anonymous
  • anonymous
The sum of the squares of two consecutive odd integers is 74. Find the two integers.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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dumbcow
  • dumbcow
odd integer can be represented as 2n+1 and the next odd int would 2n+3 so you have: (2n+1)^2 + (2n+3)^2 = 74 solve for n
anonymous
  • anonymous
i dont understand it..
anonymous
  • anonymous
i dont remember how to solve n

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More answers

dumbcow
  • dumbcow
hmm i guess an easier way is to look at perfect squares and which ones add up to 74 1,3 = 1^2 + 3^2 = 10 3,5 = 3^2 + 5^2 = 34 ....
anonymous
  • anonymous
so its 3 and 5?
dumbcow
  • dumbcow
just remember when you find it that their negative counterparts are answers too because we square them -5,-3, = (-5)^2 + (-3)^2 = 34 ...
dumbcow
  • dumbcow
no sum of 3 and 5 squared is 34...keep going try 5,7 7,9 9,11 has to equal 74
anonymous
  • anonymous
5 and 7
dumbcow
  • dumbcow
correct
anonymous
  • anonymous
thank you!
dumbcow
  • dumbcow
your welcome
anonymous
  • anonymous
Your first method was nicer :( You can't brute force it once you get up to bigboy numbers

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