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anonymous

  • 5 years ago

subtract: y/y-2 - 8+y/2-y

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  1. anonymous
    • 5 years ago
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    This is tricky... you need to know this fact. 2 - y = -(y - 2) you can always flip numbers around a - sign and multiply by a - so 5 - x = -(x - 5)

  2. anonymous
    • 5 years ago
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    In this case you want the 2 - y to be y - 2 because you need a common denominator. so you turn the bottom in to y - 2 and then you put a - sign out in front... In this case that negative sign out front would turn your problem into a + sign y/y-2 + 8 + y/y - 2 Now you have common denominators y + 8 + y -------- y - 2 2y + 8 ------ y - 2

  3. anonymous
    • 5 years ago
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    omg hi again!!!

  4. anonymous
    • 5 years ago
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    this was our next question

  5. anonymous
    • 5 years ago
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    OK... I just found you... do you get this?

  6. anonymous
    • 5 years ago
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    i dont understand how you get the common denom....

  7. anonymous
    • 5 years ago
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    Well... y - 2 and 2 - y are opposites of each other.... you should be able to see that if you flip the one on the right around the minus sign it becomes the y - 2 ex. 2 - y flips to y - 2 OK?

  8. anonymous
    • 5 years ago
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    then you have to change the subtraction to addition??

  9. anonymous
    • 5 years ago
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    Yes... because it is the opposite you have to put a - sign out in front, and actually you change the sign of the problem... so in this case the subtraction becomes addition. This is a hard concept.

  10. anonymous
    • 5 years ago
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    hmmm then what

  11. anonymous
    • 5 years ago
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    Then you have a common denominator... so if you look above to my steps you will see that you put everything on the top over y - 2 because you now have a common denominator

  12. anonymous
    • 5 years ago
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    7/T-2 - 6/T^2-2T - 3/T is the LCD T^2-2T?

  13. anonymous
    • 5 years ago
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    7 6 3 ---- - ----------- - ------ T - 2 T^2 - 2T T T - 2 factors into (T - 2) T^2 - 2T factors into T(T - 2) T factors into T Common denominator is T(T - 2) or T^2 - 2T easier if you write it T(T - 2)

  14. anonymous
    • 5 years ago
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    T(T - 2) * 7 T(T - 2) * 6 T(T - 2) * 3 ------------ - ---------- - ---------- (T - 2) T(T - 2) T

  15. anonymous
    • 5 years ago
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    The (T - 2)'s cancel in the first fraction The T and (T - 2) cancel in the second fraction The T cancels in the third fraction

  16. anonymous
    • 5 years ago
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    7t-6-3t-2 ??

  17. anonymous
    • 5 years ago
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    7T - 6 - 3(t - 2) 7T - 6 - 3T + 6 4T

  18. anonymous
    • 5 years ago
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    isnt it -6?

  19. anonymous
    • 5 years ago
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    left with 4t-12

  20. anonymous
    • 5 years ago
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    The - sign goes with the 3 so it is actually -3(T - 2) and -3 * -2 = +6

  21. anonymous
    • 5 years ago
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    ohhh got it

  22. anonymous
    • 5 years ago
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    meeee tooooooo!

  23. anonymous
    • 5 years ago
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    YEAH!!!!!

  24. anonymous
    • 5 years ago
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    5-x/x-1 / 2-x/x+1

  25. anonymous
    • 5 years ago
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    5 - x 2 - x ---- divided by ----- x - 1 x + 1 write the divide sign that has a --- with a dot above and below. Are you sure this is what you want.

  26. anonymous
    • 5 years ago
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    noooo wait hold on

  27. anonymous
    • 5 years ago
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    X 5- ---- X-1 ___________ X 2- ---- X+1

  28. anonymous
    • 5 years ago
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    yes!

  29. anonymous
    • 5 years ago
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    OK... First we will simplify the top. 5 x - - ---- 1 x- 1 what is the common denominator?

