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anonymous
 5 years ago
Solve kjackson's problem by double integrals. A rectangular prism planter is filled with potting soil. It has a length of 3 feet and a width of 8inches and a height of 8 inches. How much potting soil can it hold?
anonymous
 5 years ago
Solve kjackson's problem by double integrals. A rectangular prism planter is filled with potting soil. It has a length of 3 feet and a width of 8inches and a height of 8 inches. How much potting soil can it hold?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright, I prefer doing these with triples, but it was good to think about these again. integral(from 0 36) integral(0 8) (8dA) integral(from 0 36) 8x(0 to 8) integral(from 0 36) 64dz 64z(0 36) 2034

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{3}\int\limits_{0}^{8}8dxdy\] The outer integral would be the length (or y) and the inner one would be width(or x) and the inside is 8 because the height (z) is 8 it would just simplify to 8 * 3 * 3 (which is the volume equation)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Except 3 would be 36, otherwise proper. Do you see why I prefer triples though? It seems more logical, but perhaps thats just me. Same thing is being accomplished, just with triples I see where its coming from.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great, I was trying to figure out what f(x,y) would be. Now I know.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Have you gotten to triple integrals yet chag?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. Haven't got to triples yet.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, well they are the same idea. Its just it seems clearer to do volume problem in them: In this problem z = 36, y = 8, x = 8. Just makes more sense to me, but I also like using overkill math techniques to figure out simple stuff like this like you do. I am very fun at parties! \[\int\limits_{0}^{z} \int\limits_{0}^{y} \int\limits_{0}^{x} f(x,y,z) dx dy dz\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Great. You're invited to my next soiree.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't understand why z is 36..... z is just the height of the box, which is 8 the triple integral would just be \[\int\limits_{0}^{3}\int\limits_{0}^{8}\int\limits_{0}^{8}1dzdydx\] again, giving you 8 * 8 * 3 = 192

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think they slipped in 3 ft and 8 inches

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Z is 36 because the 3 is in units feet.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops i didn't see that i have people that mix units :x i stand corrected! scot's right
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