anonymous
  • anonymous
will someone please help me with these 9 problems that i have already did and got wrong... Please help
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
these two i had to find the base area... and i got them wrong
anonymous
  • anonymous
What are the shapes of bases on each picture? What are the formulas to calculate areas of these figures?
anonymous
  • anonymous
traingle and a circle

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Correct. What kind of triangle? It's a *regular* pyramid.
anonymous
  • anonymous
equallaterial
anonymous
  • anonymous
Yup. So you have to find an area of a circle given it's radius and an area of an equilateral triangle given the length of this side. Both formulas can be found easily, e.g. on wikipedia. If you want an additional challenge you can devise the formula for triangle using the Pythagorean theorem (if you draw its height you'll get a right triangle).
anonymous
  • anonymous
for the triangle wouldnt it be 1/2*4*4=8cm
anonymous
  • anonymous
Nope, its height does not equal 4.
anonymous
  • anonymous
what is the height
anonymous
  • anonymous
"Altitude" is another word. http://en.wikipedia.org/wiki/Altitude_%28triangle%29 I assume you used the formula for triangle that's given as area = 1/2 * base * height.
anonymous
  • anonymous
yea... for the cone the base area would be 113.0976 or 113.1in
anonymous
  • anonymous
\[113.1 in^{2} \] That is square inches. Correct.
anonymous
  • anonymous
i still dont know how to find the base area of the pyramid
anonymous
  • anonymous
Area of base: ½b×h
anonymous
  • anonymous
1/24*7=14cm
anonymous
  • anonymous
1/2*4*7=14cm
anonymous
  • anonymous
The wikipedia page about equilateral triangles has the formula that uses only the side length.
anonymous
  • anonymous
1/2*4*7=14cm so this isnt right
anonymous
  • anonymous
No, it's not right.
anonymous
  • anonymous
i give up
anonymous
  • anonymous
Too early. You're given an equilateral triangle with side length of 4cm. Apply the formula from: http://en.wikipedia.org/wiki/Equilateral_triangle
anonymous
  • anonymous
A=\frac{\sqrt{3}}{4} a^2
anonymous
  • anonymous
Yes, this one.
anonymous
  • anonymous
6.93
anonymous
  • anonymous
Correct!
anonymous
  • anonymous
okay.. how are these two wrong.. finding the volume
anonymous
  • anonymous
In both cases you got the base area wrong. First case is the same as the problem you've just solved. Second one has a base that can be thought of as consisting of multiple triangles.
anonymous
  • anonymous
the first one the base area would be 10.83
anonymous
  • anonymous
Indeed.
anonymous
  • anonymous
so the volume would be 32.49in cubed
anonymous
  • anonymous
True.
anonymous
  • anonymous
what formula would i use to get the base area for the hexagon
anonymous
  • anonymous
It consists of six equilateral triangles.
anonymous
  • anonymous
\[\sqrt{6}\div4\times3^{3}\]
anonymous
  • anonymous
\[3^{3}?\]
anonymous
  • anonymous
7^3
anonymous
  • anonymous
Let's do it more slowly. What's the area of one of the triangles that form that hexagon?
anonymous
  • anonymous
\[\sqrt{3}\div4\times7^{3}\]
anonymous
  • anonymous
7^2
anonymous
  • anonymous
Yes. And there's six of them. So the area of the whole hexagon is..?
anonymous
  • anonymous
21.21*5
anonymous
  • anonymous
5?
anonymous
  • anonymous
21.22*6
anonymous
  • anonymous
Much better. You can get the correct volume now.
anonymous
  • anonymous
127.31
anonymous
  • anonymous
Looks good to me.
anonymous
  • anonymous
381.92 would be the volume?
anonymous
  • anonymous
No, you must have missed something in the formula for volume.
anonymous
  • anonymous
127.31 this is the area of one side base or all
anonymous
  • anonymous
There's only one base in this case.
anonymous
  • anonymous
127.31 is the base area right
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
than to get the volume dont i * by 3
anonymous
  • anonymous
You do, but there's a division there too.
anonymous
  • anonymous
190.97
anonymous
  • anonymous
Pyramid (1/3) * (base area) * height
anonymous
  • anonymous
That's the correct formula, yes. Height is 3cm if I read the picture correctly.
anonymous
  • anonymous
yeah
anonymous
  • anonymous
(1/3) * 3 * 127.31 = ..?
anonymous
  • anonymous
190.97cm^3
anonymous
  • anonymous
127.32 * 3 / 3 = ..?
anonymous
  • anonymous
127.32
anonymous
  • anonymous
Aye.
anonymous
  • anonymous
(127.32 * 3) / 3 = 127.32
anonymous
  • anonymous
Multiply by the numerator, divide by denominator. That's how you multiply a number by fraction. Surprisingly 127.32 cubic centimeters is the answer. It's the same number as the base area, but unit differs (cubed vs squared).

Looking for something else?

Not the answer you are looking for? Search for more explanations.