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piece o cake... :)
how you wanna solve it?
i thought so too but when i worked the equation the way i was explained didnt get the right answer
directions say to number equations 1-3 multiply (1) by 2
8x - y + z =32(-3/8) 8x - y + z =32(-1/8) 3x +2y -3z =36 x -3y +2z =-14
what is that? confusing me more
We are multiplying row 1 by a number that will turn the first term into a negative of the equation underneath it. -3x +3/8 y -3/8z = -96/8 -1x +1/8 y -1/8z = -32/8 3x + 2y -3 z = 36 x -3 y +2 z =-14 --------------------- --------------------
-3x + 3/8 y -3/8z = -12 -1x +1/8 y - 1/8z = - 4 3x +16/8y -24/8z = 36 x -24/8 y +16/8z =-14 --------------------- ---------------------- 0 +19/8y -27/8z = 24 0 -23/8y +15/8z = -28 and we end up with two equations of two variables that are easier to work with....
the way professor taught me is multiply equation (1) by 2 16x-2y+2z=64 +3x=2y-3z=36 equation (2) =19x-z=100 which becomes equation (4)
your professor choose to eliminate the "y" variable; I simply choose to start at the front and aliminatte the "x" variable. Same rules, different variable.
ok his way seems less confusing
his way keeps the fractions out :) but the process is the same. we use the "modified" equation to eliminate a variable from the other 2
oh good i hate fractions
once you know the process..... the way you get to it is up to you :)
there is no special rule about : you have to use equation 1 and multiply by a certain variable yadayadayada.... pick your poison and drink ;)
good way to put it
can we work on a different one
we can :)
x+y+z=4 2x+4y+2z=4 -x+8y-3z=-34 please leave out the fractions on my end anyway
:) lets use equation 1 since it looks the plainest and use it to "calibrate" the other 2. ok?
x + y + z =4 <- what should we mulitply this bu to get rid 2x+4y+2z =4 of a variable in the bottom equation? -------------
we want either a: -2x, or a -4y; or even a -2z... what variable you wanna destroy?
x y or z.... just pick one so we can move ahead ;)
good, we will destroy the "x" :)
the top has an "x" and the bottom has an "2x. ___ x + 2x = 0..... what do we need to fill in the blank here?
your doing it the hard way
lol..... no I aint :)
so you want me to believe that: 1x + 2x = 0?
2x + 2x = 0?
yay!!.... we hav a winner ;) -2 it is.
x + y + z =4 <- multiply everything in this top by (-2) 2x+4y+2z =4 to get -2x -2y -2z =-8 2x +4y +2z =4 ; now add them together. ----------------- 0 +2y +0 = -4 ; wow, 2 variables with one shot lol
question? y do we put - between 2y, and 2z
because we multiply by -2, tina duh
i dont understand the question... yeah, thats the ticket :)
so we get; 2y = -4; what does y equal since its all alone?
better question why do we multiply by -2
becasue you decided to destroy the x variables...... and that meant that we needed to have a number such that: ___x + 2x = 0 ; zero means they are eliminated, destroyed, kaput right?
ok got it
(__)x + 2x = 0 ; you recall that :)
you sophies choiced it lol
going for bs in accounting didnt know this kind of math would be part of it
im actually a freshman
gotta know algebra... and thats all this is :)
still trying to figure out how i made it out of hs
So, to move ahead... we came to the conclusion that both those variables vanished in the process, and we are left with 2y=-4; whats y have to be?
good, write that down someplace...y = -2 its one of your answers :)
Now we use equation (1) that you gave me and use it to eliminate "x" in the last one right? x + y + z = 4 -x +8y -3z =-34
Is there anything we have to do to this to get: x - x = 0?
do we multiply equation 1by -3?
no..... you chose "x" variable for elimination...stick with it to the end :)
ok, carry on then
(__)x -x = 0 ; what do we have to do to make this right? what number do we need to use?
that format lied to me lol
? idk x represents 1 right?
x represents x.... 1 represents 1..... but what you a really asking is: isnt there an invisible 1 in front of those? and I say , yes. and so you say, then the number we need is 1; and I say correct :)
yeah thats exactly what i was thinking
then we can multiply everything in the top by (1)...which seems pretty pointless right? but thats what we do :) x + y + z =4 <-- multiply it all by (1) and we get. -x +8y -3z =-34 x+ y+ z =4 -x+8y-3z=-34 <-- add em up --------------- 0 +7y -2z = -30
ummm 8 + 1 = 9 :) I forgot how to add :)
8y -2z = -30 now we can use this equation for some good :)
i got 9y-2z=-30
.........so did I but my fingers aint cooperating with me brain :)
im gonna have to hold them under the iron to teach them a lesson....
