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anonymous

  • 5 years ago

I have a hyperbola on a graph. all i know is the center and the two verticies. How do i find the equaton of it?

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  1. anonymous
    • 5 years ago
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    the hyperbola opens to the side like this: )(

  2. shadowfiend
    • 5 years ago
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    There's more about this at http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx

  3. anonymous
    • 5 years ago
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    the true problem is that i dont have a or b or the asymptotes

  4. shadowfiend
    • 5 years ago
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    I believe a and b can be found based on the center and the vertices, no?

  5. anonymous
    • 5 years ago
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    thats what im not sure on. i know it has something to do with h and k and the vertices but im not sure how to use the verticies to get and b

  6. anonymous
    • 5 years ago
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    *a and b

  7. shadowfiend
    • 5 years ago
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    Ah, pwned. B is the problem.

  8. anonymous
    • 5 years ago
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    yes

  9. anonymous
    • 5 years ago
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    the verticies are (-15,9.5) and (-14,9.5) and the center is (-14.5,9.5)

  10. shadowfiend
    • 5 years ago
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    Hm. Can I see the graph? If you can take a picture/scan it, you can upload it here using the attach file button.

  11. anonymous
    • 5 years ago
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    alright

  12. shadowfiend
    • 5 years ago
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    Also, what class is this for?

  13. anonymous
    • 5 years ago
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    with the new math system its accel math 2

  14. anonymous
    • 5 years ago
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    conics

  15. shadowfiend
    • 5 years ago
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    Ok, cool.

  16. anonymous
    • 5 years ago
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    1 Attachment
  17. anonymous
    • 5 years ago
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    should be it

  18. shadowfiend
    • 5 years ago
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    Eh... Did not work :(

  19. anonymous
    • 5 years ago
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    that makes me sad

  20. shadowfiend
    • 5 years ago
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    What kind of file is it?

  21. anonymous
    • 5 years ago
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    actually i know why it didnt work

  22. anonymous
    • 5 years ago
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    its 10mb

  23. shadowfiend
    • 5 years ago
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    O_O

  24. shadowfiend
    • 5 years ago
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    I see. Heh. Is it an image or a PDF or what? If it's an image, it's probably a TIFF file. You can open it in Paint and then save as a PNG.

  25. anonymous
    • 5 years ago
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    a pdf

  26. shadowfiend
    • 5 years ago
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    Aha. Ok, so open the PDF, go to whatever page has the relevant graph, and then hit Alt+PrntScrn (not sure where the prntscrn or `print screen' button will be on your keyboard). Then, open Paint and paste.

  27. anonymous
    • 5 years ago
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    k

  28. anonymous
    • 5 years ago
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    1 Attachment
  29. shadowfiend
    • 5 years ago
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    Very nice :)

  30. anonymous
    • 5 years ago
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    had to use gif but i got it

  31. anonymous
    • 5 years ago
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    its the cherry stems on the top right i think also its flipped so what seems to be the x axis is the y axis

  32. anonymous
    • 5 years ago
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    its the cherry stems on the top right i think also its flipped so what seems to be the x axis is the y axis

  33. shadowfiend
    • 5 years ago
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    I think you may be supposed to estimate the slope of the tangent lines by finding the slope between the center and the endpoints on those hyperbolas.

  34. anonymous
    • 5 years ago
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    alright thanks

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