Evaluate:
anti-deriviative
3/(x-4) dx
will I use U substitute

- anonymous

Evaluate:
anti-deriviative
3/(x-4) dx
will I use U substitute

- jamiebookeater

See more answers at brainly.com

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Yes.

- anonymous

Identify your composite functions f(a) and g(x) such that 3/(x-4) = f(g(x))

- anonymous

u= x-4
du= 1

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

Yes.

- anonymous

Well, actually not quite

- anonymous

du = 1dx

- anonymous

yes I had that just forgot to type it

- anonymous

ok good.

- anonymous

ok this is where I have trouble.....will it be 3/u ???? Doesn't look right

- anonymous

That is exactly right.
If u = x-4 then 3/(x-4) = 3/u

- anonymous

so will I add 1 to the u (exponent) to be u^2

- anonymous

Not quite. realize that you basically have \[3 * \frac{1}{u}\]
So the derivative of what function of u gives you \(\frac{1}{u}\)?

- anonymous

u^-1 ??

- anonymous

1/u is u^-1

- anonymous

So it's not that. \(\frac{d}{du}[ln\ u] = \frac{1}{u}\) remember?

- anonymous

not sure what you mean about that?

- anonymous

The derivative of ln x = 1/x right?

- anonymous

ln is the natural logarithm function.

- anonymous

oh, yes it does. Too many rules.....

- anonymous

yeah, you'll get them with practice.

- anonymous

So the anti derivative of 1/x = ln x + C

- anonymous

So 3 times the anti derivative of 1/u du = ?

- anonymous

ok lost again.....
I know we have 3/u or 3 * 1/u
would it be 3lnx + c ???

- anonymous

It would be 3(ln u) + C, but then you have to plug in what u is.

- anonymous

how about
3 ln\[\left| x-4 \right|\] + C
sorry couln't get them all in one line

- anonymous

Yep, that's it exactly.

- anonymous

I am getting there......slowly.......
Thanks I really appreciate your help.

- anonymous

Of course! Just keep practicing. You're doing very well

- anonymous

I have a test next Tue. So I will be asking questions up until then. I am sure I will talk to you again..

- anonymous

ok!

- anonymous

I got really good with the derivatives, so my brain still wants to do them.

- anonymous

Yeah, I know the feeling. Soon you'll get the hang of going the other way.

- anonymous

I will start one more question before I have to leave

- anonymous

ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.