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anonymous
 5 years ago
will someone please help me with these 9 problems that i have already did and got wrong... Please help
anonymous
 5 years ago
will someone please help me with these 9 problems that i have already did and got wrong... Please help

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0these two i had to find the base area... and i got them wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are the shapes of bases on each picture? What are the formulas to calculate areas of these figures?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0traingle and a circle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correct. What kind of triangle? It's a *regular* pyramid.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yup. So you have to find an area of a circle given it's radius and an area of an equilateral triangle given the length of this side. Both formulas can be found easily, e.g. on wikipedia. If you want an additional challenge you can devise the formula for triangle using the Pythagorean theorem (if you draw its height you'll get a right triangle).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the triangle wouldnt it be 1/2*4*4=8cm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nope, its height does not equal 4.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0"Altitude" is another word. http://en.wikipedia.org/wiki/Altitude_%28triangle%29 I assume you used the formula for triangle that's given as area = 1/2 * base * height.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea... for the cone the base area would be 113.0976 or 113.1in

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[113.1 in^{2} \] That is square inches. Correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i still dont know how to find the base area of the pyramid

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The wikipedia page about equilateral triangles has the formula that uses only the side length.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/2*4*7=14cm so this isnt right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Too early. You're given an equilateral triangle with side length of 4cm. Apply the formula from: http://en.wikipedia.org/wiki/Equilateral_triangle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A=\frac{\sqrt{3}}{4} a^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay.. how are these two wrong.. finding the volume

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In both cases you got the base area wrong. First case is the same as the problem you've just solved. Second one has a base that can be thought of as consisting of multiple triangles.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the first one the base area would be 10.83

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the volume would be 32.49in cubed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what formula would i use to get the base area for the hexagon

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It consists of six equilateral triangles.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{6}\div4\times3^{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let's do it more slowly. What's the area of one of the triangles that form that hexagon?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{3}\div4\times7^{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes. And there's six of them. So the area of the whole hexagon is..?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Much better. You can get the correct volume now.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0381.92 would be the volume?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, you must have missed something in the formula for volume.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0127.31 this is the area of one side base or all

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There's only one base in this case.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0127.31 is the base area right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0than to get the volume dont i * by 3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You do, but there's a division there too.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Pyramid (1/3) * (base area) * height

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's the correct formula, yes. Height is 3cm if I read the picture correctly.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(1/3) * 3 * 127.31 = ..?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(127.32 * 3) / 3 = 127.32

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Multiply by the numerator, divide by denominator. That's how you multiply a number by fraction. Surprisingly 127.32 cubic centimeters is the answer. It's the same number as the base area, but unit differs (cubed vs squared).
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