At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
try visiting this url it might be able to explain this concept better than i can: http://math.etsu.edu/multicalc/archives/Chap3/Chap3-6/index.htm
did that help?
First you need to find the unit vector. You know how to find it?
yeah, I think I figured it out. Grad F(x,y,x)
so would it be. \[6(x-3) -6(y - 2) +(z-1) =0\] ?
You are right that's the equation for a plane passing through that point
Sames right 6x-6y+z=9
actually that doesnt look right
The 9 should be 7
i got the same thing as lockdown but maybe i am wrong, i do know that you should most likely condense your answer
yeah, I condensed it. I got 12x - 12y + 2z - 14 = 0 originally, but divided by 2
meaning combine constants on the other side of the equation
Here is a neat trick, Lockdown, rather than writing out the equation formula. Once you get your vector <6, -6, 1> Write it as an eq 6x-6y+1= The other side can be determined in your head by the points (6*3=18) -12 + 1=7
you know that trick is actually helpful to me too, thanks chaguanas
Yeah, the equation is taught in schools, mathematicians don't do it the eq way
yeah, thats a good way of thinking about it, since they always want simplified anyways.