anonymous
  • anonymous
anti deriv. of 5/ (1+25s^2) ?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
5ln(1+25s^2)?
anonymous
  • anonymous
no thats not it .. the derivative of that is 5arctan(25s)... i need the anti deriv. of 5/ (1+25s^2)
anonymous
  • anonymous
That looks similar to the derivative of arctan. Which is du/(1+u2)=(arctanu)′ So know that, the u would be 5s so the answer would be arctan(5s). 5/(1+(5s)2)=(arctan5s)′

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anonymous
  • anonymous
correct me if i am wrong an antideriv is going from the derivative back to the function it's self?
anonymous
  • anonymous
thanks scot.. haha i knew that .. yes thats right
anonymous
  • anonymous
zbay, yes, its also called an integral.
anonymous
  • anonymous
-5ln(u)? ,,,
anonymous
  • anonymous
Anti-derivative of that?
anonymous
  • anonymous
ya
anonymous
  • anonymous
This, I think is one of the harder integrals to see how to do it. You have to use parts. Where u = lnx and dv = 1. Then du = 1/x and v = x. So uv - integral(vdu) is xlnx - x + C is the general form, and then times the -5 so -5xlnx + 5x + C is the final answer.
anonymous
  • anonymous
wow..... ya i wasnt even close to that answer... but ya i get it now ... thanks

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