I have a hyperbola on a graph. all i know is the center and the two verticies. How do i find the equaton of it?

- anonymous

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- anonymous

the hyperbola opens to the side like this:
)(

- shadowfiend

There's more about this at http://tutorial.math.lamar.edu/Classes/Alg/Hyperbolas.aspx

- anonymous

the true problem is that i dont have a or b or the asymptotes

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## More answers

- shadowfiend

I believe a and b can be found based on the center and the vertices, no?

- anonymous

thats what im not sure on. i know it has something to do with h and k and the vertices but im not sure how to use the verticies to get and b

- anonymous

*a and b

- shadowfiend

Ah, pwned. B is the problem.

- anonymous

yes

- anonymous

the verticies are (-15,9.5) and (-14,9.5) and the center is (-14.5,9.5)

- shadowfiend

Hm. Can I see the graph? If you can take a picture/scan it, you can upload it here using the attach file button.

- anonymous

alright

- shadowfiend

Also, what class is this for?

- anonymous

with the new math system its accel math 2

- anonymous

conics

- shadowfiend

Ok, cool.

- anonymous

##### 1 Attachment

- anonymous

should be it

- shadowfiend

Eh... Did not work :(

- anonymous

that makes me sad

- shadowfiend

What kind of file is it?

- anonymous

actually i know why it didnt work

- anonymous

its 10mb

- shadowfiend

O_O

- shadowfiend

I see. Heh. Is it an image or a PDF or what? If it's an image, it's probably a TIFF file. You can open it in Paint and then save as a PNG.

- anonymous

a pdf

- shadowfiend

Aha. Ok, so open the PDF, go to whatever page has the relevant graph, and then hit Alt+PrntScrn (not sure where the prntscrn or `print screen' button will be on your keyboard). Then, open Paint and paste.

- anonymous

k

- anonymous

##### 1 Attachment

- shadowfiend

Very nice :)

- anonymous

had to use gif but i got it

- anonymous

its the cherry stems on the top right i think also its flipped so what seems to be the x axis is the y axis

- anonymous

- shadowfiend

I think you may be supposed to estimate the slope of the tangent lines by finding the slope between the center and the endpoints on those hyperbolas.

- anonymous

alright thanks

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