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anonymous
 5 years ago
square root of 2z+9square root of z+6=o
anonymous
 5 years ago
square root of 2z+9square root of z+6=o

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2z+9 }\sqrt{z+6}=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2z+9}=\sqrt{z+6}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\implies \sqrt{2z+9}=\sqrt{z+6} \implies 2z+9=z+6 \implies z=3\] Plug in the equation and check!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just substitute in the original equation with z=3 to check it's the right solution!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's right by the way!! So your answer is z=3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well. The first thing you should here is to get rid of the square root. To do so, you should square both sides. Can you do that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok. Do it and show me what you get.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt({x8})^{2}=(x4)^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you sure about the right hand side?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0all (x4) is raised to the power of 2. Not only the 4.. So it's like (x4) times (x4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok.. follow my steps carefully!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First start by squaring both sides: \[(\sqrt{x+8})^2=(x4)^2\] you did the left hand side, it's the same as x+8.. the right hand side is: \[(x4)^2=x^28x+16\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, the equation will look like: \[x+8=x^28x+16 \implies x^29x+8=0\] Do you know how to solve a quadratic equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just factorize the expression x^29x+8 to get: \[x^29x+8=0 \implies (x8)(x1)=0 \implies x=1, x=8\] We have two values for x. Check for each one!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You will find that only x=8 is a solution of the equation.
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