LOL, 8y+y would be 9y right?
Yes, I agree........but that pinky finger is revolting ;)
ok so next step is?
well, since we already determined a solid value for "y"...lets use it ....wiat for it........NOW!!
8(-2) -2z = -30 -16 - 2z = -30 -2z = -14 z = -14/-2 = 7 z = 7 yay!! write that down after you check me work..
we subtract -16 from both sides
why would we do that? -16-16 -2z = -30-16 is true, but it gets us nowhere fast. if we "add" 16 to both sides we get: -16+16 -2z = -30+16
i got z=7
me too :)
y = -2, z = 7 lets use these in any of the others equations, but equation 1 seems lonely and wants some attention...so we will use it :) x + y + z = 4 x +-2 + 7 = 4 x + 5 = 4 x = 4-5 x = -1; y=-2; z=7 is the solution to our equations.
you agree? we can double check by using these values in all the equations and seeing if the results are true...
its alot of mechanicl work, but once you know the underlying principles; the rest is just drudging thru the motions..
something isnt right
my school using mathlab and it says the answer is wrong x,y,z -1,-2,7
it was 9y instead of 8y thats y i kept getting confused
x+y+z=4 <- we know this ones good.... we used it to find x ...................................... 2(-1)+4(-2)+2(7)=4 -2 -8 +14 = 4 -10 + 14 = 4 4 = 4 ..... its good there ........................................ -(-1)+8(-2)-3(7)=-34 1 -16 -21 = -34 -14-21 = -34 -35 = -34 is off.....
the equation is -x+8y-3z=-34 but when we added that to x+y+z=4 we got 0+8y-2z=-30 it should have been 0+9y-2z=-30
1-16 = -15......
you telling me you gave me the wrong equations?
9y-2z=-30...and we used 8y right? lol
this is soooo much easier to keep track of on paper, i gotta tell ya :)
no the equations were right the math was wrong your fingers really screwed it up but just by one number the answer is x,y,z -1,-2,6
add an extra 5mins on that iron
lol.... gonna buy me one of those cigar cutters..... see what they think o that :)
lmao, so what are you majoring in
major in math hopefully; and minor in business
no wonder i just thought you were a genius with math
nah....just a normal genuis ;)
gonna take calculus 1 and stats durig the summer if the classes dont cancel
already taught myself alot up to calculus3....stats im rusty on
i hope this is all the math i have to take, WOW! i sure am glad i found you you most likely just saved this quarter for me I was crying the other night because i sucked so bad.
well, I cant teach you everything in one shot :) but most of algebra you already learned..and thats all this is
you just need to be able to see that you know it :)
i took a few years off between hs and college, and i barely passed it
hs dont count, thats for kids anyways ;)
my daughter doesnt like me to help her with her homework because what she really wants is someone to just hand her the answers ...
my son too hes 9
becoming disciplined and focused is the key...nd most kids aint acquired that skill :)
i know a few adults that havent either , i guess it really boils down to how bad you want to succeed
y = 13.9 is my guess
can i give you another equation and this time instead of helping me u just ck my answer, if you have nothing else to do
I can try :)
x+y+z=4 2x+4y+2z=4 -x+8y-3z=-34
we just did that one :)
yep sry gave you the wrong one x+y+z=5 2x+5y+2z=13 -x=9y-3z=-3
i got it already...did it on paper :)
ok gonna have to give me a min,
use the force luke...the force!!
close...but no ;)
is the z=-1
answers are: (x,y,z) (0,1,4)
nowhere near close
ok what did i do wrong
i dont know, my mind reading skills are a little lacking
oh thought that was part of being a genious
x+y+z=5 (-2) 2x+5y+2z=13 -2x-2y-2z=-10 2x+5y+2z=13 ---------------- 0 +3y + 0 = 3 ; y = 1 .............................................
I said genius not circus freak ;)
got that part right
x+y+z=5 (1) -x+9y-3z=-3 x+y+z=5 -x+9y-3z=-3 -------------- 0 +10y -2z = 2 ; since y = 1, use it here .............................................................. 10(1) -2z = 2 10 -2z = 2 -2z = -8 z = 4 ....................................
x+y+z = 5 x + 1 + 4 = 5 x + 5 = 5 x = 5-5 x = 0
your thinking: Damn!! I was thisssss close :)
i forgot to subtract 10 from both sides 2-10 =-8
aha!! that sly and coy, and other adjectivial words meaning roughly the same thing, little bugger
ok i will let you get to ur work and i will work on the rest by myself r u gonna b around in case i need help?
if I am. ill be the one with the tights and the cape ;) and the "M" on my chest..
great not sure what i could help u with but let me know,
..... k :)
Superhero hunh. lolz!!!
hey amistre64 u there