anonymous
  • anonymous
How do you solve these equations they don’t show me in my book. Once I know how to solve these I can solve the others. (X-81)/(x-3) (X5+y5)/(x+y) (a3+6a2+12a+8)/ (a+2) (5a3+8a2-23a-1)/ (5a2-7a-2)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
first one...(X-81)/(x-3)=0 x=81, 3
anonymous
  • anonymous
oh there was a divide sign !!!!!!! errrrrrrr
anonymous
  • anonymous
lets do it again

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
(x-9)(x+9)/x-3) (x-3)(x+3)(x+9) /(x-3) (x+3)(x+9)
anonymous
  • anonymous
ok now third one...
anonymous
  • anonymous
(a3+6a2+12a+8)/ (a+2) (a+2)(a2+4a+4)/(a+2) (a+2)^2
anonymous
  • anonymous
now fourth one..
anonymous
  • anonymous
I think I might have asked the question wrong because and I am confusing you. They want the answer to look something like this (x2 -6x +9)/ (x-3) = (x-3)
anonymous
  • anonymous
I've done the same too
anonymous
  • anonymous
not to doubt you but if you doing the same thing give the answer to (x2 +8x-16)/(x+4)
anonymous
  • anonymous
your question is wrong ..it should have been (x2 +8x+16)/(x+4)= (x+4)
anonymous
  • anonymous
the answer (x+4) is what I was look for
anonymous
  • anonymous
thats what I had to solve for
anonymous
  • anonymous
happy now??
anonymous
  • anonymous
noo ( again not trying to doubt your abilities) what I was checking was if your answers would look like mine. Now that I see they are what I am asking you to do is tell me the answer to the equations, because I can't see the answers your trying to give.
anonymous
  • anonymous
Do u want me to do any other ques?
anonymous
  • anonymous
sure
anonymous
  • anonymous
which one ?
anonymous
  • anonymous
I'm haveing alot of trouble with these types of questions (X5+y5)/(x+y)
anonymous
  • anonymous
okay..do u know long division method ???
anonymous
  • anonymous
yes
anonymous
  • anonymous
i feel u can get this one done by that..
anonymous
  • anonymous
I've tried but the answer keeps coming up wrong
anonymous
  • anonymous
'keeps coming' means u have tried more than once... haven't u ???
anonymous
  • anonymous
yes, but I get messed up in all the variables
anonymous
  • anonymous
i m going to do it on paper...I'll write the answer here...lets see what we going to get...
anonymous
  • anonymous
okay
anonymous
  • anonymous
x4-x3y+x2y2-xy3+y3
anonymous
  • anonymous
is that what u got?
anonymous
  • anonymous
no, so how did you get there
radar
  • radar
Oldnick, are the X and x the same variable
anonymous
  • anonymous
ahhh !!! made a lil mistake in the end...ig guess
anonymous
  • anonymous
no ...i think i was right...@radar whats ur thoughts??
anonymous
  • anonymous
@radar: yes
anonymous
  • anonymous
@ankur504: how did you get to your answer?
anonymous
  • anonymous
long division
radar
  • radar
Is this the problem as written in your text or worksheet?
anonymous
  • anonymous
@ankur504: yeah I now that give me the proses you used.
anonymous
  • anonymous
I dont know how to type that method here...sorry
radar
  • radar
\[(x ^{5}+y ^{5})/(x+y)\]
anonymous
  • anonymous
@ankur504: use the equation tool bar
anonymous
  • anonymous
wait a min..
anonymous
  • anonymous
@radar: the first variable looks wrong
radar
  • radar
do you mean it is not x^5???
anonymous
  • anonymous
1 Attachment
radar
  • radar
Please restate the problem
anonymous
  • anonymous
look at this pic..i havent done the full problem but thats enough to give u an idea
anonymous
  • anonymous
@radar and @oldnick..what u have to say
anonymous
  • anonymous
@ankur504: I can't really see what your doing
anonymous
  • anonymous
i m exhausted...sry ...thats all I could do...my bad (
amistre64
  • amistre64
so whats our equation that we are longjohning?
radar
  • radar
\[(x+y)(x ^{4}-yx ^{3}+y ^{2}x ^{2}-y ^{3}x+y ^{4})\]
anonymous
  • anonymous
(X5+y5)/(x+y)
radar
  • radar
amistre64 we are trying to do (x^5+y^5/(x+Y)
anonymous
  • anonymous
@amistre: could you please have a look at the picture which I've uploaded top see if I m correct or not?
amistre64
  • amistre64
pic looks good, from what I can read :)
radar
  • radar
I think I put the factors up there the (x+y) would cancel and leave the (x^4..............y^4)
amistre64
  • amistre64
x^4 -x^3 y --------------------- x+y | x^5 + y^5 -x^5 -x^4 y --------------- -x^4 y +y^5 +x^4y +x^3 y^2 ----------------- +x^3 y^2 +y^5 and it keeps going till you get no x values to plug into it
anonymous
  • anonymous
@amistre64: I can't understand what you did there.
