can anyone help Mee .

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can anyone help Mee .

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Which of the following numbers is closest to the mean of this distribution ?
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If you have a distribution like that, it's usually safe to say that the middle number will be the mean. The reason is because there are decreasing amounts of the numbers on either side, making them count `less' towards the mean, while there are more of the center number, so it counts `more'. Thus, it's a reasonable guess. Another way to do it is to actually do the math, adding up the number of squares for 1 (there is 1 square for 1), squares for 2 (2 squares of 2), etc. So you end up with 1 + 2 + 2 + 3 + 3 + 3 + ... Then you can divide that by the total number of squares.

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