anonymous
  • anonymous
use ratio test to determine if converge or diverge sigma n=1 to infinity 1/ne^n. after solving it this is where i am stuck n/(n+1)e
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
lim n->inf (n/ [(n+1)*e] ) = (1/e)* lim n->inf ( n/(n+1) ) = 1/e 1/e < 1/2 <1 and therefore it converges
anonymous
  • anonymous
wouldn't u get infinity over infinity when u plug in n
anonymous
  • anonymous
oh when u factor 1/e and u get 1 when u take the rest of the equation to infinity

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anonymous
  • anonymous
exactly
anonymous
  • anonymous
k ty u i get it

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