## A community for students. Sign up today

Here's the question you clicked on:

## anonymous 5 years ago A jogger started a course and jogged an average speed of 4mph. One hour later, a cyclist started the same course and cycled at an average speed of 11mph. How long after the jogger started did the cyclist overtake the jogger?

• This Question is Closed
1. mattfeury

So you can set up an algebraic equation to solve this. You basically want to know the time at which the jogger and the cyclist are at the same position. so we have an unknown variable time, which we call 't'

2. mattfeury

for the jogger, 4mph * t = distance travelled for the cyclist, 11mph * (t-1) = distance travelled. this is (t-1) because when t = 1, the cyclist is just beginning.

3. mattfeury

$4*t = 11*(t-1)$$4*t = 11*t - 11$$11 = 7*t$$t = \frac{11}{7} seconds$

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy