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anonymous

  • 5 years ago

complete the ordered triple 8x-y+z=32 3x+2y-3z=36 x-3y+2z=-14

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  1. amistre64
    • 5 years ago
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    piece o cake... :)

  2. amistre64
    • 5 years ago
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    how you wanna solve it?

  3. anonymous
    • 5 years ago
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    i thought so too but when i worked the equation the way i was explained didnt get the right answer

  4. anonymous
    • 5 years ago
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    directions say to number equations 1-3 multiply (1) by 2

  5. amistre64
    • 5 years ago
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    8x - y + z =32(-3/8) 8x - y + z =32(-1/8) 3x +2y -3z =36 x -3y +2z =-14

  6. anonymous
    • 5 years ago
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    what is that? confusing me more

  7. amistre64
    • 5 years ago
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    We are multiplying row 1 by a number that will turn the first term into a negative of the equation underneath it. -3x +3/8 y -3/8z = -96/8 -1x +1/8 y -1/8z = -32/8 3x + 2y -3 z = 36 x -3 y +2 z =-14 --------------------- --------------------

  8. amistre64
    • 5 years ago
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    -3x + 3/8 y -3/8z = -12 -1x +1/8 y - 1/8z = - 4 3x +16/8y -24/8z = 36 x -24/8 y +16/8z =-14 --------------------- ---------------------- 0 +19/8y -27/8z = 24 0 -23/8y +15/8z = -28 and we end up with two equations of two variables that are easier to work with....

  9. anonymous
    • 5 years ago
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    the way professor taught me is multiply equation (1) by 2 16x-2y+2z=64 +3x=2y-3z=36 equation (2) =19x-z=100 which becomes equation (4)

  10. amistre64
    • 5 years ago
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    your professor choose to eliminate the "y" variable; I simply choose to start at the front and aliminatte the "x" variable. Same rules, different variable.

  11. anonymous
    • 5 years ago
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    ok his way seems less confusing

  12. amistre64
    • 5 years ago
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    his way keeps the fractions out :) but the process is the same. we use the "modified" equation to eliminate a variable from the other 2

  13. anonymous
    • 5 years ago
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    oh good i hate fractions

  14. amistre64
    • 5 years ago
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    once you know the process..... the way you get to it is up to you :)

  15. amistre64
    • 5 years ago
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    there is no special rule about : you have to use equation 1 and multiply by a certain variable yadayadayada.... pick your poison and drink ;)

  16. anonymous
    • 5 years ago
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    good way to put it

  17. anonymous
    • 5 years ago
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    can we work on a different one

  18. amistre64
    • 5 years ago
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    we can :)

  19. anonymous
    • 5 years ago
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    x+y+z=4 2x+4y+2z=4 -x+8y-3z=-34 please leave out the fractions on my end anyway

  20. amistre64
    • 5 years ago
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    :) lets use equation 1 since it looks the plainest and use it to "calibrate" the other 2. ok?

  21. amistre64
    • 5 years ago
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    x + y + z =4 <- what should we mulitply this bu to get rid 2x+4y+2z =4 of a variable in the bottom equation? -------------

  22. amistre64
    • 5 years ago
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    we want either a: -2x, or a -4y; or even a -2z... what variable you wanna destroy?

  23. amistre64
    • 5 years ago
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    x y or z.... just pick one so we can move ahead ;)

  24. anonymous
    • 5 years ago
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    x

  25. amistre64
    • 5 years ago
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    good, we will destroy the "x" :)

  26. amistre64
    • 5 years ago
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    the top has an "x" and the bottom has an "2x. ___ x + 2x = 0..... what do we need to fill in the blank here?

  27. anonymous
    • 5 years ago
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    your doing it the hard way

  28. amistre64
    • 5 years ago
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    lol..... no I aint :)

  29. anonymous
    • 5 years ago
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    1

  30. anonymous
    • 5 years ago
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    sry 2

  31. amistre64
    • 5 years ago
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    so you want me to believe that: 1x + 2x = 0?

  32. amistre64
    • 5 years ago
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    2x + 2x = 0?

