1. P=2L+2w p=700 meters w= .75 x L 700/4 sides 175 =4 equal sides i substituted 150 in for w. then subed 200 in for L
L= 200 W= 150
2.The width of my computer room is _____% of its length. If the perimeter is 52 feet, then what are the length and width?

- anonymous

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- schrodinger

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- anonymous

TIANA

- amistre64

can you format that to something readable by the rest of us :)

- anonymous

it is a discussion topic i have to answer that is what is given

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## More answers

- anonymous

1. Solve the following problem. The width of a rectangular lot is 75% of its length. If the perimeter is 700 meters, then what are the length and width?

- amistre64

P=2l+2w is the perimeter of a rectangular room.
P=700 width is 3/4 of the lenght...

- amistre64

700 = 2l + 6l/4

- anonymous

I'm not sure what the question is in the first one...because i think you solved it...
for the second question
let L = length
let W = width
let x = percentage (ie 5%, then x would be 0.05)
W = L*x
2W + 2L = 52
substitute
2(L*x) + 2L = 52
L*x + L = 26
L ( x + 1) = 26
L = 26 / (x+1)
W = (26*x) / (x+1)

- amistre64

700 = 14l/4
280 = 14l
280/14 = l
l = 140/7 = 120

- anonymous

tina

- amistre64

l = 700; w = 350/4 if we go the top route and thats after I fixed my glaring fauxpas :)

- amistre64

DOH!.....

- amistre64

i think i just had a lobotomy :)

- amistre64

l=200; w=150

- amistre64

whats with number 2?

- anonymous

# 2 is me having to measure a room and make up an equation for someone else to solve or do you mean the 2L 2W

- amistre64

hmmm... then say the length is 100% of the width and make it a square ;)

- amistre64

52/4 = 13....that was EASY!! lol

- anonymous

amistre plz helo me write that essay its do tommorwo

- anonymous

cant be a square has to be rectangluar

- amistre64

a square IS a rectangle

- anonymous

amistre plz

- amistre64

by definition a square is a rectangle; just a special rectangle

- anonymous

ok so what is the answer you confused me

- amistre64

mary, I dont write esssays; at least not well. And I aint got the time to do no reasearchand put the stuff together if I did.

- amistre64

You wanted to make up a question to fit the ...thing.. in Q2 right?

- amistre64

if p=52 and the width is 100% of the l then l and w are 13

- anonymous

Q1 and Q2 are for my discussion thread it belongs to another student that I have to answer, Pt.2 is i have to do the same for him to answer

- amistre64

then put in 100% as the answer :)
"The width of my computer room is __100___% of its length. If the perimeter is 52 feet, then what are the length and width?"

- amistre64

l=13 ; w=13

- anonymous

ok gottcha

- anonymous

1. Solve the following problem. The width of a rectangular lot is 75% of its length. If the perimeter is 700 meters, then what are the length and width?
2. Measure the length and width of any rectangular (not square) room in your residence, and calculate the perimeter. Determine what percent of the length the width of the room is. Write a problem following the format below and post it for your classmates to solve.
The width of my (living room, family room, etc) is ____% of its length. If the perimeter is ____ meters, then what are the length and width?
Due by 11:59 MST on Friday.
3 Pick a problem posted by your classmate and solve it either by substitution or elimination. Make sure to pick the problem not solved by somebody else and show all steps in the solution. Explain why you chose the method you did.
Due by 11:59 MST on Sunday.

- anonymous

i know thats alot but this is the assignment so u helped me answer the students which is number 3

- amistre64

percent is figured out by taking the "part" and dividing by the "total"; times 100.
35/100 = .35
.35 * 100 = 35% :)

- amistre64

if the length is 144 and the width is 98: the percentages are:
l/w = .xxx times 100 = xx.x%

- anonymous

what is #1

- amistre64

L=200; W=150 is #1

- anonymous

ok i have to show my work

- amistre64

W = (.75)L
700 = 2(.75L) + 2L
700 = 1.5L +2L
700 = 3.5L
700/3.5 = L
L = 200. W = .75(200) = 150

- amistre64

so number 2 says NOT a square...what a crock !

- amistre64

pick a number....

- amistre64

between 1 and 15

- anonymous

7

- anonymous

does 7 work

- anonymous

r u there

- amistre64

im here.. :) got side tracked

- amistre64

....butterfly......>>>>>

- anonymous

i love butterflies all my tats are

- amistre64

7 is fine; say 7 is the width and times that by 4; 28
28 is my length; and my width is 25% of the length

- amistre64

14+56 = 70 is the perimeter of my room....

- amistre64

i aint got any tats. im a good Mormon, most of the time :)

- anonymous

ive got 3

- anonymous

The width of my room, is 25% of its length. If the perimeter is ____ meters, then what are the length and width?
the perimeter is how many meters 70?

- amistre64

70..yes/ 7+7+28+28 = 14+56 = 70

- anonymous

ok i get it

- anonymous

hey r u there amistre64? yesterday you helped me with this
The width of my room, is 25% of its length. If the perimeter is 70 meters, then what are the length and width?
was that 70meters or 70 ft
this is my teacher response
Please check your measurements. First, the ratio of the width to the length is too small. Your room must very narrow. Second, the perimeter of 70 meters appears to be to big for a room in a residence. Is it in meters or feet?

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