will someone please help me with these 9 problems that i have already did and got wrong... Please help

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will someone please help me with these 9 problems that i have already did and got wrong... Please help

Mathematics
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these two i had to find the base area... and i got them wrong
What are the shapes of bases on each picture? What are the formulas to calculate areas of these figures?
traingle and a circle

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Other answers:

Correct. What kind of triangle? It's a *regular* pyramid.
equallaterial
Yup. So you have to find an area of a circle given it's radius and an area of an equilateral triangle given the length of this side. Both formulas can be found easily, e.g. on wikipedia. If you want an additional challenge you can devise the formula for triangle using the Pythagorean theorem (if you draw its height you'll get a right triangle).
for the triangle wouldnt it be 1/2*4*4=8cm
Nope, its height does not equal 4.
what is the height
"Altitude" is another word. http://en.wikipedia.org/wiki/Altitude_%28triangle%29 I assume you used the formula for triangle that's given as area = 1/2 * base * height.
yea... for the cone the base area would be 113.0976 or 113.1in
\[113.1 in^{2} \] That is square inches. Correct.
i still dont know how to find the base area of the pyramid
Area of base: ½b×h
1/24*7=14cm
1/2*4*7=14cm
The wikipedia page about equilateral triangles has the formula that uses only the side length.
1/2*4*7=14cm so this isnt right
No, it's not right.
i give up
Too early. You're given an equilateral triangle with side length of 4cm. Apply the formula from: http://en.wikipedia.org/wiki/Equilateral_triangle
A=\frac{\sqrt{3}}{4} a^2
Yes, this one.
6.93
Correct!
okay.. how are these two wrong.. finding the volume
In both cases you got the base area wrong. First case is the same as the problem you've just solved. Second one has a base that can be thought of as consisting of multiple triangles.
the first one the base area would be 10.83
Indeed.
so the volume would be 32.49in cubed
True.
what formula would i use to get the base area for the hexagon
It consists of six equilateral triangles.
\[\sqrt{6}\div4\times3^{3}\]
\[3^{3}?\]
7^3
Let's do it more slowly. What's the area of one of the triangles that form that hexagon?
\[\sqrt{3}\div4\times7^{3}\]
7^2
Yes. And there's six of them. So the area of the whole hexagon is..?
21.21*5
5?
21.22*6
Much better. You can get the correct volume now.
127.31
Looks good to me.
381.92 would be the volume?
No, you must have missed something in the formula for volume.
127.31 this is the area of one side base or all
There's only one base in this case.
127.31 is the base area right
Yes.
than to get the volume dont i * by 3
You do, but there's a division there too.
190.97
Pyramid (1/3) * (base area) * height
That's the correct formula, yes. Height is 3cm if I read the picture correctly.
yeah
(1/3) * 3 * 127.31 = ..?
190.97cm^3
127.32 * 3 / 3 = ..?
127.32
Aye.
(127.32 * 3) / 3 = 127.32
Multiply by the numerator, divide by denominator. That's how you multiply a number by fraction. Surprisingly 127.32 cubic centimeters is the answer. It's the same number as the base area, but unit differs (cubed vs squared).

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