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amistre64
 5 years ago
The Area of the region bounded by the xaxis and the graph of y= x^3x: Is it:
1/2 ; 1/4 ; 1/4 ; 0
amistre64
 5 years ago
The Area of the region bounded by the xaxis and the graph of y= x^3x: Is it: 1/2 ; 1/4 ; 1/4 ; 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Doesn't look very well bounded to me :P

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I thought if anything it was the interval between 1 and 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which you could say the area is 1/2 total..

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0that was my first conjecture as well.. But then I read one source that says odd functions cancel to zero; and others which say to add absolute values of the areas together

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You don't need a source to say odd functions cancel to zero :(

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol..... I wish that was true :) but im just to much of an idiot at this stage to know the differences ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:( If I asked you to find: \[\int^\pi_{\pi}x^{10} \sin x \mathbb{d}x \] would you do it all by parts?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0hmm... I would notice that the graph of the sine is odd and that the part [pi,0] has the same "area" as [0,pi] and conclude that the total area would be both parts.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:( The integral is 0 because the functions cancel. HOWEVER, from the exact phrasing of your question, I think you may have to add them together, rather than say 'they cancel', but not completely sure.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I agree that the functions cancel. But intuitivly I want to say that the areas combine to total 1/2. But then the question leaves me to beleieve also that the "bounds" of the function are limitless and not just confined to an interval [1,1]. The total area under the curve and bounded by the x axis would then be zero to me becasause I can t see trying to take an infinite area....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think in questions like this it is assumed they mean the 'finite area bounded'  it is just sometimes left out.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I agree. But the solutions I put into the answer box all tell me im wrong. ......

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You tried all the solutions in your original post? Hmm

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0yep, tried 1/2 to begin with; then figured if it aint that then zero, then the only other options that make sense are 1/4 or 1/4. I think the programs broke :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0infinity/2...maybe? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I honestly have no idea what it could be. I agree, it's broken.
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