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anonymous
 5 years ago
Evaluate:
antiderivative x dx/sqrt(x^2+1)
anonymous
 5 years ago
Evaluate: antiderivative x dx/sqrt(x^2+1)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I get u= x^2+1 du = 1 dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put x^2 +1 =t diff w.r.t. x , we get 2x dx= dt

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0u could even substitute sqrt(x^2+1)=t than can work too

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0tan(t) = x ; dt sec^2 = dx; t = tan^1(x)..lets start :) x dx tan(t) sec^2(t) dt  >  (x^2 +1) tan^2 +1 < this is eqaul to sec^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, it helps if you read the sqrt part ;).....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0...if you ever need to do the one I was working on....lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when I re did it with the approriate sqrt.... I got\[\int\limits_{}\frac{\tan(t)\sec^2(t)}{\sec(t)}dt \rightarrow \int\limits_{} \sec(t)\tan(t)dt \rightarrow \sec(t)\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sec(t) = \sqrt{x^2+1}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I started a new problem

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yay!! .... I was just trying to wrap this one up in me brain :)
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