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## anonymous 5 years ago Icebergs consist of freshwater ice and float in the ocean with only about 10.0 of their volume above water (the "tip of the iceberg," so to speak). This percentage can vary, depending on the condition of the ice. Assume that the ice has the density given in Table 13.1, although, in reality, this can vary considerably, depending on the condition of the ice and the amount of impurities in it. What does this 10.0 tell us is the density of seawater? What percentage of the icebergs' volume would be above water if they were floating in a large freshwater lake such as Lake Superior?

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1. anonymous

The iceberg is in equilibrium which means that the mass displaced by the iceberg is equal to the mass above the water. So Density of iceberg $\rho_i$ and density of water $\rho_w$ are related by: $0.9V_i * \rho_w = V_i * \rho_i$ so the density of water is about 10/9 times that of the iceberg. if the iceberg were to float in fresh water, almost all the iceberg would be below. This is dependent on the density of your iceberg and water, since ice expands, the density is slightly less than that of water in liquid form. so not completely under but almost.

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