the problem, The problem is that the variable keep confusing me and I don't understand were the are suppose to go.

  100. amistre64
    • 5 years ago
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    each time we find a "value" to multiply (x+y) by we want to choose a "value" the will make the first term disappear to zero. that way it is no longer bother in us and we can move down the line.

  101. amistre64
    • 5 years ago
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    How do we make (x+y) and (x^5 + y^5) have the same first term?

  102. anonymous
    • 5 years ago
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    i do not know

  103. amistre64
    • 5 years ago
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    the first terms are important..... nothing else really matters. so lets concentrate on the first terms only; ok?

  104. amistre64
    • 5 years ago
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    how do we get (x) to equal (x^5)..... we have to multiply it by some "value"

  105. amistre64
    • 5 years ago
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    x * ? = x^5 ??

  106. anonymous
    • 5 years ago
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    x^4

  107. amistre64
    • 5 years ago
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    that is absolutely correct :)

  108. anonymous
    • 5 years ago
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    x needs another x^4 to equal to x^5...

  109. amistre64
    • 5 years ago
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    so we multiply (x+y) by (x^4) and get a "value" what is: x^4 (x+y) = ???

  110. anonymous
    • 5 years ago
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    @ankur504: nope

  111. anonymous
    • 5 years ago
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    x^5+x^4y

  112. amistre64
    • 5 years ago
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    exactly :)

  113. amistre64
    • 5 years ago
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    now we need to subtract that value from (x^5 + y^5) in order to move along.... what is: -(x^5 + x^4 y ) = ???

  114. anonymous
    • 5 years ago
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    I do not know

  115. amistre64
    • 5 years ago
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    look at it again...what is: -1(x^5 +x^4 y) = ??? you know this :)

  116. anonymous
    • 5 years ago
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    -x^5-x^4y

  117. amistre64
    • 5 years ago
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    yay!!.... I knew you knew it :)

  118. amistre64
    • 5 years ago
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    now lets put this to good use shall we? what is: x^5 + 0x^4 y + ......... + y^5 -x^5 - x^4 y ------------------------ ??? ???? ???

  119. anonymous
    • 5 years ago
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    ehat do the ....... stand for

  120. amistre64
    • 5 years ago
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    ............. means all the garbage and space in between that gets in the way when using a keyboard.

  121. amistre64
    • 5 years ago
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    its the stuff thats not important to focus on fo rthe current time

  122. anonymous
    • 5 years ago
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    I thing the answer is x^5+y^5 but I might be wrong

  123. amistre64
    • 5 years ago
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    lets see what happens when we combine our like terms ok? it might be easier to see for you if we do this across.

  124. amistre64
    • 5 years ago
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    what does: x^5 - x^5 = ????

  125. anonymous
    • 5 years ago
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    0

  126. amistre64
    • 5 years ago
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    Good :) x^5 + 0x^4 y + ......... + y^5 -x^5 - x^4 y ------------------------ 0 ???? ??? Now what is this: 0x^4 y -x^4 y = ???

  127. anonymous
    • 5 years ago
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    0, but where does the other x^4y come from

  128. amistre64
    • 5 years ago
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    your gonna have to be more specific...what do you mean by the "other" x^4y? the one with the 0 stuck to it? or the one with the (-) stuck to it?

  129. anonymous
    • 5 years ago
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    both

  130. amistre64
    • 5 years ago
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    remeber this part we did: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan look at it again...what is: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan -1(x^5 +x^4 y) = ??? you know this :) 11 minutes ago oldnick Lifesaver (2 fans)Become a fan You're a fanNot a fan -x^5-x^4y <----- RIGHT HERE!!!!!!!!! 10 minutes ago amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan yay!!.... I knew you knew it :)

  131. amistre64
    • 5 years ago
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    and also this part?: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan x^5 + y^5 is the same as: x^5 +0x^4y +0x^3 y^2+0x^2 y^3+0x y^4+y^5 if you expand it out... 36 minutes ago

  132. anonymous
    • 5 years ago
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    where does the 0x^4y come from then

  133. amistre64
    • 5 years ago
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    by expanding the (x^5 + y^5) to include all the emply little spaces.

  134. anonymous
    • 5 years ago
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    thats where I'm gettting lost

  135. amistre64
    • 5 years ago
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    0 times any number equals 0 x+5 +0x^4 y + y^5 = x^5 + y^5 right?

  136. amistre64
    • 5 years ago
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    x^5 + 0 + y^5 = x^5 + y^5 .....right?

  137. anonymous
    • 5 years ago
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    yes

  138. amistre64
    • 5 years ago
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    x^5 +0 +0+0+0+y^5 = x^5 + y^5 right? alll those empty terms between x^5 ...... and .........y^5 are simply 0 terms

  139. anonymous
    • 5 years ago
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    right now I need a break, I'm going to leave for right now, okay?

  140. amistre64
    • 5 years ago
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    I could have written it like this jsut as well: x^5 + y^5 -x^5 - x^4 y ----------------------- 0 ???? ??? have fun :)

  141. amistre64
    • 5 years ago
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    I understand that what might seem simple for me, is not the same for someone else. But its the journey that we grow from ;)

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