  30. anonymous
    • 5 years ago
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    x-1?

  31. anonymous
    • 5 years ago
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    (x - 1)*5 x ------- - ----- x - 1 x - 1

  32. anonymous
    • 5 years ago
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    5x - 5 x ----- - ----- x - 1 x - 1 4x - 5 ------ x - 1 ok?

  33. anonymous
    • 5 years ago
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    5X+1-X --------- X-1

  34. anonymous
    • 5 years ago
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    GOT IT

  35. anonymous
    • 5 years ago
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    Yes... now add the x's

  36. anonymous
    • 5 years ago
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    Now let's do the same to the bottom.

  37. anonymous
    • 5 years ago
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    X+2 ----- X+1

  38. anonymous
    • 5 years ago
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    2 x - - ---- 1 x + 1 (x + 1)*2 x -------- - ---- (x + 1)*1 x + 1 (x + 1) *2 x -------- - ----- x + 1 x + 1 2x + 2 - x --------- x + 1 x + 2 ---- x + 1

  39. anonymous
    • 5 years ago
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    OOPS... go back to the first one... you have 4x - 1 look at mine... it is 4x - 5.. you have to distribute.

  40. anonymous
    • 5 years ago
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    got it

  41. anonymous
    • 5 years ago
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    4x - 5 x + 2 ------ divided by ------ x - 1 x + 1 Now.... when ever you have a fraction divided by a fraction. you ALWAYS multiply by the reciprocal

  42. anonymous
    • 5 years ago
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    4X+5 ------ X+1 -------- X+2 --- X+1

  43. anonymous
    • 5 years ago
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    4x - 5 x + 1 ------ x ----- x - 1 x + 2

  44. anonymous
    • 5 years ago
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    top right and bottom left cancel out?

  45. anonymous
    • 5 years ago
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    4X+5 ------ X+2

  46. anonymous
    • 5 years ago
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    amazing... go back and look at the numerator.. it is 4x - 5

  47. anonymous
    • 5 years ago
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    4X-5 ------ X+2 ????? I HOPE

  48. anonymous
    • 5 years ago
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    I wish they did cancel... they usually do.. but not here a (x - 1) can ONLY cancel with an (x - 1) and a (x + 1) can ONLY cancel with (x + 1) Usually you CAN cancel, but not in this problem. You would multiply the numerators (FOIL METHOD) then multiply the denominators (FOIL METHOD) and you would have your answer

  49. anonymous
    • 5 years ago
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    so now what!?!?!!? omg im lost now

  50. anonymous
    • 5 years ago
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    (4x - 5)(x + 1) ------------- (x - 1)(x + 2) 4x^2 + 4x - 5x - 5 ---------------- x^2 + 2x - x - 2 4x^2 - x - 5 ----------- x^2 + x - 2

  51. anonymous
    • 5 years ago
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    Unless you did not type in the original problem correctly? otherwise this is the answer.

  52. anonymous
    • 5 years ago
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    i got that

  53. anonymous
    • 5 years ago
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    Good.

  54. anonymous
    • 5 years ago
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    i wanna cry this is hard

  55. anonymous
    • 5 years ago
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    solve for X: (4x-7)^2 = -27 :)

  56. anonymous
    • 5 years ago
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    They are just a lot of steps.

  57. anonymous
    • 5 years ago
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    (4x - 7)^2 = -27 Are you sure this is correct?

  58. anonymous
    • 5 years ago
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    Yes

  59. anonymous
    • 5 years ago
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    yessssssssss

  60. anonymous
    • 5 years ago
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    OK.. so you know what imaginary numbers are i's

  61. anonymous
    • 5 years ago
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    yes !

