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anonymous
 5 years ago
What is the solution to the equation (lny)^2  2ln(y^5) = 11, and how do you get the derivative of the equation with respect to y?
anonymous
 5 years ago
What is the solution to the equation (lny)^2  2ln(y^5) = 11, and how do you get the derivative of the equation with respect to y?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, why are you trying to do a derivative of the equation? this is a simple quadratic equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Like as in b(+) sqrt b^24ac over 2a?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is \[\ln a ^{b}\] ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, so I can just plug all of that into the quadratic equation to get my solution and then take the derivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, you dont need to take any derivatives at all.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just answer my question. what is \[\ln a ^{b}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay do you know about logarithms?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A little. I had calculus last semester...and I'm having to refresh everything...lol. If I took the derivative of the equation you just gave me, then I would get a^b right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't ask for the derivative of log a^b. I just asked what log a^b was.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay log a^b = b log a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0http://en.wikipedia.org/wiki/Logarithmic_identities#Algebraic_identities_or_laws

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0do you know what logarithm means though?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0don't worry, thats a side question.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Holy crap! So, really the problem should look like...\[((lny)^2)/(2lny^5)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0NO! how did you get THAT?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(lny)^2  2lny^5 = 11 or (lny)^2  10 lny 11 = 0 say ln y = x x^210x11 =0 solve for x, substitute in ln y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0need feedback to know you got it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ohhh OKay I got it, I'm sorry for the delay. I was making dinner. That makes sense. See, I started dividing because I figured if you have ln (23) then it's ln 2/ln 3. Idk. I don't know why I thought that.
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