A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

solve by factoring t^2+3t-18=0

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The general form of polynomials like this are (Xn +/- Constant1) * (Yn +/- Constant2) Since the constant in the equation (-18) is negative, one of the constants in our new equation has to be negative, and other has to positive. And since our t^2 term has no coefficient, neither X nor Y can be anything besides 1. So rewriting: (t + Constant1) * (t - Constant2) Now we have to be clever. We need to find out which factors of 18 would ever add or subtract to be the coefficient of the t term. The factors of 18 are 1, 2, 3, 6, 9 and 18. We notice that 6 minus 3 would equal 3 so we put 6 in the positive spot, and 3 minus spot. (t + 6)(t - 3) = 0

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The answer is (t+6)(t-3)=0 To check it you can use distributive property to check your answer

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.