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anonymous
 5 years ago
how to find the domain
anonymous
 5 years ago
how to find the domain

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can't have a square of a negative number so 3x + 4 must be greater than or equal to zero so your domain is \[3x + 4 \ge 0\] \[x \ge \frac{4}{3}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks! I got the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Factor 5z(2z+1)2(2z+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OH I SEE IT NOW ignore my other anwer it's (2z + 1)(5z 2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you help me with my other problems ,

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0won't know till you tell me the questions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can yu help with the steps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so you need two numbers that multiply to 20 and add up to 9 the numbers at multiply to 20 are 2,10 1,20 and 4,5 only 4 and 5 add up to 9 so it's 4 and 5 so (x + 4)(x + 5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04a2+a3 so we need two numbers that can muliply by a3 right ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, this one is different, because there's a 4 in front of the a squared.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going to try to explain this...so bear with me.... :x so your answer is going to be something like this with numbers in place of the _ (_a + _)(_a + )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Correction : (_a + _)(_a + _)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sigh..this is hard over the internet...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0go to this site http://tutorial.math.lamar.edu/Classes/Alg/Factoring.aspx it's really helpful i'm sorry that i can't explain this. but read over the site. it explains it quite well. tell me how it goes go to example 3 part e
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