Solve kjackson's problem by double integrals. A rectangular prism planter is filled with potting soil. It has a length of 3 feet and a width of 8inches and a height of 8 inches. How much potting soil can it hold?

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Solve kjackson's problem by double integrals. A rectangular prism planter is filled with potting soil. It has a length of 3 feet and a width of 8inches and a height of 8 inches. How much potting soil can it hold?

Mathematics
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Alright, I prefer doing these with triples, but it was good to think about these again. integral(from 0 36) integral(0 8) (8dA) integral(from 0 36) 8x|(0 to 8) integral(from 0 36) 64dz 64z|(0 36) 2034
\[\int\limits_{0}^{3}\int\limits_{0}^{8}8dxdy\] The outer integral would be the length (or y) and the inner one would be width(or x) and the inside is 8 because the height (z) is 8 it would just simplify to 8 * 3 * 3 (which is the volume equation)
Except 3 would be 36, otherwise proper. Do you see why I prefer triples though? It seems more logical, but perhaps thats just me. Same thing is being accomplished, just with triples I see where its coming from.

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Great, I was trying to figure out what f(x,y) would be. Now I know.
Have you gotten to triple integrals yet chag?
No. Haven't got to triples yet.
Ok, well they are the same idea. Its just it seems clearer to do volume problem in them: In this problem z = 36, y = 8, x = 8. Just makes more sense to me, but I also like using overkill math techniques to figure out simple stuff like this like you do. I am very fun at parties! \[\int\limits_{0}^{z} \int\limits_{0}^{y} \int\limits_{0}^{x} f(x,y,z) dx dy dz\]
Great. You're invited to my next soiree.
I don't understand why z is 36..... z is just the height of the box, which is 8 the triple integral would just be \[\int\limits_{0}^{3}\int\limits_{0}^{8}\int\limits_{0}^{8}1dzdydx\] again, giving you 8 * 8 * 3 = 192
I think they slipped in 3 ft and 8 inches
Z is 36 because the 3 is in units feet.
oops i didn't see that i have people that mix units :x i stand corrected! scot's right

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