  33. anonymous
    • 5 years ago
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    -2

  34. amistre64
    • 5 years ago
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    yay!!.... we hav a winner ;) -2 it is.

  35. amistre64
    • 5 years ago
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    x + y + z =4 <- multiply everything in this top by (-2) 2x+4y+2z =4 to get -2x -2y -2z =-8 2x +4y +2z =4 ; now add them together. ----------------- 0 +2y +0 = -4 ; wow, 2 variables with one shot lol

  36. anonymous
    • 5 years ago
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    question? y do we put - between 2y, and 2z

  37. anonymous
    • 5 years ago
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    because we multiply by -2, tina duh

  38. amistre64
    • 5 years ago
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    i dont understand the question... yeah, thats the ticket :)

  39. amistre64
    • 5 years ago
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    so we get; 2y = -4; what does y equal since its all alone?

  40. anonymous
    • 5 years ago
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    better question why do we multiply by -2

  41. amistre64
    • 5 years ago
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    becasue you decided to destroy the x variables...... and that meant that we needed to have a number such that: ___x + 2x = 0 ; zero means they are eliminated, destroyed, kaput right?

  42. anonymous
    • 5 years ago
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    ok got it

  43. amistre64
    • 5 years ago
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    (__)x + 2x = 0 ; you recall that :)

  44. amistre64
    • 5 years ago
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    you sophies choiced it lol

  45. anonymous
    • 5 years ago
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    going for bs in accounting didnt know this kind of math would be part of it

  46. anonymous
    • 5 years ago
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    im actually a freshman

  47. amistre64
    • 5 years ago
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    gotta know algebra... and thats all this is :)

  48. anonymous
    • 5 years ago
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    still trying to figure out how i made it out of hs

  49. amistre64
    • 5 years ago
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    So, to move ahead... we came to the conclusion that both those variables vanished in the process, and we are left with 2y=-4; whats y have to be?

  50. anonymous
    • 5 years ago
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    -2

  51. amistre64
    • 5 years ago
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    good, write that down someplace...y = -2 its one of your answers :)

  52. amistre64
    • 5 years ago
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    Now we use equation (1) that you gave me and use it to eliminate "x" in the last one right? x + y + z = 4 -x +8y -3z =-34

  53. amistre64
    • 5 years ago
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    Is there anything we have to do to this to get: x - x = 0?

  54. anonymous
    • 5 years ago
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    do we multiply equation 1by -3?

  55. anonymous
    • 5 years ago
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    1-1=0

  56. amistre64
    • 5 years ago
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    no..... you chose "x" variable for elimination...stick with it to the end :)

  57. anonymous
    • 5 years ago
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    ok, carry on then

  58. amistre64
    • 5 years ago
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    (__)x -x = 0 ; what do we have to do to make this right? what number do we need to use?

  59. amistre64
    • 5 years ago
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    that format lied to me lol

  60. anonymous
    • 5 years ago
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    ? idk x represents 1 right?

  61. amistre64
    • 5 years ago
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    x represents x.... 1 represents 1..... but what you a really asking is: isnt there an invisible 1 in front of those? and I say , yes. and so you say, then the number we need is 1; and I say correct :)

  62. anonymous
    • 5 years ago
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    yeah thats exactly what i was thinking

  63. amistre64
    • 5 years ago
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    then we can multiply everything in the top by (1)...which seems pretty pointless right? but thats what we do :) x + y + z =4 <-- multiply it all by (1) and we get. -x +8y -3z =-34 x+ y+ z =4 -x+8y-3z=-34 <-- add em up --------------- 0 +7y -2z = -30

  64. amistre64
    • 5 years ago
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    ummm 8 + 1 = 9 :) I forgot how to add :)

  65. amistre64
    • 5 years ago
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    8y -2z = -30 now we can use this equation for some good :)

  66. anonymous
    • 5 years ago
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    i got 9y-2z=-30

  67. amistre64
    • 5 years ago
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    .........so did I but my fingers aint cooperating with me brain :)

  68. amistre64
    • 5 years ago
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    im gonna have to hold them under the iron to teach them a lesson....

  69. anonymous
    • 5 years ago
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    LOL, 8y+y would be 9y right?

