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anonymous

  • 5 years ago

can somebody help me solving this problems? http://tinyurl.com/3wne3vx

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  1. anonymous
    • 5 years ago
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    this is a vector problem

  2. anonymous
    • 5 years ago
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    It's late where I am so I'm gonna hit some easy ones here. (b(i)): p dot q = ||p|| ||q|| cos(theta), where theta is the angle between the vectors. so just multiply all that you're given, and you'll get \[ 2 \pi \] Hope I helped with something

  3. anonymous
    • 5 years ago
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    can you help me with a(iii) and b

  4. anonymous
    • 5 years ago
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    I already gave you a hint. can you not see the answer to a (iii)?

  5. anonymous
    • 5 years ago
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    no

  6. anonymous
    • 5 years ago
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    DEC and similar to AEF

  7. anonymous
    • 5 years ago
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    and AF and DC are corresponding parts, but DC = AB

  8. anonymous
    • 5 years ago
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    AF=kDC => AF/DC = k

  9. anonymous
    • 5 years ago
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    and EF/DF = 1/lambda, so by the property of similar triangles...

  10. anonymous
    • 5 years ago
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    i get it now, how about part b?

  11. anonymous
    • 5 years ago
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    i dont understand part b

  12. anonymous
    • 5 years ago
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    i need help to find k

  13. anonymous
    • 5 years ago
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    kAB = AF and AF = proj FD on FA so proj FD is FD (dot) FA / |FA|^2 * FA

  14. anonymous
    • 5 years ago
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    i dont understand it

  15. anonymous
    • 5 years ago
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    is there another way to solve for k?

  16. anonymous
    • 5 years ago
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    yeah sorry ignore that. I miss read the diagram

  17. anonymous
    • 5 years ago
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    i found that DF = kp-q

  18. anonymous
    • 5 years ago
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    rinspd how you up load the picture?

  19. anonymous
    • 5 years ago
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    i used flick to upload the picture

  20. anonymous
    • 5 years ago
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    do you have to paid monthly?

  21. anonymous
    • 5 years ago
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    no its free

  22. anonymous
    • 5 years ago
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    do you have a link my mail it yahoo

  23. anonymous
    • 5 years ago
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    yeah

  24. anonymous
    • 5 years ago
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    I have a problem to upload picture

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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