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anonymous
 5 years ago
I don't see the reasoning in going straight from this limit to the answer is one.. someone help.
(((1+n^(1/7)+n^(1/6))/(2n+n^(4/3))) *
(n^(7/6)) / 1
anonymous
 5 years ago
I don't see the reasoning in going straight from this limit to the answer is one.. someone help. (((1+n^(1/7)+n^(1/6))/(2n+n^(4/3))) * (n^(7/6)) / 1

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[((1+ \sqrt[7]{n}+\sqrt[6]{n})\div(2n+ \sqrt[3]{n ^{4}}))(\sqrt[6]{n ^{7}})\] Written out a little nicer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do u need to calculate limit?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well I'm doing a limit comparison test, and they went straight from this mess to the limit equals one.. I just need to know this limit doesn't equal 0 really..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And it's as it goes to infinity

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I already wolframmed it.. I clicked show steps and there were none, lol. but i'll check it out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah.. still no steps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lim comparison test, they took the function they were evaluating, they took another function that they know how it behaves, function a/function b take lim. Limit is 1is helpful info: lim>0 says function a and function b either both converge or both diverge.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I need help understanding why exactly that limit it one. It looks like there is too much going on to start L'hopitaling it.. And the top and both both have different powers when multiplied through by n^(7/6)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For better readability: \[\frac{1 + n^{1/7} + n^{1/6}}{2n +n^{4/3}} * \frac{n^{7/5}}{1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Simplify, take lim of n^(highest exponent)/n^(highest exponent)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes except it's n^(7/6) / 1 at the end

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so distribute that n through we get \[\frac{n^{7/6} + n^{1/7 + 5/7} + n^{1/6 + 5/7}}{2n + n^{4/3}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Got my fractions upsidedown \[\frac{n^{7/6} + n^{1/7 + 7/6} + n^{1/6 + 7/6}}{2n+n^{4/3}}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol.. thats just perfect isn't it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I was trying to multiply the exponents.. I see why it's one now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So on top we have the largest power of n being \( n^{8/6}\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And on bottom, same thing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you multiply powers of the same base you add their exponents.
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