anonymous
  • anonymous
Find the integral:
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\sqrt{x} + 1/ x^4 dx\]
anonymous
  • anonymous
what is the integral of sqrt x
anonymous
  • anonymous
that also is \[(x)^{1/2} + (x)^{-4}\]

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anonymous
  • anonymous
You can rewrite that integral as the integral of (x^(1/2) + x^(-4)) Using the power rule, we get: (x^(3/2) / (3/2)) + (x^(-3) / -3) which may be rewritten as (2/3) x^(3/2) - 3/x^3
anonymous
  • anonymous
just integrate each part individually then add together
anonymous
  • anonymous
add 1 to the exponents and w/e you get multiply each part by it's inverse
anonymous
  • anonymous
you can't add them. If he could then he would do it before the integration
anonymous
  • anonymous
integral of sqrt x = [2x^(3/2)]/3 integral of 1/x^4= -1/3x^3 Then add together and you get (2 x^(9/2)-1)/(3 x^3)+ C

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