amistre64
  • amistre64
its just long division.... the same way you do numbers....but with xs and ys
amistre64
  • amistre64
les try 27/5 we want a number that is less than but close to 5*x = 27 lets use 5 5. <- when we multiply this to the 5 we "subtract" it from the 27 ------ 5 | 27.00000 - 25 <- 5*5 = 25....but!! 27-25 is what we want for an answer ----- 20 <- this is whats left over and drop down the next "number"
radar
  • radar
oldnick, i suggest you factor the (x^5+y^5) first using the rule \[x ^{n}+y ^{n}\] when n is odd. n is 5 so it is odd.
anonymous
  • anonymous
thats the problem is that the book gives an example on how to do the equation with (x3 +1)/(x+1). but not with only variables, so I don't now what to do with variables and large numbers.
amistre64
  • amistre64
5.4 ------ 5 | 27.00000 - 25 ----- 20 <- now we want a number that is 5*x = 20, use 4 :) -20 <- 5*4 = 20...but!! we want 20 - 20 for an answer.. ------- 0
anonymous
  • anonymous
@radar: whats the xn+yn rule
amistre64
  • amistre64
the variables that cancel go away...and you add the ones that are alike and bring down the ones that arent....
radar
  • radar
\[(x+y)(x ^{n-1)}-yx ^{n-2}+a ^{2}x ^{n-3}-...+y ^{n-1})\] you can use this then as you see the x+y divides into the x=y giving 1 and you have the long one left which is the answer4
amistre64
  • amistre64
(x) * ? is close to x^5. lets use x^4 (x+y)x^4 = x^5 + x^4 y so we subtract that to get a new round -(x^5 +x^4 y) = -x^5 -x^4 y x^4 --------------------- x+y | x^5 + y^5 -x^5 -x^4 y <- we subtract it --------------- 0 -x^4 y +y^5 <- the x^5 goes to zero and the only things left that didnt subtract to zero is brought down and worked again
radar
  • radar
Corrections; change a to a y. remember in this case n=5
amistre64
  • amistre64
(x) * ? is close to -x^4 y. lets use -x^3 y (x+y)-x^3 y = -x^4 y -x^3 y^2 so we subtract that to get a new round -(-x^4 y -x^3 y^2) = x^4 y +x^3 y^2 x^4 -x^3 y --------------------- x+y | x^5 + y^5 -x^5 -x^4 y --------------- -x^4 y +y^5 x^4 y +x^3 y^2 <- subtract it ----------------- 0 + x^3 y^2 +y^5 <-whats left that didnt subtract to zero is brought down and worked again
amistre64
  • amistre64
thats the easiest way I know to explain it...
amistre64
  • amistre64
on a keyboard that is :)
radar
  • radar
The keyboard does provide limitation
anonymous
  • anonymous
I'm not sure if this will help but this is what they want me to do.
amistre64
  • amistre64
and that is exactly what I showed you ;)
radar
  • radar
Then the amistre64 method (long division) is the way to go
anonymous
  • anonymous
heres the problem what you showed me I can't understand
amistre64
  • amistre64
x^5 + y^5 is the same as: x^5 +0x^4y +0x^3 y^2+0x^2 y^3+0x y^4+y^5 if you expand it out...
anonymous
  • anonymous
right I understand that
amistre64
  • amistre64
that is just impractical on the keyboard to try to use...
amistre64
  • amistre64
so instead of using all those 0 place holders... ignore them.
amistre64
  • amistre64
add together your like terms...and drop the rest down
anonymous
  • anonymous
okay
anonymous
  • anonymous
but there are no like terms
amistre64
  • amistre64
x^5 +0x^4 y + ............+ y^5 -x^5 -x^4 y --------------- -x^4 y + ............. +y^5 right?
anonymous
  • anonymous
thats where you loss me
amistre64
  • amistre64
I just included the "like term" for you to see that its just a place holder
radar
  • radar
The sum of equal powers can be factored. different rules for even vs odd powers. Not really different rules, just different patterns.
amistre64
  • amistre64
y^5 -x^4 y ------- -x^4 y + y^5 thats all there is to it....
amistre64
  • amistre64
whatever doesn subtract from each other...carries on down ....... do you see that?
amistre64
  • amistre64
like terms dont combine...so both terms drop down as they are..
anonymous
  • anonymous
what do the ------ stand for?
amistre64
  • amistre64
unlike terms dont combine is what it should read... my fingers got lazy on me :)
amistre64
  • amistre64
thats an equals bar underneath the terms to be added. 4 +5 ---- 9
amistre64
  • amistre64
we can add across like this: 4+5 = 9 or we can add up and down like this: 4 +5 ---- 9
amistre64
  • amistre64
when we do long division; we add/subtract in the vertical way.... keeps everything tidy
amistre64
  • amistre64
yes?no? makes sense? doesnt? i need to hear from you...
