whats the anti-derivative of -4sqrtx??? having a hard time with this
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Not the answer you are looking for? Search for more explanations.
do you take the anti-derivative of the derivative then?
that answer doesnt seem right.. and whats the *2/3??
You can bring the -4 out because your integrating and -4 is a constant. So now you are just integrating sqrt(x), which can be re-written as x^(1/2). The rule with integration is the exponent + 1 and divide by the new exponent. So that leaves you with x^(3/2) divided by (3/2) and then time the -4 you pulled out in the beginning.
i gotcha... i was reading your answer wrong .. my bad ..
thank you a lot
what about (-3/x)? i got -6x^(1/2)?
Well once again we can pull -3 out to make our lives easier. After doing that we get 1/x. The integral of 1/x is because if you try to integrate this normally you would get x^0 and that is not right. If you would like a full proof of why its lnx, I can send a link. So after integration we get -3ln(x) + C