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*_Artist_*

  • 3 years ago

16 = 1/2*4 (3+ b2)

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  1. *_Artist_*
    • 3 years ago
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    \[16 = half * 4* (3 + b _{2})\]

  2. shadowfiend
    • 3 years ago
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    Are you trying to solve for \(b_2\)?

  3. *_Artist_*
    • 3 years ago
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    yes.

  4. shadowfiend
    • 3 years ago
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    Ok, so let's start at the top. When you have a multiplication between regular numbers, go ahead and do that first. In this case: \[16 = \frac{1}{2}4(3 + b_2)\] You can do the multiplication of 1/2 * 4. What do you get?

  5. *_Artist_*
    • 3 years ago
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    2?

  6. shadowfiend
    • 3 years ago
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    Right. So then we have: \[16 = 2(3 + b_2)\]

  7. shadowfiend
    • 3 years ago
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    Now the easiest thing now is to move that 2 over to the left. Can you do that?

  8. *_Artist_*
    • 3 years ago
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    yes....16 -2 = 14

  9. shadowfiend
    • 3 years ago
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    Not quite. 2 is multiplied on the right, so you have to divide, not subtract, to get it back.

  10. shadowfiend
    • 3 years ago
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    Or, to move it over, rather.

  11. *_Artist_*
    • 3 years ago
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    yes.... duh..I realized that shortly after posting...

  12. *_Artist_*
    • 3 years ago
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    so 16/2 is 8 right?

  13. shadowfiend
    • 3 years ago
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    Right. So now we have: \[8 = 3 + b_2\]

  14. *_Artist_*
    • 3 years ago
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    divide 8 by 3 now?

  15. shadowfiend
    • 3 years ago
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    No, 3 is added in, so we subtract it this time :)

  16. shadowfiend
    • 3 years ago
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    Remember, we can also rewrite that: \[8 = b_2 - 3\]

  17. shadowfiend
    • 3 years ago
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    !! Sorry, I meant: \[ 8 = b_2 + 3 \]

  18. *_Artist_*
    • 3 years ago
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    okay...so \[b _{2}\] =5?

  19. shadowfiend
    • 3 years ago
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    Right! (Sorry for the delay.)

  20. *_Artist_*
    • 3 years ago
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    no biggie

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