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these two i had to find the base area... and i got them wrong

traingle and a circle

Correct. What kind of triangle? It's a *regular* pyramid.

equallaterial

for the triangle wouldnt it be 1/2*4*4=8cm

Nope, its height does not equal 4.

what is the height

yea...
for the cone the base area would be 113.0976 or 113.1in

\[113.1 in^{2} \]
That is square inches. Correct.

i still dont know how to find the base area of the pyramid

Area of base: ½b×h

1/24*7=14cm

1/2*4*7=14cm

The wikipedia page about equilateral triangles has the formula that uses only the side length.

1/2*4*7=14cm so this isnt right

No, it's not right.

i give up

A=\frac{\sqrt{3}}{4} a^2

Yes, this one.

6.93

Correct!

okay.. how are these two wrong.. finding the volume

the first one the base area would be 10.83

Indeed.

so the volume would be 32.49in cubed

True.

what formula would i use to get the base area for the hexagon

It consists of six equilateral triangles.

\[\sqrt{6}\div4\times3^{3}\]

\[3^{3}?\]

7^3

Let's do it more slowly. What's the area of one of the triangles that form that hexagon?

\[\sqrt{3}\div4\times7^{3}\]

7^2

Yes. And there's six of them. So the area of the whole hexagon is..?

21.21*5

5?

21.22*6

Much better. You can get the correct volume now.

127.31

Looks good to me.

381.92 would be the volume?

No, you must have missed something in the formula for volume.

127.31 this is the area of one side base or all

There's only one base in this case.

127.31 is the base area right

Yes.

than to get the volume dont i * by 3

You do, but there's a division there too.

190.97

Pyramid (1/3) * (base area) * height

That's the correct formula, yes. Height is 3cm if I read the picture correctly.

yeah

(1/3) * 3 * 127.31 = ..?

190.97cm^3

127.32 * 3 / 3 = ..?

127.32

Aye.

(127.32 * 3) / 3 = 127.32