anonymous
  • anonymous
Solve for V in V = s^3 , if s = 4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
64
anonymous
  • anonymous
s^3 = s * s * s
anonymous
  • anonymous
Thank you guys.

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anonymous
  • anonymous
I was wondering how he got that...
anonymous
  • anonymous
A= 1/2 h \[ ( b _{1} + b _{2} )\] if A = 16, h = 4, and b1 = 3
anonymous
  • anonymous
so basically 16 = 1/2*4 (3+\[ b _{2}\])
anonymous
  • anonymous
I need to find b2
nowhereman
  • nowhereman
Do you know about equivalent transformation of equations?
anonymous
  • anonymous
Uh...I'm not sure....could you please explain for me?
nowhereman
  • nowhereman
If you have a function which is injective (i.e. one-to-one) you can apply it to both sides of an equation and get an equivalent expression. i.e. the new expression is true for exactly the same allocation of the variables with values as the initial one. So for example you can multiply with a constant (non-zero) factor on both sides, because you can invert that operation by dividing through that factor.
anonymous
  • anonymous
okay..
anonymous
  • anonymous
How would I use it on my problem?
nowhereman
  • nowhereman
You cant to seperate b2, but you have it enclosed in operations, so you must apply the inverses of those functions and as explained before, to get the correct b2 you have to do that on both sides.
anonymous
  • anonymous
what would be the inverse for \[b _{2}\]?
nowhereman
  • nowhereman
You have \[16 = 2(3 + b_2)\] given. So for a start the outermost operation on the right hand side is multiplication by 2. So first you would have to divide by 2 on both sides.
anonymous
  • anonymous
Okay. On the first side we have 8 right?
anonymous
  • anonymous
Square root is the inverse of the power of two.
nowhereman
  • nowhereman
There is no power of two anywhere here^^ yes, 8 is correct.
anonymous
  • anonymous
Okay. How do I divide the second half by 2?
anonymous
  • anonymous
Ah, I wrongly assumed \[b_2\] was a typo of \[b^{2}\] Sorry. :)
anonymous
  • anonymous
s'okay! ^^
nowhereman
  • nowhereman
First multiplying something (3+b2 e.g.) by 2 and then dividing by two again, what will you get?
anonymous
  • anonymous
the first answer....?
nowhereman
  • nowhereman
I'm not sure what you are referring to...
anonymous
  • anonymous
i'm confused now too
anonymous
  • anonymous
"First multiplying something (3+b2 e.g.) by 2 and then dividing by two again, what will you get?"
nowhereman
  • nowhereman
You just have to think about that something as a number.
anonymous
  • anonymous
okay...
anonymous
  • anonymous
so, now what am i supposed to do? I'm confused.
nowhereman
  • nowhereman
Try to answer that last question, if you don't know it, try it out with several numbers.
anonymous
  • anonymous
which one?
anonymous
  • anonymous
i gotta go.... be back later

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