I REALLY NEED SOMEONE TO HELP ME WITH AT LEAST ONE OF THESE PROBLEMS.. PLEASE The solid is similar to a larger solid with the given scale factor, find the surface area and volume of the larger solid. 1) Cylinder: scale factor 1:2, SA=208pi in^2, V=320pi in^3
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
The first thing that needs to be done is find the radius and height of the original cylinder. Using \[SA = 2\pi r h = 208 \pi\] and \[V = \pi r^2 h = 320 \pi\] we get:
\[(1)r h = 104\] \[(2)r^2 h = 320\] Solving for h in equation (1), we get \[h = 104/r\] so substituting this into equation (2), we get \[r = 320/104\] and by using the formula we got for h, we find \[h = 104^2/320\]
Since the scale is 1:2, I'm asuming that this means the radius and height are doubled. Hence our new r and h are \[r = 320/52 = 80/13\] \[h=104^2/160=10816/160=338/5\]
Now by the surface area formula, \[SA = 2* \pi *80/13*338/5 = 832 \pi \]
By the Volume formula, \[V = \pi * r^2 * h = \pi * (80/13)^2 * 338/5 = 2560 \pi \] I think that's it.
thank you.. can you look at my other two please i have been doing these for a week and cant figure them out