  70. amistre64
    • 5 years ago
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    Yes, I agree........but that pinky finger is revolting ;)

  71. anonymous
    • 5 years ago
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    ok so next step is?

  72. amistre64
    • 5 years ago
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    well, since we already determined a solid value for "y"...lets use it ....wiat for it........NOW!!

  73. amistre64
    • 5 years ago
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    8(-2) -2z = -30 -16 - 2z = -30 -2z = -14 z = -14/-2 = 7 z = 7 yay!! write that down after you check me work..

  74. anonymous
    • 5 years ago
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    we subtract -16 from both sides

  75. amistre64
    • 5 years ago
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    why would we do that? -16-16 -2z = -30-16 is true, but it gets us nowhere fast. if we "add" 16 to both sides we get: -16+16 -2z = -30+16

  76. anonymous
    • 5 years ago
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    i got z=7

  77. amistre64
    • 5 years ago
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    me too :)

  78. amistre64
    • 5 years ago
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    y = -2, z = 7 lets use these in any of the others equations, but equation 1 seems lonely and wants some attention...so we will use it :) x + y + z = 4 x +-2 + 7 = 4 x + 5 = 4 x = 4-5 x = -1; y=-2; z=7 is the solution to our equations.

  79. amistre64
    • 5 years ago
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    you agree? we can double check by using these values in all the equations and seeing if the results are true...

  80. anonymous
    • 5 years ago
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    i agree

  81. amistre64
    • 5 years ago
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    its alot of mechanicl work, but once you know the underlying principles; the rest is just drudging thru the motions..

  82. anonymous
    • 5 years ago
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    something isnt right

  83. anonymous
    • 5 years ago
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    my school using mathlab and it says the answer is wrong x,y,z -1,-2,7

  84. anonymous
    • 5 years ago
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    it was 9y instead of 8y thats y i kept getting confused

  85. amistre64
    • 5 years ago
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    x+y+z=4 <- we know this ones good.... we used it to find x ...................................... 2(-1)+4(-2)+2(7)=4 -2 -8 +14 = 4 -10 + 14 = 4 4 = 4 ..... its good there ........................................ -(-1)+8(-2)-3(7)=-34 1 -16 -21 = -34 -14-21 = -34 -35 = -34 is off.....

  86. anonymous
    • 5 years ago
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    the equation is -x+8y-3z=-34 but when we added that to x+y+z=4 we got 0+8y-2z=-30 it should have been 0+9y-2z=-30

  87. amistre64
    • 5 years ago
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    1-16 = -15......

  88. amistre64
    • 5 years ago
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    you telling me you gave me the wrong equations?

  89. amistre64
    • 5 years ago
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    9y-2z=-30...and we used 8y right? lol

  90. amistre64
    • 5 years ago
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    this is soooo much easier to keep track of on paper, i gotta tell ya :)

  91. anonymous
    • 5 years ago
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    no the equations were right the math was wrong your fingers really screwed it up but just by one number the answer is x,y,z -1,-2,6

  92. anonymous
    • 5 years ago
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    add an extra 5mins on that iron

  93. amistre64
    • 5 years ago
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    lol.... gonna buy me one of those cigar cutters..... see what they think o that :)

  94. anonymous
    • 5 years ago
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    lmao, so what are you majoring in

  95. amistre64
    • 5 years ago
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    major in math hopefully; and minor in business

  96. anonymous
    • 5 years ago
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    no wonder i just thought you were a genius with math

  97. amistre64
    • 5 years ago
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    nah....just a normal genuis ;)

  98. amistre64
    • 5 years ago
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    gonna take calculus 1 and stats durig the summer if the classes dont cancel

  99. amistre64
    • 5 years ago
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    already taught myself alot up to calculus3....stats im rusty on

  100. anonymous
    • 5 years ago
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    i hope this is all the math i have to take, WOW! i sure am glad i found you you most likely just saved this quarter for me I was crying the other night because i sucked so bad.

