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anonymous

  • 5 years ago

will someone please help me with these 9 problems that i have already did and got wrong... Please help

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  1. anonymous
    • 5 years ago
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    these two i had to find the base area... and i got them wrong

  2. anonymous
    • 5 years ago
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    What are the shapes of bases on each picture? What are the formulas to calculate areas of these figures?

  3. anonymous
    • 5 years ago
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    traingle and a circle

  4. anonymous
    • 5 years ago
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    Correct. What kind of triangle? It's a *regular* pyramid.

  5. anonymous
    • 5 years ago
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    equallaterial

  6. anonymous
    • 5 years ago
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    Yup. So you have to find an area of a circle given it's radius and an area of an equilateral triangle given the length of this side. Both formulas can be found easily, e.g. on wikipedia. If you want an additional challenge you can devise the formula for triangle using the Pythagorean theorem (if you draw its height you'll get a right triangle).

  7. anonymous
    • 5 years ago
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    for the triangle wouldnt it be 1/2*4*4=8cm

  8. anonymous
    • 5 years ago
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    Nope, its height does not equal 4.

  9. anonymous
    • 5 years ago
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    what is the height

  10. anonymous
    • 5 years ago
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    "Altitude" is another word. http://en.wikipedia.org/wiki/Altitude_%28triangle%29 I assume you used the formula for triangle that's given as area = 1/2 * base * height.

  11. anonymous
    • 5 years ago
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    yea... for the cone the base area would be 113.0976 or 113.1in

  12. anonymous
    • 5 years ago
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    \[113.1 in^{2} \] That is square inches. Correct.

  13. anonymous
    • 5 years ago
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    i still dont know how to find the base area of the pyramid

  14. anonymous
    • 5 years ago
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    Area of base: ½b×h

  15. anonymous
    • 5 years ago
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    1/24*7=14cm

  16. anonymous
    • 5 years ago
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    1/2*4*7=14cm

  17. anonymous
    • 5 years ago
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    The wikipedia page about equilateral triangles has the formula that uses only the side length.

  18. anonymous
    • 5 years ago
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    1/2*4*7=14cm so this isnt right

  19. anonymous
    • 5 years ago
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    No, it's not right.

  20. anonymous
    • 5 years ago
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    i give up

  21. anonymous
    • 5 years ago
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    Too early. You're given an equilateral triangle with side length of 4cm. Apply the formula from: http://en.wikipedia.org/wiki/Equilateral_triangle

  22. anonymous
    • 5 years ago
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    A=\frac{\sqrt{3}}{4} a^2

  23. anonymous
    • 5 years ago
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    Yes, this one.

  24. anonymous
    • 5 years ago
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    6.93

  25. anonymous
    • 5 years ago
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    Correct!

  26. anonymous
    • 5 years ago
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    okay.. how are these two wrong.. finding the volume

  27. anonymous
    • 5 years ago
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    In both cases you got the base area wrong. First case is the same as the problem you've just solved. Second one has a base that can be thought of as consisting of multiple triangles.

  28. anonymous
    • 5 years ago
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    the first one the base area would be 10.83

  29. anonymous
    • 5 years ago
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    Indeed.

  30. anonymous
    • 5 years ago
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    so the volume would be 32.49in cubed

  31. anonymous
    • 5 years ago
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    True.

  32. anonymous
    • 5 years ago
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    what formula would i use to get the base area for the hexagon

  33. anonymous
    • 5 years ago
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    It consists of six equilateral triangles.

  34. anonymous
    • 5 years ago
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    \[\sqrt{6}\div4\times3^{3}\]

  35. anonymous
    • 5 years ago
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    \[3^{3}?\]

  36. anonymous
    • 5 years ago
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    7^3

  37. anonymous
    • 5 years ago
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    Let's do it more slowly. What's the area of one of the triangles that form that hexagon?

  38. anonymous
    • 5 years ago
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    \[\sqrt{3}\div4\times7^{3}\]

  39. anonymous
    • 5 years ago
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    7^2

  40. anonymous
    • 5 years ago
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    Yes. And there's six of them. So the area of the whole hexagon is..?

  41. anonymous
    • 5 years ago
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    21.21*5

  42. anonymous
    • 5 years ago
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    5?

  43. anonymous
    • 5 years ago
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    21.22*6

  44. anonymous
    • 5 years ago
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    Much better. You can get the correct volume now.

  45. anonymous
    • 5 years ago
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    127.31

  46. anonymous
    • 5 years ago
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    Looks good to me.

  47. anonymous
    • 5 years ago
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    381.92 would be the volume?

  48. anonymous
    • 5 years ago
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    No, you must have missed something in the formula for volume.

  49. anonymous
    • 5 years ago
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    127.31 this is the area of one side base or all

  50. anonymous
    • 5 years ago
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    There's only one base in this case.

  51. anonymous
    • 5 years ago
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    127.31 is the base area right

  52. anonymous
    • 5 years ago
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    Yes.

  53. anonymous
    • 5 years ago
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    than to get the volume dont i * by 3

  54. anonymous
    • 5 years ago
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    You do, but there's a division there too.

  55. anonymous
    • 5 years ago
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    190.97

  56. anonymous
    • 5 years ago
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    Pyramid (1/3) * (base area) * height

  57. anonymous
    • 5 years ago
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    That's the correct formula, yes. Height is 3cm if I read the picture correctly.

  58. anonymous
    • 5 years ago
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    yeah

  59. anonymous
    • 5 years ago
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    (1/3) * 3 * 127.31 = ..?

  60. anonymous
    • 5 years ago
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    190.97cm^3

  61. anonymous
    • 5 years ago
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    127.32 * 3 / 3 = ..?

  62. anonymous
    • 5 years ago
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    127.32

  63. anonymous
    • 5 years ago
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    Aye.

  64. anonymous
    • 5 years ago
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    (127.32 * 3) / 3 = 127.32

  65. anonymous
    • 5 years ago
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    Multiply by the numerator, divide by denominator. That's how you multiply a number by fraction. Surprisingly 127.32 cubic centimeters is the answer. It's the same number as the base area, but unit differs (cubed vs squared).

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