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anonymous

  • 5 years ago

can you help me?

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  1. anonymous
    • 5 years ago
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    with what

  2. anonymous
    • 5 years ago
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    trig

  3. anonymous
    • 5 years ago
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    ?

  4. anonymous
    • 5 years ago
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    depends on the trig but should be able to

  5. anonymous
    • 5 years ago
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    it's solving equations using identities.

  6. anonymous
    • 5 years ago
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    yea depends :3

  7. anonymous
    • 5 years ago
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    i know

  8. anonymous
    • 5 years ago
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    <->

  9. anonymous
    • 5 years ago
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    lol

  10. anonymous
    • 5 years ago
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    first question...

  11. anonymous
    • 5 years ago
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    Find all values of (theda symbol) on the interval 0 more than or equal to (theda) more than or equal to 360 that solve sin(2(theda))=sin(theda)

  12. anonymous
    • 5 years ago
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    Can't type symbols lol

  13. anonymous
    • 5 years ago
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    Find all values of Ө on the interval 0≤Ө≤360 that solve sin(2Ө)=sinӨ

  14. anonymous
    • 5 years ago
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    ok this is fairly simple

  15. anonymous
    • 5 years ago
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    you know that sine is a function who's curve repeats it self over and over, a function that does this is called a periodic function, meaning it has a period upon which it repeats its self, in the case of sine and cosine they are periodic about 2PI

  16. anonymous
    • 5 years ago
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    sine at zero is equal zero, one could also say that sin(0*Pi) = 0 because zero times pi also equals zero thus it is the same as saying sin(0)=0

  17. anonymous
    • 5 years ago
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    the sine curve oscillates between 1 and -1 with a period of 2 pi, so at zero sin =0, at 90* which is equal to pi/2 radians sine hits one, then comes back down to zero at 180* or pi radians, it then goes down under the x axis and touches -1 at sine(270*) or 3pi/2 radians, then back up to zero when it hits 360* or 2pi radians. so sine(0)=0 , sine(pi/2)=1, sine(pi)=0, sine(3pi/2) = -1, and sine(pi)=0

  18. anonymous
    • 5 years ago
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    however there are other values between these angles such as sin(pi/4) , pi/6, ect... so you would need to check for those values as well. the easiest way to do this is by drawing or looking at a unit circle. are you familiar with the unit circle?

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