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anonymous
 5 years ago
How do you solve these equations they don’t show me in my book. Once I know how to solve these I can solve the others.
(X81)/(x3)
(X5+y5)/(x+y)
(a3+6a2+12a+8)/ (a+2)
(5a3+8a223a1)/ (5a27a2)
anonymous
 5 years ago
How do you solve these equations they don’t show me in my book. Once I know how to solve these I can solve the others. (X81)/(x3) (X5+y5)/(x+y) (a3+6a2+12a+8)/ (a+2) (5a3+8a223a1)/ (5a27a2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first one...(X81)/(x3)=0 x=81, 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh there was a divide sign !!!!!!! errrrrrrr

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x9)(x+9)/x3) (x3)(x+3)(x+9) /(x3) (x+3)(x+9)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(a3+6a2+12a+8)/ (a+2) (a+2)(a2+4a+4)/(a+2) (a+2)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I might have asked the question wrong because and I am confusing you. They want the answer to look something like this (x2 6x +9)/ (x3) = (x3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've done the same too

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not to doubt you but if you doing the same thing give the answer to (x2 +8x16)/(x+4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your question is wrong ..it should have been (x2 +8x+16)/(x+4)= (x+4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer (x+4) is what I was look for

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what I had to solve for

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0noo ( again not trying to doubt your abilities) what I was checking was if your answers would look like mine. Now that I see they are what I am asking you to do is tell me the answer to the equations, because I can't see the answers your trying to give.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do u want me to do any other ques?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm haveing alot of trouble with these types of questions (X5+y5)/(x+y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay..do u know long division method ???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i feel u can get this one done by that..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I've tried but the answer keeps coming up wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0'keeps coming' means u have tried more than once... haven't u ???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, but I get messed up in all the variables

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i m going to do it on paper...I'll write the answer here...lets see what we going to get...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, so how did you get there

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Oldnick, are the X and x the same variable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ahhh !!! made a lil mistake in the end...ig guess

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no ...i think i was right...@radar whats ur thoughts??

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@ankur504: how did you get to your answer?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Is this the problem as written in your text or worksheet?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@ankur504: yeah I now that give me the proses you used.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I dont know how to type that method here...sorry

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x ^{5}+y ^{5})/(x+y)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@ankur504: use the equation tool bar

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@radar: the first variable looks wrong

radar
 5 years ago
Best ResponseYou've already chosen the best response.0do you mean it is not x^5???

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Please restate the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0look at this pic..i havent done the full problem but thats enough to give u an idea

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@radar and @oldnick..what u have to say

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@ankur504: I can't really see what your doing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i m exhausted...sry ...thats all I could do...my bad (

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so whats our equation that we are longjohning?

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x+y)(x ^{4}yx ^{3}+y ^{2}x ^{2}y ^{3}x+y ^{4})\]

radar
 5 years ago
Best ResponseYou've already chosen the best response.0amistre64 we are trying to do (x^5+y^5/(x+Y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre: could you please have a look at the picture which I've uploaded top see if I m correct or not?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0pic looks good, from what I can read :)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0I think I put the factors up there the (x+y) would cancel and leave the (x^4..............y^4)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^4 x^3 y  x+y  x^5 + y^5 x^5 x^4 y  x^4 y +y^5 +x^4y +x^3 y^2  +x^3 y^2 +y^5 and it keeps going till you get no x values to plug into it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@amistre64: I can't understand what you did there.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its just long division.... the same way you do numbers....but with xs and ys

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0les try 27/5 we want a number that is less than but close to 5*x = 27 lets use 5 5. < when we multiply this to the 5 we "subtract" it from the 27  5  27.00000  25 < 5*5 = 25....but!! 2725 is what we want for an answer  20 < this is whats left over and drop down the next "number"

radar
 5 years ago
Best ResponseYou've already chosen the best response.0oldnick, i suggest you factor the (x^5+y^5) first using the rule \[x ^{n}+y ^{n}\] when n is odd. n is 5 so it is odd.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats the problem is that the book gives an example on how to do the equation with (x3 +1)/(x+1). but not with only variables, so I don't now what to do with variables and large numbers.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.05.4  5  27.00000  25  20 < now we want a number that is 5*x = 20, use 4 :) 20 < 5*4 = 20...but!! we want 20  20 for an answer..  0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@radar: whats the xn+yn rule

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the variables that cancel go away...and you add the ones that are alike and bring down the ones that arent....

radar
 5 years ago
Best ResponseYou've already chosen the best response.0\[(x+y)(x ^{n1)}yx ^{n2}+a ^{2}x ^{n3}...+y ^{n1})\] you can use this then as you see the x+y divides into the x=y giving 1 and you have the long one left which is the answer4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x) * ? is close to x^5. lets use x^4 (x+y)x^4 = x^5 + x^4 y so we subtract that to get a new round (x^5 +x^4 y) = x^5 x^4 y x^4  x+y  x^5 + y^5 x^5 x^4 y < we subtract it  0 x^4 y +y^5 < the x^5 goes to zero and the only things left that didnt subtract to zero is brought down and worked again

