What is the solution to the equation (lny)^2 - 2ln(y^5) = 11, and how do you get the derivative of the equation with respect to y?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
wait, why are you trying to do a derivative of the equation? this is a simple quadratic equation.
Holy crap! So, really the problem should look like...\[((lny)^2)/(2lny^5)\]
NO! how did you get THAT?
(lny)^2 - 2lny^5 = 11
or (lny)^2 - 10 lny -11 = 0
say ln y = x
solve for x, substitute in ln y
need feedback to know you got it.
Ohhh OKay I got it, I'm sorry for the delay. I was making dinner. That makes sense. See, I started dividing because I figured if you have ln (2-3) then it's ln 2/ln 3. Idk. I don't know why I thought that.