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anonymous

  • 5 years ago

limit as x tends to infinity of 5sin(x^3)/sin^3(2x)?

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  1. anonymous
    • 5 years ago
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    sorry, x tends to 0

  2. anonymous
    • 5 years ago
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    That makes more sense.

  3. anonymous
    • 5 years ago
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    yeah lol..any ideas?

  4. anonymous
    • 5 years ago
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    You're going to have to use L'Hopitals rule because if you put 0 in for the Xs you get the indeterminant form 0/0.

  5. anonymous
    • 5 years ago
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    ok, i'll give that a go

  6. anonymous
    • 5 years ago
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    done the top and got 15x^2cosx^3... the bottom could take a while longer

  7. anonymous
    • 5 years ago
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    If you can somehow determine that the bottom cannot equal zero, you could save yousrself a good deal of time, since the top will always equal zero.

  8. anonymous
    • 5 years ago
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    is there any sin/cos equations for sin^3(x) that can be used

  9. anonymous
    • 5 years ago
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    its just gonna be a long retricel'hopital iteration i think

  10. anonymous
    • 5 years ago
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    it cant be that difficult, its only worth 2 marks lol

  11. anonymous
    • 5 years ago
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    sin^3 is tricky in the way that you need to use two of the derivation methods you've been taught. Rewrite it as (sin(x)) ^ 3 Now use the power rule + chain rule 3(sin^2(x))(cos x) Another iteration will be required.

  12. anonymous
    • 5 years ago
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    well l'hopital's not really that difficult so meh could be worth 2 marks

  13. anonymous
    • 5 years ago
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    ive applied l'hopitals once and it diddnt help :(

  14. anonymous
    • 5 years ago
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    Keep going, sometimes it takes a few. The problem is probably aimed to teach you that.

  15. anonymous
    • 5 years ago
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    think ive got it

  16. anonymous
    • 5 years ago
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    sin^3(2x)=(2sinxcosx)^3=8sin^3xcos^3x so we have 5sin(x^3)/(8sin^3xcos^3x)

  17. anonymous
    • 5 years ago
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    oh wait, nope :(

  18. anonymous
    • 5 years ago
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    answers 5/8 btw

  19. anonymous
    • 5 years ago
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    yeah, i got that off wolfram..there must be a way of getting sin(x)/x in there somehow

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