*_Artist_*
16 = 1/2*4 (3+ b2)
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*_Artist_*
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\[16 = half * 4* (3 + b _{2})\]
shadowfiend
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Are you trying to solve for \(b_2\)?
*_Artist_*
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yes.
shadowfiend
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Ok, so let's start at the top. When you have a multiplication between regular numbers, go ahead and do that first. In this case:
\[16 = \frac{1}{2}4(3 + b_2)\]
You can do the multiplication of 1/2 * 4. What do you get?
*_Artist_*
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2?
shadowfiend
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Right. So then we have:
\[16 = 2(3 + b_2)\]
shadowfiend
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Now the easiest thing now is to move that 2 over to the left. Can you do that?
*_Artist_*
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yes....16 -2 = 14
shadowfiend
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Not quite. 2 is multiplied on the right, so you have to divide, not subtract, to get it back.
shadowfiend
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Or, to move it over, rather.
*_Artist_*
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yes.... duh..I realized that shortly after posting...
*_Artist_*
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so 16/2 is 8 right?
shadowfiend
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Right. So now we have:
\[8 = 3 + b_2\]
*_Artist_*
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divide 8 by 3 now?
shadowfiend
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No, 3 is added in, so we subtract it this time :)
shadowfiend
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Remember, we can also rewrite that:
\[8 = b_2 - 3\]
shadowfiend
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!! Sorry, I meant:
\[ 8 = b_2 + 3 \]
*_Artist_*
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okay...so \[b _{2}\] =5?
shadowfiend
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Right! (Sorry for the delay.)
*_Artist_*
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no biggie