  62. anonymous
    • 5 years ago
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    OK.. what if I gave you this problem... do you know what to do. x^2 = 16

  63. anonymous
    • 5 years ago
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    yes square root both sides

  64. anonymous
    • 5 years ago
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    Good... so in this problem you have (something)^2 = -27 so you square root both sides

  65. anonymous
    • 5 years ago
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    x=4

  66. anonymous
    • 5 years ago
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    (4x - 7)^2 = -27 4x - 7 = sqrt(-27)

  67. anonymous
    • 5 years ago
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    sqrt(-27) is -3i sqrt(3) do you understand this?

  68. anonymous
    • 5 years ago
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    \[3i \sqrt{3?}\]

  69. anonymous
    • 5 years ago
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    yess!

  70. anonymous
    • 5 years ago
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    OOPS you are correct is is positive

  71. anonymous
    • 5 years ago
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    4x - 7 = 3i sqrt(3) 4x = 3i sqrt(3) + 7 x = 3i sqrt(3) + 7 ------------ 4

  72. anonymous
    • 5 years ago
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    \[9+3x-2x ^{2} \over x ^{2}-16 \]

  73. anonymous
    • 5 years ago
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    wait im not done hold on!

  74. anonymous
    • 5 years ago
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    all that divided by \[4x ^{3}-9x \over 2x ^{2}+5x-12\]

  75. anonymous
    • 5 years ago
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    simplify and state restricitons

  76. anonymous
    • 5 years ago
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    -2x^2 + 3x + 9 2x^2 + 5x - 12 --------------- x ------------- x^2 - 16 4x^3 - 9x since it is a fraction divide by a fraction.. we are going to turn it into a multiply problem right away by using the reciprocal. OK?

  77. anonymous
    • 5 years ago
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    ok hold on lemme take all that in

  78. anonymous
    • 5 years ago
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    then factor?

  79. anonymous
    • 5 years ago
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    yes we have to factor all four... but it is difficult to factor when there is a negative in front of the x^2 so for the first fraction in the numerator we are going to factor out a - sign first. - (2x^2 - 3x - 9)

  80. anonymous
    • 5 years ago
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    -(2x + 3)(x - 3) (2x - 3)(x + 4) -------------- x ------------- (x + 4)(x - 4) x(4x^2 - 9) x(2x + 3)(2x - 3)

  81. anonymous
    • 5 years ago
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    -(2x+3)(x-3) (x+4) (2x-3) ---------- ------------ (x+4) (x-4) x(2x+3) (2x-3)

  82. anonymous
    • 5 years ago
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    now we can cancel out right?

  83. anonymous
    • 5 years ago
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    Yes... now cancel anything in ( )'s with like ( )'s Anything on the top with anything on the bottom that matches.

  84. anonymous
    • 5 years ago
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    x-3 ----- x(x-4)

  85. anonymous
    • 5 years ago
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    close you still have that - sign on top -(x - 3) ------- x(x - 4) they may want it like -x + 3 ------ x^2 - 4x it is all the same...

  86. anonymous
    • 5 years ago
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    Now you also said you had to tell restrictions.

  87. anonymous
    • 5 years ago
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    yesss

  88. anonymous
    • 5 years ago
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    OK... go back to the factored fractions. The rule is you can NEVER divide by 0 so whatever makes those ( )'s 0 would be a restriction.

  89. anonymous
    • 5 years ago
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    We are only concerned with the denominators.

  90. anonymous
    • 5 years ago
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    okkk

  91. anonymous
    • 5 years ago
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    (x + 4)(x - 4) x(2x + 3)(2x - 3)

  92. anonymous
    • 5 years ago
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    -4,4 -3/2, 3/2

  93. anonymous
    • 5 years ago
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    And one more you need 0 because of the single x Every where there is an x there is a restriction.

  94. anonymous
    • 5 years ago
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    blexting you are great!!! we have 3 more can we keep going?

  95. anonymous
    • 5 years ago
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    Sure

  96. anonymous
    • 5 years ago
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    way better then our professor!

