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anonymous
 5 years ago
use ratio test to determine if converge or diverge sigma n=1 to infinity 1/ne^n. after solving it this is where i am stuck n/(n+1)e
anonymous
 5 years ago
use ratio test to determine if converge or diverge sigma n=1 to infinity 1/ne^n. after solving it this is where i am stuck n/(n+1)e

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lim n>inf (n/ [(n+1)*e] ) = (1/e)* lim n>inf ( n/(n+1) ) = 1/e 1/e < 1/2 <1 and therefore it converges

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wouldn't u get infinity over infinity when u plug in n

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh when u factor 1/e and u get 1 when u take the rest of the equation to infinity
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