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no thats not it .. the derivative of that is 5arctan(25s)... i need the anti deriv. of 5/ (1+25s^2)
That looks similar to the derivative of arctan. Which is
So know that, the u would be 5s so the answer would be arctan(5s).
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correct me if i am wrong an antideriv is going from the derivative back to the function it's self?
thanks scot.. haha i knew that .. yes thats right
zbay, yes, its also called an integral.
Anti-derivative of that?
This, I think is one of the harder integrals to see how to do it. You have to use parts. Where u = lnx and dv = 1. Then du = 1/x and v = x. So uv - integral(vdu) is xlnx - x + C is the general form, and then times the -5 so -5xlnx + 5x + C is the final answer.
wow..... ya i wasnt even close to that answer... but ya i get it now ... thanks