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anonymous
 5 years ago
Solve differential equation using inverse laplace transform: y''4y'+3y=6t8, y(0)=y'(0)=0.
anonymous
 5 years ago
Solve differential equation using inverse laplace transform: y''4y'+3y=6t8, y(0)=y'(0)=0.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[Y=(68s)\div((s3)(s1)s^2)\] is what I have so far, I know I need to do partial fraction decomp and the integral because of the s^2 in the denominator. Does it matter which I do first?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there's no integration involved, you simply have to use partial fractions so it is in a more appropriate form to inverse laplace

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Don't you have to do partial fractions to solve (68s)/((s3)(s1), and then something with an integral to deal with the s^2 in the denominator? Partial fractions doesn't give me a complete answer. I can get e^te^3t, but the answer also includes a 2t which I'm not getting

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nevermind, I got it. You were right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, laplace is pretty much always the same process so if you get that down it's just algebra after that
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