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anonymous
 5 years ago
1. P=2L+2w p=700 meters w= .75 x L 700/4 sides 175 =4 equal sides i substituted 150 in for w. then subed 200 in for L
L= 200 W= 150
2.The width of my computer room is _____% of its length. If the perimeter is 52 feet, then what are the length and width?
anonymous
 5 years ago
1. P=2L+2w p=700 meters w= .75 x L 700/4 sides 175 =4 equal sides i substituted 150 in for w. then subed 200 in for L L= 200 W= 150 2.The width of my computer room is _____% of its length. If the perimeter is 52 feet, then what are the length and width?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0can you format that to something readable by the rest of us :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is a discussion topic i have to answer that is what is given

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01. Solve the following problem. The width of a rectangular lot is 75% of its length. If the perimeter is 700 meters, then what are the length and width?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0P=2l+2w is the perimeter of a rectangular room. P=700 width is 3/4 of the lenght...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure what the question is in the first one...because i think you solved it... for the second question let L = length let W = width let x = percentage (ie 5%, then x would be 0.05) W = L*x 2W + 2L = 52 substitute 2(L*x) + 2L = 52 L*x + L = 26 L ( x + 1) = 26 L = 26 / (x+1) W = (26*x) / (x+1)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0700 = 14l/4 280 = 14l 280/14 = l l = 140/7 = 120

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0l = 700; w = 350/4 if we go the top route and thats after I fixed my glaring fauxpas :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i think i just had a lobotomy :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0# 2 is me having to measure a room and make up an equation for someone else to solve or do you mean the 2L 2W

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm... then say the length is 100% of the width and make it a square ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.052/4 = 13....that was EASY!! lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre plz helo me write that essay its do tommorwo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cant be a square has to be rectangluar

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0a square IS a rectangle

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0by definition a square is a rectangle; just a special rectangle

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok so what is the answer you confused me

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0mary, I dont write esssays; at least not well. And I aint got the time to do no reasearchand put the stuff together if I did.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0You wanted to make up a question to fit the ...thing.. in Q2 right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if p=52 and the width is 100% of the l then l and w are 13

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Q1 and Q2 are for my discussion thread it belongs to another student that I have to answer, Pt.2 is i have to do the same for him to answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then put in 100% as the answer :) "The width of my computer room is __100___% of its length. If the perimeter is 52 feet, then what are the length and width?"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01. Solve the following problem. The width of a rectangular lot is 75% of its length. If the perimeter is 700 meters, then what are the length and width? 2. Measure the length and width of any rectangular (not square) room in your residence, and calculate the perimeter. Determine what percent of the length the width of the room is. Write a problem following the format below and post it for your classmates to solve. The width of my (living room, family room, etc) is ____% of its length. If the perimeter is ____ meters, then what are the length and width? Due by 11:59 MST on Friday. 3 Pick a problem posted by your classmate and solve it either by substitution or elimination. Make sure to pick the problem not solved by somebody else and show all steps in the solution. Explain why you chose the method you did. Due by 11:59 MST on Sunday.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know thats alot but this is the assignment so u helped me answer the students which is number 3

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0percent is figured out by taking the "part" and dividing by the "total"; times 100. 35/100 = .35 .35 * 100 = 35% :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if the length is 144 and the width is 98: the percentages are: l/w = .xxx times 100 = xx.x%

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i have to show my work

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0W = (.75)L 700 = 2(.75L) + 2L 700 = 1.5L +2L 700 = 3.5L 700/3.5 = L L = 200. W = .75(200) = 150

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0so number 2 says NOT a square...what a crock !

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0im here.. :) got side tracked

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0....butterfly......>>>>>

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i love butterflies all my tats are

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.07 is fine; say 7 is the width and times that by 4; 28 28 is my length; and my width is 25% of the length

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.014+56 = 70 is the perimeter of my room....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i aint got any tats. im a good Mormon, most of the time :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The width of my room, is 25% of its length. If the perimeter is ____ meters, then what are the length and width? the perimeter is how many meters 70?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.070..yes/ 7+7+28+28 = 14+56 = 70

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hey r u there amistre64? yesterday you helped me with this The width of my room, is 25% of its length. If the perimeter is 70 meters, then what are the length and width? was that 70meters or 70 ft this is my teacher response Please check your measurements. First, the ratio of the width to the length is too small. Your room must very narrow. Second, the perimeter of 70 meters appears to be to big for a room in a residence. Is it in meters or feet?
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