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*_Artist_*Best ResponseYou've already chosen the best response.0
I was wondering how he got that...
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
A= 1/2 h \[ ( b _{1} + b _{2} )\] if A = 16, h = 4, and b1 = 3
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
so basically 16 = 1/2*4 (3+\[ b _{2}\])
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
Do you know about equivalent transformation of equations?
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
Uh...I'm not sure....could you please explain for me?
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
If you have a function which is injective (i.e. onetoone) you can apply it to both sides of an equation and get an equivalent expression. i.e. the new expression is true for exactly the same allocation of the variables with values as the initial one. So for example you can multiply with a constant (nonzero) factor on both sides, because you can invert that operation by dividing through that factor.
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
How would I use it on my problem?
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
You cant to seperate b2, but you have it enclosed in operations, so you must apply the inverses of those functions and as explained before, to get the correct b2 you have to do that on both sides.
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
what would be the inverse for \[b _{2}\]?
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
You have \[16 = 2(3 + b_2)\] given. So for a start the outermost operation on the right hand side is multiplication by 2. So first you would have to divide by 2 on both sides.
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
Okay. On the first side we have 8 right?
 2 years ago

knowakBest ResponseYou've already chosen the best response.0
Square root is the inverse of the power of two.
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
There is no power of two anywhere here^^ yes, 8 is correct.
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
Okay. How do I divide the second half by 2?
 2 years ago

knowakBest ResponseYou've already chosen the best response.0
Ah, I wrongly assumed \[b_2\] was a typo of \[b^{2}\] Sorry. :)
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
First multiplying something (3+b2 e.g.) by 2 and then dividing by two again, what will you get?
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
the first answer....?
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
I'm not sure what you are referring to...
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
i'm confused now too
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
"First multiplying something (3+b2 e.g.) by 2 and then dividing by two again, what will you get?"
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
You just have to think about that something as a number.
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
so, now what am i supposed to do? I'm confused.
 2 years ago

nowheremanBest ResponseYou've already chosen the best response.0
Try to answer that last question, if you don't know it, try it out with several numbers.
 2 years ago

*_Artist_*Best ResponseYou've already chosen the best response.0
i gotta go.... be back later
 2 years ago
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