## anonymous 5 years ago can somebody help me solving this problems? http://tinyurl.com/3wne3vx

1. anonymous

this is a vector problem

2. anonymous

It's late where I am so I'm gonna hit some easy ones here. (b(i)): p dot q = ||p|| ||q|| cos(theta), where theta is the angle between the vectors. so just multiply all that you're given, and you'll get $2 \pi$ Hope I helped with something

3. anonymous

can you help me with a(iii) and b

4. anonymous

I already gave you a hint. can you not see the answer to a (iii)?

5. anonymous

no

6. anonymous

DEC and similar to AEF

7. anonymous

and AF and DC are corresponding parts, but DC = AB

8. anonymous

AF=kDC => AF/DC = k

9. anonymous

and EF/DF = 1/lambda, so by the property of similar triangles...

10. anonymous

i get it now, how about part b?

11. anonymous

i dont understand part b

12. anonymous

i need help to find k

13. anonymous

kAB = AF and AF = proj FD on FA so proj FD is FD (dot) FA / |FA|^2 * FA

14. anonymous

i dont understand it

15. anonymous

is there another way to solve for k?

16. anonymous

yeah sorry ignore that. I miss read the diagram

17. anonymous

i found that DF = kp-q

18. anonymous

rinspd how you up load the picture?

19. anonymous

i used flick to upload the picture

20. anonymous

do you have to paid monthly?

21. anonymous

no its free

22. anonymous

do you have a link my mail it yahoo

23. anonymous

yeah

24. anonymous

I have a problem to upload picture