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omg hi again!!!

this was our next question

OK... I just found you...
do you get this?

i dont understand how you get the common denom....

then you have to change the subtraction to addition??

hmmm then what

7/T-2 - 6/T^2-2T - 3/T is the LCD T^2-2T?

T(T - 2) * 7 T(T - 2) * 6 T(T - 2) * 3
------------ - ---------- - ----------
(T - 2) T(T - 2) T

7t-6-3t-2 ??

7T - 6 - 3(t - 2)
7T - 6 - 3T + 6
4T

isnt it -6?

left with 4t-12

The - sign goes with the 3 so it is actually
-3(T - 2)
and -3 * -2 = +6

ohhh got it

meeee tooooooo!

YEAH!!!!!

5-x/x-1 / 2-x/x+1

noooo wait hold on

X
5- ----
X-1
___________
X
2- ----
X+1

yes!

OK... First we will simplify the top.
5 x
- - ----
1 x- 1
what is the common denominator?

x-1?

(x - 1)*5 x
------- - -----
x - 1 x - 1

5x - 5 x
----- - -----
x - 1 x - 1
4x - 5
------
x - 1
ok?

5X+1-X
---------
X-1

GOT IT

Yes... now add the x's

Now let's do the same to the bottom.

X+2
-----
X+1

got it

4X+5
------
X+1
--------
X+2
---
X+1

4x - 5 x + 1
------ x -----
x - 1 x + 2

top right and bottom left cancel out?

4X+5
------
X+2

amazing... go back and look at the numerator.. it is 4x - 5

4X-5
------
X+2
????? I HOPE

so now what!?!?!!? omg im lost now

Unless you did not type in the original problem correctly? otherwise this is the answer.

i got that

Good.

i wanna cry this is hard

solve for X: (4x-7)^2 = -27 :)

They are just a lot of steps.

(4x - 7)^2 = -27
Are you sure this is correct?

Yes

yessssssssss

OK.. so you know what imaginary numbers are i's

yes !

OK.. what if I gave you this problem... do you know what to do.
x^2 = 16

yes square root both sides

Good... so in this problem you have
(something)^2 = -27
so you square root both sides

x=4

(4x - 7)^2 = -27
4x - 7 = sqrt(-27)

sqrt(-27) is -3i sqrt(3)
do you understand this?

\[3i \sqrt{3?}\]

yess!

OOPS you are correct is is positive

4x - 7 = 3i sqrt(3)
4x = 3i sqrt(3) + 7
x = 3i sqrt(3) + 7
------------
4

\[9+3x-2x ^{2} \over x ^{2}-16 \]

wait im not done hold on!

all that divided by \[4x ^{3}-9x \over 2x ^{2}+5x-12\]

simplify and state restricitons

ok hold on lemme take all that in

then factor?

-(2x+3)(x-3) (x+4) (2x-3)
---------- ------------
(x+4) (x-4) x(2x+3) (2x-3)

now we can cancel out right?

x-3
-----
x(x-4)

Now you also said you had to tell restrictions.

yesss

We are only concerned with the denominators.

okkk

(x + 4)(x - 4) x(2x + 3)(2x - 3)

-4,4 -3/2, 3/2

And one more you need 0 because of the single x
Every where there is an x there is a restriction.

blexting you are great!!! we have 3 more can we keep going?

Sure

way better then our professor!

X^2-9
----------------
X^3+X^2-9X-9
SIMPLIFY

Factor

(x + 3)(x - 3)
------------

x+1 is the answer right?

(X^2-9) (X+1)

I MEAN (X-1)

they dont cancel out

solve for X: 3 17 7
------- = ---- - -----
4x+2 2 2x+1

Common denominator
4x + 2 = 2(2x + 1)
2 = 2
2x + 1 = 2x + 1
common denominator 2(2x + 1)

Put that on top of each fraction and then cancel with the denominators.

34X+3=3
??

X=1/34

3 = 17(2x + 1) - 14
3 = 34x + 17 - 14
3 = 34x + 3
0 = 34x
0 = x

amozing when you take 34x + 3 = 3 and you subtract 3 you get 34x = 0

Restrictions x cannot be -1/2

GOT IT, THANKS!!
ONE MORE :)

OK

X^2+XY-2Y^2 X
----------- X -----------------
X^3+X^2Y X^2+3XY+2Y^2

3X^3Y^2

NOT 3Y JUST Y SORRY

(x + 2y)(x - y) x
------------ times --------------
x^2(x + y) (x + 2y)(x + y)

(x - y)
------------
x(x + y)^2

GOT IT THANKS!!

gixxergirl..... did you leave us?

Are we done????

lol sorry i had to pee!!! but thank you so mucchhhhh for everythinggg !!! are you a math teacher?

yes I am in a high school

YOU HAVE BEEN SO HELPFUL!! THANK YOU SO MUCH