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anonymous

  • 5 years ago

Differentiation: The two tangents to the curve y=x^2 at the points where y=9 intersect at the point P. Find the coordinates of P.

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  1. myininaya
    • 5 years ago
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    this is what I think: if y=9, then 9=x^2 implies x=3 and x=-3 the slope of the tangent line at x=3 and x=-3 can be found by finding the derivative. If you write both equations of each line, you should get that they intersect the y-axis at the same point which is (0,-9)

  2. anonymous
    • 5 years ago
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    wow, i was confused about what the question was asking for and now it makes complete sense.

  3. anonymous
    • 5 years ago
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    thank you!

  4. myininaya
    • 5 years ago
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    np

  5. anonymous
    • 5 years ago
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    so i got the equations y=-6x-9 and y=6x-9. how do i solve for the intersecting point?

  6. myininaya
    • 5 years ago
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    well look at the y-intercepts of each line

  7. anonymous
    • 5 years ago
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    for future problems, how would i find the intercept if the linear equations didn't have the same y-intercept?

  8. myininaya
    • 5 years ago
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    the y-intercepts are the same so they intersect at (0,-9)

  9. myininaya
    • 5 years ago
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    set them equal to each other. my computer is going slow

  10. anonymous
    • 5 years ago
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    before you crash, know i'm thankful haha

  11. myininaya
    • 5 years ago
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    lol i can try to make a problem like this where the y intercepts are not the same

  12. anonymous
    • 5 years ago
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    i get it it's ok :)

  13. myininaya
    • 5 years ago
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    ok

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