A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
I need some help solving these problems through elimination.
1) 4x+3y=1
2x+5y=3
2) 12x5y=9
3x8y=18
anonymous
 5 years ago
I need some help solving these problems through elimination. 1) 4x+3y=1 2x+5y=3 2) 12x5y=9 3x8y=18

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Is that the intersection of 4 lines? or 2 seperate questions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.02 seperate questions. If yiu can guide me through the first, maybe I can get the second?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0elimination just means that we modify one equation thru multiplication in order to find a value that can cancel out a variable in the other equation.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04x+3y=1 2x+5y=3 < we can multiply this by 2 to get: 4x should we?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04x+3y=1 (2x+5y=3) (2) 4x +3y =1 4x10y =6 < now we add them together 

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.04x +3y =1 4x10y =6  0 7y = 7 < now we solve for y y = 1 is correct

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Since y = 1, we can use that to find "x" in the equations...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do I just plug the y into one of the equations? or both?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0either one is fine; they both meet at a specific point if they are not parallel lines; and that point has y=1 in common; so use it in any of them to find the common x value

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so if I plug it into the first equation I got x=1 is rhat right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01 is good to me :) this is a generic setup so dont be fooled by the position of the solution in my graph.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh... thanks, but thankfully my teacher isnt making us graph :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0You see where the lines cross they have x and y in common right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the solution to a set of equations is "where the lines have X and Y in common". Or at a single point.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks for your help. I want to see if I can get the answer to the second one on my own. If I need help will you be around for a few?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which one should I try to cancel out? Does it matter?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0doesnt matter; pick one and run with it :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0YAy... I think I got it (3,3) Can you help me with this one or tell me if I'm right. This one is using subsitution. 6xy=5 y=11x I got x=5 y=55 I dont think its right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.06x  11x = 5 5x = 5 x = 1

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0since y = "11x" we substitute that value into the other equation: 6x y = 5 6x  (11x) = 5 ...and solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you. I see where I went wrong.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.