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i was thinking 2n-8?
Do you mean 2n^2 - 32n?
Well, both of the terms have a factors of 2n, so if we pull 2n out of both we get 2n * (n-16) = 2n^2 - 32n So a factor of 2n^2 - 32n would be (n - 16)
no that answer is wrong it is 2n(n-16)
no it's n-16
because if it was n-16 how are you gonna get to 2n^2-32n
its factoring the binomial
No its not i have a factor calculator go to mathway.com
trust me its right. there are three options on my paper: n-16 2n-8 n+4 its n-16
Model_chic, 2n is a factor, as well as (n-16), both are correct. It would be good form to list both factors, but either would work if they just want one factor.
so wouldn't it be (n-16) (n-16)
please tell me how you got n-16
Lets look at the equation. It is 2n^2 - 32n. The 2n^2 part and the 32n part have a common factor. 2n divides nicely into both of them, when we divide 2n^2 by 2n we get n, and when we divide 32n by 2n we get 16. So we can rewrite the equation like so 2n * (n-16) = 2n^2 - 32n We can verify this is correct by multiply 2n and (n - 16) to get our original equation.
then it will just be 2n*(n-16) i just searched it up
i mean 2n(n-16)
Yes, but keep in mind, 2n is a factor, and (n-16) is a factor.
2n is also yhe gcf sp when you have your final answer the gcf will be in your answer