Solve differential equation using inverse laplace transform: y''+2y'-3y=6e^(-2t)

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Solve differential equation using inverse laplace transform: y''+2y'-3y=6e^(-2t)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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I end up doing a partial fraction decomposition and get -3e^(-2t) + 11/2e^(-3t) - 3/2e^t, which is almost right except the actual answer is -2e^(-2t) + 11/2e^(-3t)-3/2e^t. I can't figure out what I'm doing wrong
y(0)=? and y'(0)=?
Oh, sorry. y(0)=2 and y'(0)=-14

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thank you, i found the mistake i made in my work by comparing.

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