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anonymous
 5 years ago
anti deriv. of 5/ (1+25s^2) ?
anonymous
 5 years ago
anti deriv. of 5/ (1+25s^2) ?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no thats not it .. the derivative of that is 5arctan(25s)... i need the anti deriv. of 5/ (1+25s^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That looks similar to the derivative of arctan. Which is du/(1+u2)=(arctanu)′ So know that, the u would be 5s so the answer would be arctan(5s). 5/(1+(5s)2)=(arctan5s)′

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0correct me if i am wrong an antideriv is going from the derivative back to the function it's self?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks scot.. haha i knew that .. yes thats right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0zbay, yes, its also called an integral.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Antiderivative of that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This, I think is one of the harder integrals to see how to do it. You have to use parts. Where u = lnx and dv = 1. Then du = 1/x and v = x. So uv  integral(vdu) is xlnx  x + C is the general form, and then times the 5 so 5xlnx + 5x + C is the final answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow..... ya i wasnt even close to that answer... but ya i get it now ... thanks
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