The sum of the squares of two consecutive odd integers is 74. Find the two integers.

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The sum of the squares of two consecutive odd integers is 74. Find the two integers.

Mathematics
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odd integer can be represented as 2n+1 and the next odd int would 2n+3 so you have: (2n+1)^2 + (2n+3)^2 = 74 solve for n
i dont understand it..
i dont remember how to solve n

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hmm i guess an easier way is to look at perfect squares and which ones add up to 74 1,3 = 1^2 + 3^2 = 10 3,5 = 3^2 + 5^2 = 34 ....
so its 3 and 5?
just remember when you find it that their negative counterparts are answers too because we square them -5,-3, = (-5)^2 + (-3)^2 = 34 ...
no sum of 3 and 5 squared is 34...keep going try 5,7 7,9 9,11 has to equal 74
5 and 7
correct
thank you!
your welcome
Your first method was nicer :( You can't brute force it once you get up to bigboy numbers

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