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anonymous
 5 years ago
Minimum Wage The table shows the minimum wage for
three different years. Year/wages: 1940/0.25, 1968/1.60, 1997/5.15
(a) Make a scatterplot of the data in the viewing rectangle
[1930, 2010, 10] by [0, 6, 1].
(b) Find a quadratic function given by
that models the data.
f(x)=a(x  h)^2 + k
(c) Estimate the minimum wage in 1976 and compare
it to the actual value of $2.30.
(d) Estimate when the minimum wage was $1.00.
(e) If current trends continue, predict the minimum
wage in 2009. Compare it to the projected value of
$7.25.
anonymous
 5 years ago
Minimum Wage The table shows the minimum wage for three different years. Year/wages: 1940/0.25, 1968/1.60, 1997/5.15 (a) Make a scatterplot of the data in the viewing rectangle [1930, 2010, 10] by [0, 6, 1]. (b) Find a quadratic function given by that models the data. f(x)=a(x  h)^2 + k (c) Estimate the minimum wage in 1976 and compare it to the actual value of $2.30. (d) Estimate when the minimum wage was $1.00. (e) If current trends continue, predict the minimum wage in 2009. Compare it to the projected value of $7.25.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The question is too long. I feel too lazy to read it :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0ive never made a scatter plot tha tI know of...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0just three plots aint much of a scatter, but I can make a quad out of it if you want :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.00.001301745743669519x^2 5.0390080805461945x + 4876.675395385017 maybe

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going nuts on this. I need to learn how to do this not just answers. Thanks for everyone's help. If anyone else knows how to solve these. Please let me know. Thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going nuts on this. I need to learn how to do this not just answers. Thanks for everyone's help. If anyone else knows how to solve these. Please let me know. Thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going nuts on this. I need to learn how to do this not just answers. Thanks for everyone's help. If anyone else knows how to solve these. Please let me know. Thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going nuts on this. I need to learn how to do this not just answers. Thanks for everyone's help. If anyone else knows how to solve these. Please let me know. Thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going nuts on this. I need to learn how to do this not just answers. Thanks for everyone's help. If anyone else knows how to solve these. Please let me know. Thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going nuts on this. I need to learn how to do this not just answers. Thanks for everyone's help. If anyone else knows how to solve these. Please let me know. Thank you.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol...you still there?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(1940/0.25), (1968/1.60), (1997/5.15 ) the numbers are huge, but the process is the same: a(1940)^2 + b(1940) +c = .25 a(1968)^2 + b(1968) +c = 1.6 a(1997)^2 + b(1997) +c = 5.15 we can reduce the numbers and still get the same effect by subtracting 1940 from everything...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0these numbers are more managable; just dont forget to "+40" to the year when your done. a(0)^2 + b(0) +c = .25 < from this we see that c = .25 thats a given; write it down :) a(28)^2 + b(28) +c = 1.6 a(57)^2 + b(57) +c = 5.15

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Eq simply means "Equation": a(28)^2 + b(28) +.25 = 1.6 a(28)^2 + b(28) = 1.6  .25 = 1.35 <Eq2 .............................................. a(57)^2 + b(57) +.25 = 5.15 a(57)^2 + b(57) = 5.15  .25 = 4.90 <Eq3 ....................................... a(28)^2 + b(28) = 1.35 <Eq2 ; solve for b, just a random pick nothing special about it 1.35  a(28)^2 b =  < use this "value" of b in the other Eq. 28 .................................................

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Eq3: a(57)^2 + b(57) = 4.90 (1.35  a(28)^2) (57) a(57)^2 +  = 4.90 ; solve for "a" :) 28

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a(57)^2(28) + (1.35  a(28)^2) (57) = 4.90(28) a(57)^2(28) + 1.35(57)  a(28)^2(57) = 4.90(28) a(57)^2(28)  a(28)^2(57) = 4.90(28)  1.35(57) a [(57)^2(28) (28)^2(57)] = 4.90(28)  1.35(57) 4.90(28)  1.35(57) 60.25 a =  =  ; reduce as wanted :) (57)^2(28) (28)^2(57) 46284 ............................................. a = 60.25/46284 ;c = .25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now lets see what "b" equals with this monstrocity: recall that "b" =: 1.35  a(28)^2 b =  28 1.35  (60.25/46284)(28)^2 b =  28 1.35(46284)  (60.25)(28)^2 b =  ; reduce as wanted :) 48284(28)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now you plug those values into the equation: y = a(x40)^2 + b(x40) + c : and you get your quadratic equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Amistre64, You are awesome. I'm a little confused but I will look it over better in the morning in hope that I can follow. Once again thank you so much.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Youre welcome :) I just hope its useful lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that doesnt wanna open on this computer....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0your probably gonna have to chisel it on a stela and throw it at me :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I'm just a lost cause. I'm lost. Its crazy. Sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So I plug in y=60.25(x40)^2+28(x40)+.25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then if I want to know the wages for 1976 Do I plug that in for x or am I crazy lost.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0did you get 60.25 and 28 from those monster fractions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok when I did that I got y=225876992.25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I just plugged a=60.25, b = 28, and c = .25 Into y=a(x40)^2+b(x40)+c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm sorry I don't know why I'm having so much trouble with this. I'm just not understanding it.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when I use my "quad" finder I programed I get the:

