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Is that the intersection of 4 lines? or 2 seperate questions?
2 seperate questions. If yiu can guide me through the first, maybe I can get the second?
elimination just means that we modify one equation thru multiplication in order to find a value that can cancel out a variable in the other equation.
4x+3y=-1 2x+5y=3 <- we can multiply this by -2 to get: -4x should we?
4x+3y=-1 (2x+5y=3) (-2) 4x +3y =-1 -4x-10y =-6 <-- now we add them together -------------
So would y be -1
4x +3y =-1 -4x-10y =-6 ------------ 0 -7y = -7 <-- now we solve for y y = 1 is correct
not -1. 1?
ok. got it
Since y = 1, we can use that to find "x" in the equations...
Do I just plug the y into one of the equations? or both?
either one is fine; they both meet at a specific point if they are not parallel lines; and that point has y=1 in common; so use it in any of them to find the common x value
Ok, so if I plug it into the first equation I got x=1 is rhat right?
Oh... thanks, but thankfully my teacher isnt making us graph :)
You see where the lines cross they have x and y in common right?
Yes, I do see that.
the solution to a set of equations is "where the lines have X and Y in common". Or at a single point.
Thanks for your help. I want to see if I can get the answer to the second one on my own. If I need help will you be around for a few?
i should be... :)
Which one should I try to cancel out? Does it matter?
doesnt matter; pick one and run with it :)
YAy... I think I got it (3,3) Can you help me with this one or tell me if I'm right. This one is using subsitution. 6x-y=5 y=11x I got x=-5 y=-55 I dont think its right?
6x - 11x = 5 -5x = 5 x = -1
since y = "11x" we substitute that value into the other equation: 6x -y = 5 6x - (11x) = 5 ...and solve
Thank you. I see where I went wrong.