y=2x^2-8x+7 i have to find the axis of symmetry the coordinates of the vertex and tell whether the vertex is a maximum or a minimum

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

y=2x^2-8x+7 i have to find the axis of symmetry the coordinates of the vertex and tell whether the vertex is a maximum or a minimum

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

-b/2a ia axis of symmetry --8/2.2 8/4 = 2
ia is stupidity for "is" ...
haha thank you

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[y = 2x^2 - 8x + 7\] \[ = 2(x^2 - 4x) + 7\] \[= 2(x^2 -4x + 4) -8 + 7\] \[\implies y +1 = 2(x-2)^2\]
So we have a parabola which is shifted 1 unit up in y and 2 units forward in x and grows twice as fast as the standard parabola.
Err shifted 1 unit down in y, sorry.
oh ok u got me confused 4 a sec
what part of the problem are u helping with
Finding the vertex, and the axis of symmetry.
Actually this form of the function answers all of those questions.
i did not learn it that way can u help me another way by chance
Since the coefficient of x is positive, the graph is opening upward. Therefore the vertex will be a min. The location of the vertex can be found from the shift in x and y of the function from (0,0). In this case we shifted down 1 unit and 2 units to the right. \[y-y_0 = m(x-x_0)^2\] Is the standard form for a parabola. Where \(x_0,y_0\) are the x and y points of your vertex. And m is the scaling and directional coefficient. So we have \(y - (-1) = 2(x - 2)^2\) which tells us the vertex is at (2,-1) And since the graph is opening upward the line x = 2 will be the line of symmetry (the line going up/down that goes through the vertex)
thank you soooooo much

Not the answer you are looking for?

Search for more explanations.

Ask your own question