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anonymous
 5 years ago
condense the expression: 1/2Log5 163log5 x+4Log5y
anonymous
 5 years ago
condense the expression: 1/2Log5 163log5 x+4Log5y

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first move the coefficients that are infront of the logarithms to the right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0meaning log\[\log_{5} 16^{1/2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ignore the first log my equations button is not working

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but the log expression below is correct use that example to simplify the other two

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then let me know what you got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\log_{5} 4\log_{5} x ^{3}+\log_{5} y ^{4}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thankyou for helping me their just really hard for me ;(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we aren't done yet sorry, now when you are subtract two logs with the same base do you condense them by multiplying them together or dividing them?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes so log base 4 is on top the numerator making the other two...?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0on the bottom being multiplied together

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because they were being added

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so can you show me what your answer would be?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when you are adding two logs together with the same base then you multiply them together

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\log_{5} (4/x ^{3}y ^{4})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just want to make sure you understand rather than just giving you the answer so that later you can ace a test on this if you need to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok why we try another problem. this will be the last one i can help with, then i have to go alright?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0solve the equation; 15+2 log2 x=31

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so when solving for any variable the whole point is to get the variable by itself so what would be one thing we can move away from the side with x easily?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i didn't mean the final answer, i meant that it will be easy to move the fifteen since the fifteen is not attached to anything

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes we subtract fifteen from both sides then we simplify the logarithm but first what does the new equation look like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it will equeal 16instead of 31

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0know we focus on the log

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what can we move to condense the logarithm more?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so what do we have now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no... \[\log_{2} x ^{2}=16\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay a trick that i learned is you put the same base of the log you want to remove under both sides of the equation like so: \[2^{\log_{2}x ^{2} }=2^{16}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now what can you simplify?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes \[x ^{2}=2^{16}\] is our new equation as 2^log base 2 equals one

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now what would be the next step?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why would we do that when we already have x by itself. what we would do is simplify 2^16=65536

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes now what would you do to get x all by itself?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0take the root of x and the other side

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does that make sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{x ^{2}}=\sqrt{65536}=x=256\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no problem I have to go now, but i wish you the best of luck :)
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