How do I get the lowest common multiple with: 2233 and 333?

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How do I get the lowest common multiple with: 2233 and 333?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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How do I get the lowest common multiple of 36, 27. Ignore first question...
you find a number that will divide evenly into both of your numbers
I know that...

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Other answers:

The first question was more fun - if a little weird, considering they were coprime.
The answer is 3
The answer isn't 3 ^
Ok
my bad i was thinking about something else geesh
36 = 4 * 9 27 = 3 * 9 Does that help?
?
36 = 4 X 9 27 = 3 X 9
To find the lowest common multiple, you can find their highest common factor first. i.e. if n = 5 * k and m = 7 * k , their lowest common multiple is 5 * 7 * k Or you can write out their multiples until one is the same.
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newton
The LCM is 108
The lowest common multiple is 3 x 4 x 9
plz help me write my essay
inewton
I don't know k and m.
its 108
ok
i newtown
It was just an example. I was trying to help you learn a method yo can apply again and not tell you the answer.
newtom
Mary I'm not going to write your essay, now go away.
ok but plz
The lcm is 108
Why ON EARTH would I write your essay.
108 = 3 x 4 x 9 ....
that helps me its due tommorow
He said no so NO.
model chic how did you figure it out?
I wrote out all the multiples
Thank you all...
I don't have any more questions...
Thank you INewton and model_chic13 for helping me...

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