  97. anonymous
    • 5 years ago
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    X^2-9 ---------------- X^3+X^2-9X-9 SIMPLIFY

  98. anonymous
    • 5 years ago
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    Factor

  99. anonymous
    • 5 years ago
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    (x + 3)(x - 3) ------------

  100. anonymous
    • 5 years ago
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    When you have 4 terms you should try this first. Take the first two terms and take out a common factor. x^3 + x^2 = x^2(x + 1) Take the last two terms and do the same thing. -9x - 9 = -9(x + 1) OK?

  101. anonymous
    • 5 years ago
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    x+1 is the answer right?

  102. anonymous
    • 5 years ago
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    (X^2-9) (X+1)

  103. anonymous
    • 5 years ago
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    I MEAN (X-1)

  104. anonymous
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    OK.. Now you have x^2(x + 1) - 9(x + 1) ... good amozing. because (x + 1) is a common factor you now have (x + 1)(x^2 - 9) BUT this is the difference of two squares. (x + 1)(x + 3)(x - 3)

  105. anonymous
    • 5 years ago
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    they dont cancel out

  106. anonymous
    • 5 years ago
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    ?

  107. anonymous
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    So you have the top which is (x + 3)(x - 3) ------------ (x + 1)(x + 3)(x - 3) then cancel and you are left with 1 ------- x + 1 with restrictions of x cannot be -1,-3 or 3

  108. anonymous
    • 5 years ago
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    solve for X: 3 17 7 ------- = ---- - ----- 4x+2 2 2x+1

  109. anonymous
    • 5 years ago
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    Common denominator 4x + 2 = 2(2x + 1) 2 = 2 2x + 1 = 2x + 1 common denominator 2(2x + 1)

  110. anonymous
    • 5 years ago
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    Put that on top of each fraction and then cancel with the denominators.

  111. anonymous
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    2(2x + 1) * 3 2(2x + 1) * 17 2(2x + 1) * 7 ----------- = ------------- - ----------- 2(2x + 1) 2 2x + 1

  112. anonymous
    • 5 years ago
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    34X+3=3 ??

  113. anonymous
    • 5 years ago
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    X=1/34

  114. anonymous
    • 5 years ago
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    3 = 17(2x + 1) - 14 3 = 34x + 17 - 14 3 = 34x + 3 0 = 34x 0 = x

  115. anonymous
    • 5 years ago
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    amozing when you take 34x + 3 = 3 and you subtract 3 you get 34x = 0

  116. anonymous
    • 5 years ago
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    Restrictions x cannot be -1/2

  117. anonymous
    • 5 years ago
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    GOT IT, THANKS!! ONE MORE :)

  118. anonymous
    • 5 years ago
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    OK

  119. anonymous
    • 5 years ago
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    X^2+XY-2Y^2 X ----------- X ----------------- X^3+X^2Y X^2+3XY+2Y^2

  120. anonymous
    • 5 years ago
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    3X^3Y^2

  121. anonymous
    • 5 years ago
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    NOT 3Y JUST Y SORRY

  122. anonymous
    • 5 years ago
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    (x + 2y)(x - y) x ------------ times -------------- x^2(x + y) (x + 2y)(x + y)

  123. anonymous
    • 5 years ago
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    (x - y) ------------ x(x + y)^2

  124. anonymous
    • 5 years ago
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    GOT IT THANKS!!

  125. anonymous
    • 5 years ago
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    gixxergirl..... did you leave us?

  126. anonymous
    • 5 years ago
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    Are we done????

  127. anonymous
    • 5 years ago
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    lol sorry i had to pee!!! but thank you so mucchhhhh for everythinggg !!! are you a math teacher?

  128. anonymous
    • 5 years ago
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    yes I am in a high school

  129. anonymous
    • 5 years ago
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    YOU HAVE BEEN SO HELPFUL!! THANK YOU SO MUCH

  130. anonymous
    • 5 years ago
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    No problem.. if you see me on here again and want help.. just holler. Have a wonderful Easter... He is risen!!! Good night.

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