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anonymous
 5 years ago
Find the equation of the osculating plane.
I know there is a long way and a short way to do this. Just find a normal vector for the plane.
1) T(t) = r'(t) / r'(t) Long way
N(t) = T'(t) / T'(t)
B(t) = T(t) x N(t)
2) r'(t) x r''(t) = n(t) Short way
Where n(t) can be used as the normal vector
I just want to know if n(t) and B(t) are equal, or are they just proportionate with the same direction
And then B(t) or n(t) can be used as a normal vector for the plane
anonymous
 5 years ago
Find the equation of the osculating plane. I know there is a long way and a short way to do this. Just find a normal vector for the plane. 1) T(t) = r'(t) / r'(t) Long way N(t) = T'(t) / T'(t) B(t) = T(t) x N(t) 2) r'(t) x r''(t) = n(t) Short way Where n(t) can be used as the normal vector I just want to know if n(t) and B(t) are equal, or are they just proportionate with the same direction And then B(t) or n(t) can be used as a normal vector for the plane

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