Use the quadratic formula to find the zeros of the function. Round to tenths if necessary. y = 17x2 - 21
So since its not in ax^2 + bx + c wouldnt it be no real solution?
A. {-1.1, 1.1}
B. {1.1}
C. {-4.1, 4.6}
D. no real solution

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why isn't it \[ax^2 + bx + c\]
?
b is simply zero...

oh i seeee wow my dad told me otherwise :P

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