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anonymous
 5 years ago
can you help me?
anonymous
 5 years ago
can you help me?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0depends on the trig but should be able to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's solving equations using identities.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find all values of (theda symbol) on the interval 0 more than or equal to (theda) more than or equal to 360 that solve sin(2(theda))=sin(theda)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can't type symbols lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find all values of Ө on the interval 0≤Ө≤360 that solve sin(2Ө)=sinӨ

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok this is fairly simple

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know that sine is a function who's curve repeats it self over and over, a function that does this is called a periodic function, meaning it has a period upon which it repeats its self, in the case of sine and cosine they are periodic about 2PI

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sine at zero is equal zero, one could also say that sin(0*Pi) = 0 because zero times pi also equals zero thus it is the same as saying sin(0)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the sine curve oscillates between 1 and 1 with a period of 2 pi, so at zero sin =0, at 90* which is equal to pi/2 radians sine hits one, then comes back down to zero at 180* or pi radians, it then goes down under the x axis and touches 1 at sine(270*) or 3pi/2 radians, then back up to zero when it hits 360* or 2pi radians. so sine(0)=0 , sine(pi/2)=1, sine(pi)=0, sine(3pi/2) = 1, and sine(pi)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0however there are other values between these angles such as sin(pi/4) , pi/6, ect... so you would need to check for those values as well. the easiest way to do this is by drawing or looking at a unit circle. are you familiar with the unit circle?
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