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64

s^3 = s * s * s

Thank you guys.

I was wondering how he got that...

A= 1/2 h \[ ( b _{1} + b _{2} )\] if A = 16, h = 4, and b1 = 3

so basically 16 = 1/2*4 (3+\[ b _{2}\])

I need to find b2

Do you know about equivalent transformation of equations?

Uh...I'm not sure....could you please explain for me?

okay..

How would I use it on my problem?

what would be the inverse for \[b _{2}\]?

Okay. On the first side we have 8 right?

Square root is the inverse of the power of two.

There is no power of two anywhere here^^
yes, 8 is correct.

Okay. How do I divide the second half by 2?

Ah, I wrongly assumed \[b_2\] was a typo of \[b^{2}\] Sorry. :)

s'okay! ^^

First multiplying something (3+b2 e.g.) by 2 and then dividing by two again, what will you get?

the first answer....?

I'm not sure what you are referring to...

i'm confused now too

"First multiplying something (3+b2 e.g.) by 2 and then dividing by two again, what will you get?"

You just have to think about that something as a number.

okay...

so, now what am i supposed to do? I'm confused.

Try to answer that last question, if you don't know it, try it out with several numbers.

which one?

i gotta go....
be back later