  101. amistre64
    • 5 years ago
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    well, I cant teach you everything in one shot :) but most of algebra you already learned..and thats all this is

  102. amistre64
    • 5 years ago
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    you just need to be able to see that you know it :)

  103. anonymous
    • 5 years ago
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    i took a few years off between hs and college, and i barely passed it

  104. amistre64
    • 5 years ago
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    hs dont count, thats for kids anyways ;)

  105. amistre64
    • 5 years ago
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    my daughter doesnt like me to help her with her homework because what she really wants is someone to just hand her the answers ...

  106. anonymous
    • 5 years ago
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    my son too hes 9

  107. amistre64
    • 5 years ago
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    becoming disciplined and focused is the key...nd most kids aint acquired that skill :)

  108. anonymous
    • 5 years ago
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    i know a few adults that havent either , i guess it really boils down to how bad you want to succeed

  109. anonymous
    • 5 years ago
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    8.3-y=-5.6

  110. amistre64
    • 5 years ago
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    y = 13.9 is my guess

  111. anonymous
    • 5 years ago
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    can i give you another equation and this time instead of helping me u just ck my answer, if you have nothing else to do

  112. amistre64
    • 5 years ago
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    I can try :)

  113. anonymous
    • 5 years ago
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    x+y+z=4 2x+4y+2z=4 -x+8y-3z=-34

  114. amistre64
    • 5 years ago
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    we just did that one :)

  115. anonymous
    • 5 years ago
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    yep sry gave you the wrong one x+y+z=5 2x+5y+2z=13 -x=9y-3z=-3

  116. amistre64
    • 5 years ago
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    i got it already...did it on paper :)

  117. anonymous
    • 5 years ago
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    ok gonna have to give me a min,

  118. amistre64
    • 5 years ago
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    use the force luke...the force!!

  119. anonymous
    • 5 years ago
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    x,y,z 3,1,1

  120. amistre64
    • 5 years ago
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    close...but no ;)

  121. anonymous
    • 5 years ago
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    is the z=-1

  122. amistre64
    • 5 years ago
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    answers are: (x,y,z) (0,1,4)

  123. anonymous
    • 5 years ago
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    nowhere near close

  124. amistre64
    • 5 years ago
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    lol....

  125. anonymous
    • 5 years ago
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    ok what did i do wrong

  126. amistre64
    • 5 years ago
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    i dont know, my mind reading skills are a little lacking

  127. anonymous
    • 5 years ago
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    oh thought that was part of being a genious

  128. amistre64
    • 5 years ago
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    x+y+z=5 (-2) 2x+5y+2z=13 -2x-2y-2z=-10 2x+5y+2z=13 ---------------- 0 +3y + 0 = 3 ; y = 1 .............................................

  129. amistre64
    • 5 years ago
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    I said genius not circus freak ;)

  130. anonymous
    • 5 years ago
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    got that part right

  131. amistre64
    • 5 years ago
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    x+y+z=5 (1) -x+9y-3z=-3 x+y+z=5 -x+9y-3z=-3 -------------- 0 +10y -2z = 2 ; since y = 1, use it here .............................................................. 10(1) -2z = 2 10 -2z = 2 -2z = -8 z = 4 ....................................

  132. amistre64
    • 5 years ago
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    x+y+z = 5 x + 1 + 4 = 5 x + 5 = 5 x = 5-5 x = 0

  133. amistre64
    • 5 years ago
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    your thinking: Damn!! I was thisssss close :)

  134. anonymous
    • 5 years ago
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    i forgot to subtract 10 from both sides 2-10 =-8

  135. amistre64
    • 5 years ago
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    aha!! that sly and coy, and other adjectivial words meaning roughly the same thing, little bugger

  136. anonymous
    • 5 years ago
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    ok i will let you get to ur work and i will work on the rest by myself r u gonna b around in case i need help?

  137. amistre64
    • 5 years ago
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    if I am. ill be the one with the tights and the cape ;) and the "M" on my chest..

  138. anonymous
    • 5 years ago
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    great not sure what i could help u with but let me know,

  139. amistre64
    • 5 years ago
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    ..... k :)

  140. anonymous
    • 5 years ago
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    Superhero hunh. lolz!!!

  141. anonymous
    • 5 years ago
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    hey amistre64 u there

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spraguer (Moderator)
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