i have to find the axis of symmetry
the coordinates of the vertex
and tell whether the vertex is a maximum or a minimum
Stacey Warren - Expert brainly.com
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So we have a parabola which is shifted 1 unit up in y and 2 units forward in x and grows twice as fast as the standard parabola.
Err shifted 1 unit down in y, sorry.
oh ok u got me confused 4 a sec
what part of the problem are u helping with
Finding the vertex, and the axis of symmetry.
Actually this form of the function answers all of those questions.
i did not learn it that way can u help me another way by chance
Since the coefficient of x is positive, the graph is opening upward. Therefore the vertex will be a min. The location of the vertex can be found from the shift in x and y of the function from (0,0). In this case we shifted down 1 unit and 2 units to the right.
\[y-y_0 = m(x-x_0)^2\]
Is the standard form for a parabola. Where \(x_0,y_0\) are the x and y points of your vertex. And m is the scaling and directional coefficient.
So we have \(y - (-1) = 2(x - 2)^2\) which tells us the vertex is at (2,-1)
And since the graph is opening upward the line x = 2 will be the line of symmetry (the line going up/down that goes through the vertex)