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anonymous
 5 years ago
I have a hyperbola on a graph. all i know is the center and the two verticies. How do i find the equaton of it?
anonymous
 5 years ago
I have a hyperbola on a graph. all i know is the center and the two verticies. How do i find the equaton of it?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the hyperbola opens to the side like this: )(

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0There's more about this at http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the true problem is that i dont have a or b or the asymptotes

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0I believe a and b can be found based on the center and the vertices, no?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what im not sure on. i know it has something to do with h and k and the vertices but im not sure how to use the verticies to get and b

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Ah, pwned. B is the problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the verticies are (15,9.5) and (14,9.5) and the center is (14.5,9.5)

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Hm. Can I see the graph? If you can take a picture/scan it, you can upload it here using the attach file button.

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Also, what class is this for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with the new math system its accel math 2

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Eh... Did not work :(

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0What kind of file is it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually i know why it didnt work

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0I see. Heh. Is it an image or a PDF or what? If it's an image, it's probably a TIFF file. You can open it in Paint and then save as a PNG.

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0Aha. Ok, so open the PDF, go to whatever page has the relevant graph, and then hit Alt+PrntScrn (not sure where the prntscrn or `print screen' button will be on your keyboard). Then, open Paint and paste.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0had to use gif but i got it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its the cherry stems on the top right i think also its flipped so what seems to be the x axis is the y axis

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0its the cherry stems on the top right i think also its flipped so what seems to be the x axis is the y axis

shadowfiend
 5 years ago
Best ResponseYou've already chosen the best response.0I think you may be supposed to estimate the slope of the tangent lines by finding the slope between the center and the endpoints on those hyperbolas.
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