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Corrections; change a to a y. remember in this case n=5

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(x) * ? is close to x^4 y. lets use x^3 y (x+y)x^3 y = x^4 y x^3 y^2 so we subtract that to get a new round (x^4 y x^3 y^2) = x^4 y +x^3 y^2 x^4 x^3 y  x+y  x^5 + y^5 x^5 x^4 y  x^4 y +y^5 x^4 y +x^3 y^2 < subtract it  0 + x^3 y^2 +y^5 <whats left that didnt subtract to zero is brought down and worked again

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats the easiest way I know to explain it...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0on a keyboard that is :)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The keyboard does provide limitation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure if this will help but this is what they want me to do.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and that is exactly what I showed you ;)

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Then the amistre64 method (long division) is the way to go

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0heres the problem what you showed me I can't understand

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^5 + y^5 is the same as: x^5 +0x^4y +0x^3 y^2+0x^2 y^3+0x y^4+y^5 if you expand it out...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right I understand that

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that is just impractical on the keyboard to try to use...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so instead of using all those 0 place holders... ignore them.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0add together your like terms...and drop the rest down

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but there are no like terms

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^5 +0x^4 y + ............+ y^5 x^5 x^4 y  x^4 y + ............. +y^5 right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats where you loss me

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I just included the "like term" for you to see that its just a place holder

radar
 5 years ago
Best ResponseYou've already chosen the best response.0The sum of equal powers can be factored. different rules for even vs odd powers. Not really different rules, just different patterns.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y^5 x^4 y  x^4 y + y^5 thats all there is to it....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0whatever doesn subtract from each other...carries on down ....... do you see that?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0like terms dont combine...so both terms drop down as they are..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do the  stand for?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0unlike terms dont combine is what it should read... my fingers got lazy on me :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thats an equals bar underneath the terms to be added. 4 +5  9

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we can add across like this: 4+5 = 9 or we can add up and down like this: 4 +5  9

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when we do long division; we add/subtract in the vertical way.... keeps everything tidy

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yes?no? makes sense? doesnt? i need to hear from you...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0mind reading aint my forte :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes I understand what stans for now its just I was trying to figure out the problem, The problem is that the variable keep confusing me and I don't understand were the are suppose to go.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0each time we find a "value" to multiply (x+y) by we want to choose a "value" the will make the first term disappear to zero. that way it is no longer bother in us and we can move down the line.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0How do we make (x+y) and (x^5 + y^5) have the same first term?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the first terms are important..... nothing else really matters. so lets concentrate on the first terms only; ok?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0how do we get (x) to equal (x^5)..... we have to multiply it by some "value"

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that is absolutely correct :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x needs another x^4 to equal to x^5...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so we multiply (x+y) by (x^4) and get a "value" what is: x^4 (x+y) = ???

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now we need to subtract that value from (x^5 + y^5) in order to move along.... what is: (x^5 + x^4 y ) = ???

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0look at it again...what is: 1(x^5 +x^4 y) = ??? you know this :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yay!!.... I knew you knew it :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now lets put this to good use shall we? what is: x^5 + 0x^4 y + ......... + y^5 x^5  x^4 y  ??? ???? ???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ehat do the ....... stand for

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0............. means all the garbage and space in between that gets in the way when using a keyboard.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0its the stuff thats not important to focus on fo rthe current time

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thing the answer is x^5+y^5 but I might be wrong

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lets see what happens when we combine our like terms ok? it might be easier to see for you if we do this across.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what does: x^5  x^5 = ????

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Good :) x^5 + 0x^4 y + ......... + y^5 x^5  x^4 y  0 ???? ??? Now what is this: 0x^4 y x^4 y = ???

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.00, but where does the other x^4y come from

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your gonna have to be more specific...what do you mean by the "other" x^4y? the one with the 0 stuck to it? or the one with the () stuck to it?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0remeber this part we did: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan look at it again...what is: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan 1(x^5 +x^4 y) = ??? you know this :) 11 minutes ago oldnick Lifesaver (2 fans)Become a fan You're a fanNot a fan x^5x^4y < RIGHT HERE!!!!!!!!! 10 minutes ago amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan yay!!.... I knew you knew it :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and also this part?: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan x^5 + y^5 is the same as: x^5 +0x^4y +0x^3 y^2+0x^2 y^3+0x y^4+y^5 if you expand it out... 36 minutes ago

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where does the 0x^4y come from then

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0by expanding the (x^5 + y^5) to include all the emply little spaces.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats where I'm gettting lost

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.00 times any number equals 0 x+5 +0x^4 y + y^5 = x^5 + y^5 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^5 + 0 + y^5 = x^5 + y^5 .....right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^5 +0 +0+0+0+y^5 = x^5 + y^5 right? alll those empty terms between x^5 ...... and .........y^5 are simply 0 terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right now I need a break, I'm going to leave for right now, okay?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I could have written it like this jsut as well: x^5 + y^5 x^5  x^4 y  0 ???? ??? have fun :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I understand that what might seem simple for me, is not the same for someone else. But its the journey that we grow from ;)
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