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anonymous
 5 years ago
y=2x^28x+7
i have to find the axis of symmetry
the coordinates of the vertex
and tell whether the vertex is a maximum or a minimum
anonymous
 5 years ago
y=2x^28x+7 i have to find the axis of symmetry the coordinates of the vertex and tell whether the vertex is a maximum or a minimum

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b/2a ia axis of symmetry 8/2.2 8/4 = 2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ia is stupidity for "is" ...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y = 2x^2  8x + 7\] \[ = 2(x^2  4x) + 7\] \[= 2(x^2 4x + 4) 8 + 7\] \[\implies y +1 = 2(x2)^2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we have a parabola which is shifted 1 unit up in y and 2 units forward in x and grows twice as fast as the standard parabola.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Err shifted 1 unit down in y, sorry.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh ok u got me confused 4 a sec

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what part of the problem are u helping with

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Finding the vertex, and the axis of symmetry.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Actually this form of the function answers all of those questions.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did not learn it that way can u help me another way by chance

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Since the coefficient of x is positive, the graph is opening upward. Therefore the vertex will be a min. The location of the vertex can be found from the shift in x and y of the function from (0,0). In this case we shifted down 1 unit and 2 units to the right. \[yy_0 = m(xx_0)^2\] Is the standard form for a parabola. Where \(x_0,y_0\) are the x and y points of your vertex. And m is the scaling and directional coefficient. So we have \(y  (1) = 2(x  2)^2\) which tells us the vertex is at (2,1) And since the graph is opening upward the line x = 2 will be the line of symmetry (the line going up/down that goes through the vertex)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you soooooo much
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