amistre64
  • amistre64
mind reading aint my forte :)
anonymous
  • anonymous
yes I understand what ---stans for now its just I was trying to figure out the problem, The problem is that the variable keep confusing me and I don't understand were the are suppose to go.
amistre64
  • amistre64
each time we find a "value" to multiply (x+y) by we want to choose a "value" the will make the first term disappear to zero. that way it is no longer bother in us and we can move down the line.
amistre64
  • amistre64
How do we make (x+y) and (x^5 + y^5) have the same first term?
anonymous
  • anonymous
i do not know
amistre64
  • amistre64
the first terms are important..... nothing else really matters. so lets concentrate on the first terms only; ok?
amistre64
  • amistre64
how do we get (x) to equal (x^5)..... we have to multiply it by some "value"
amistre64
  • amistre64
x * ? = x^5 ??
anonymous
  • anonymous
x^4
amistre64
  • amistre64
that is absolutely correct :)
anonymous
  • anonymous
x needs another x^4 to equal to x^5...
amistre64
  • amistre64
so we multiply (x+y) by (x^4) and get a "value" what is: x^4 (x+y) = ???
anonymous
  • anonymous
@ankur504: nope
anonymous
  • anonymous
x^5+x^4y
amistre64
  • amistre64
exactly :)
amistre64
  • amistre64
now we need to subtract that value from (x^5 + y^5) in order to move along.... what is: -(x^5 + x^4 y ) = ???
anonymous
  • anonymous
I do not know
amistre64
  • amistre64
look at it again...what is: -1(x^5 +x^4 y) = ??? you know this :)
anonymous
  • anonymous
-x^5-x^4y
amistre64
  • amistre64
yay!!.... I knew you knew it :)
amistre64
  • amistre64
now lets put this to good use shall we? what is: x^5 + 0x^4 y + ......... + y^5 -x^5 - x^4 y ------------------------ ??? ???? ???
anonymous
  • anonymous
ehat do the ....... stand for
amistre64
  • amistre64
............. means all the garbage and space in between that gets in the way when using a keyboard.
amistre64
  • amistre64
its the stuff thats not important to focus on fo rthe current time
anonymous
  • anonymous
I thing the answer is x^5+y^5 but I might be wrong
amistre64
  • amistre64
lets see what happens when we combine our like terms ok? it might be easier to see for you if we do this across.
amistre64
  • amistre64
what does: x^5 - x^5 = ????
anonymous
  • anonymous
0
amistre64
  • amistre64
Good :) x^5 + 0x^4 y + ......... + y^5 -x^5 - x^4 y ------------------------ 0 ???? ??? Now what is this: 0x^4 y -x^4 y = ???
anonymous
  • anonymous
0, but where does the other x^4y come from
amistre64
  • amistre64
your gonna have to be more specific...what do you mean by the "other" x^4y? the one with the 0 stuck to it? or the one with the (-) stuck to it?
anonymous
  • anonymous
both
amistre64
  • amistre64
remeber this part we did: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan look at it again...what is: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan -1(x^5 +x^4 y) = ??? you know this :) 11 minutes ago oldnick Lifesaver (2 fans)Become a fan You're a fanNot a fan -x^5-x^4y <----- RIGHT HERE!!!!!!!!! 10 minutes ago amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan yay!!.... I knew you knew it :)
amistre64
  • amistre64
and also this part?: amistre64 Superhero (322 fans)Become a fan You're a fanNot a fan x^5 + y^5 is the same as: x^5 +0x^4y +0x^3 y^2+0x^2 y^3+0x y^4+y^5 if you expand it out... 36 minutes ago
anonymous
  • anonymous
where does the 0x^4y come from then
amistre64
  • amistre64
by expanding the (x^5 + y^5) to include all the emply little spaces.
anonymous
  • anonymous
thats where I'm gettting lost
amistre64
  • amistre64
0 times any number equals 0 x+5 +0x^4 y + y^5 = x^5 + y^5 right?
amistre64
  • amistre64
x^5 + 0 + y^5 = x^5 + y^5 .....right?
anonymous
  • anonymous
yes
amistre64
  • amistre64
x^5 +0 +0+0+0+y^5 = x^5 + y^5 right? alll those empty terms between x^5 ...... and .........y^5 are simply 0 terms
anonymous
  • anonymous
right now I need a break, I'm going to leave for right now, okay?
amistre64
  • amistre64
I could have written it like this jsut as well: x^5 + y^5 -x^5 - x^4 y ----------------------- 0 ???? ??? have fun :)
amistre64
  • amistre64
I understand that what might seem simple for me, is not the same for someone else. But its the journey that we grow from ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.