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I programmed that thing myself just for cases like these lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.00.001301745743669519x^2 + 5.0390080805461945x + 4876.675395385017 the quadratic equation is this monster of a mess...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wow...I don't know. errrr lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when given 3 sets of data; you can find a quad to match it by doing all that stuff I did up there; so instead, I just told the computer to do it all and give me an answer ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know how to explain my answer in a, b,c, d and e in these problems. I have to show how I got the answers.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then you show them what I typed out ;) cause thats the most basic way to derive it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(a) Make a scatterplot of the data in the viewing rectangle [1930, 2010, 10] by [0, 6, 1]. (b) Find a quadratic function given by f(x) = a(x – h)^2 + k that models the data. (c) Estimate when the minimum wage in 1976 and compare it to the actual value of $2.30. (d) Estimate when the minimum wage was $1.00. (e) If current trends continue, predict the minimum wage in 2009. Compare it to the projected value of $7.25.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0This is the formula I worked out up there :) 0.0013017457436695185(x40)^2 + 0.011765404891539196(x40) + 0.25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0where you got 60.25 and 28 from .... I dunno. Unless I got typoed; which is a possibility

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I so need a tutor like you in person

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0From 1976 as an input we get: 2.36 which is pretty close to 2.30.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) if your near tampa....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0id have to do a little more programming to determine the "$1.00" part. just have to tell it to get it from the other input box and give me an answer for it...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i wrote an algorithym a while back to zone in on a particular value by seeing when it gets over to back up and add halves....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You are too smart. LOL. I haven't had a math class in over 12 years. This is what I get for having kids and getting married then a divorce makes me want to finishing school

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, it was 20 years for me.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tried back in 92 but kids and bills got more important

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0now that im "unemployable" I am going back to get some degrees to teach in colleges

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0awesome that im unemployable ? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No that you are going back to school now

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah. Im surrounded by students that are not much older than my kids...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre, need your help

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hey...who cares...I think it is great that you are back...trying...Thats amazing

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0thanx :) BTM, itll be about 30 mins prolly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok Thank you for everything

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0just finishing up some last minute programming and it should be set....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol..... still got a bug that needs squashed; sqrt(64) is NOT zero lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if (q=g){...} is meaningless, if(q==g){.......} is proper. I forgot to put 2 "=" lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im just gonna plug in dates till I get near 1 ;) just gonna be easier

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I get 1959 = .9434 cents 1960 = 1.006 :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02009 prediction is: $7.259 as compared to $7.25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0and thats all the answers :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok quick question. I know (from what you gave me) that a=60.25/46284, c =.25, and what you gave me for b, is not working out for me. What would b be again. and can a be broke down smaller. so in my problem: y=a(x40)^2+b(x40)+c I plug in y=60.25/46284(x40)^2+b(x40)+.25 So for x I can replace it with 1976, right? and b I can replace it with (?)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are plugging the dates into? Please show me?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b is a constant that the equation requires in order to function correctly. b :=approximately: 0.011765404891539196 round that to .01 if need be

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a :=approx" 0.0013017457436695186241465733298764; rounded to .001 if need be

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0plugging the "dates" into is: x = date. we use the date as the input variable for the value of "X".

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a, b and c are constants that do not change in this equation. They allow us to pinpoint with a great deal of accuracy the proper amounts that the inputs require.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0output = .001 x^2 +.01 x +.25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that looks more manageable ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0opps...(x40)^2 and (x40) is what it should read

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0output = .001(x40)^2 +.01(x40) +.25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0for 1975 we get: .001(35)^2 +.01(35) + .25 = 1.825 with this simplified version of it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When I try this and put 1976 in for x I get y=3767.706

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but they ask for 1976 lol..... i have a memory like a steel seive :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0197640=36 right? so: .001(36^2) + .01(36) + .25 = 1.906 is what I get for 1976

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0to get it more accurate, you will have to include more decimal points from the original setup

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0This setup right here gives you the most accurate: .0013017457436695185 (x40)^2 + .011765404891539196 (x40) + .25

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0are you making sure you subtract 40 from the year?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That was my problem. Thank You. I get it now. You are amazing. Thank you Thank you Thank you!!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Google gives me this ;) (.0013017457436695185 * (36^2)) + (.011765404891539196 * 36) + .25 = 2.36061706

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0you can copy and past an equation into a google search bar and it calculates it for you. its pretty nifty lol I said nifty

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't know that. Cool. Thanks again. Yay!!!

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yay!! we got new stuff to play with in here...
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