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anonymous
 5 years ago
solve by factoring
t^2+3t18=0
anonymous
 5 years ago
solve by factoring t^2+3t18=0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The general form of polynomials like this are (Xn +/ Constant1) * (Yn +/ Constant2) Since the constant in the equation (18) is negative, one of the constants in our new equation has to be negative, and other has to positive. And since our t^2 term has no coefficient, neither X nor Y can be anything besides 1. So rewriting: (t + Constant1) * (t  Constant2) Now we have to be clever. We need to find out which factors of 18 would ever add or subtract to be the coefficient of the t term. The factors of 18 are 1, 2, 3, 6, 9 and 18. We notice that 6 minus 3 would equal 3 so we put 6 in the positive spot, and 3 minus spot. (t + 6)(t  3) = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The answer is (t+6)(t3)=0 To check it you can use distributive property to check your answer
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