The lengths of the sides of a triangle form three consecutive odd numbers. The perimeter is 21 centimeters. What is the length of the longest side?

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The lengths of the sides of a triangle form three consecutive odd numbers. The perimeter is 21 centimeters. What is the length of the longest side?

Mathematics
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Consecutive odd numbers differ by 2. n + (n + 2) + (n + 4) = 21 n + n + 2 + n + 4 = 21 3n+6=21 3n=21-6=15 n=5 5, 5+2=7, 5+4=9 5+7+9=21
Small thing (very small). It's a slicker operation if you call them (n-2) , n, (n+2) I mean, obviously it makes no difference, but I prefer it :D
Yes, the twos cancel. ------- Did you review my solution to your "fun" problem the other day?

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no, sorry :( I'll try and find that thread again
A real shame :( You (I think) misread the fractions 1/3 1/5 1/7 etc as 13, 15, 17. I think that is the cause of the difference. I assume yours are correct to the (slightly different) problem though.
I will redo it with your fractions. Thanks for responding.
I look forward to it
After my last post above, I remember taking a screen capture of the problems that you posted on this math site so that I would not make any errors in the equations to be solved. Refer to the attachment, a screen capture. I will check the equations carefully again.
Oh, weird, your computer doesn't render LaTeX on this site :/
What do you see below? \[\frac{4}{5} \] ? Because that renders as a fraction (4/5), do you see 45?
I see 45 on the screen. Unable today to enter x^2 and have complained about it. x^2 is present as 2x in their window. I'll try another computer or use a virtuaized version of Ubuntu Linux.
:( Sorry for any confusion. For the record the full question is in this image: one jpeg and one tif

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