anonymous
  • anonymous
I need some help solving these problems through elimination. 1) 4x+3y=-1 2x+5y=3 2) 12x-5y=9 3x-8y=-18
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

anonymous
  • anonymous
I need some help solving these problems through elimination. 1) 4x+3y=-1 2x+5y=3 2) 12x-5y=9 3x-8y=-18
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

amistre64
  • amistre64
Is that the intersection of 4 lines? or 2 seperate questions?
anonymous
  • anonymous
2 seperate questions. If yiu can guide me through the first, maybe I can get the second?
amistre64
  • amistre64
elimination just means that we modify one equation thru multiplication in order to find a value that can cancel out a variable in the other equation.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
4x+3y=-1 2x+5y=3 <- we can multiply this by -2 to get: -4x should we?
anonymous
  • anonymous
Ok..
amistre64
  • amistre64
4x+3y=-1 (2x+5y=3) (-2) 4x +3y =-1 -4x-10y =-6 <-- now we add them together -------------
anonymous
  • anonymous
So would y be -1
amistre64
  • amistre64
4x +3y =-1 -4x-10y =-6 ------------ 0 -7y = -7 <-- now we solve for y y = 1 is correct
anonymous
  • anonymous
not -1. 1?
anonymous
  • anonymous
ok. got it
amistre64
  • amistre64
Since y = 1, we can use that to find "x" in the equations...
anonymous
  • anonymous
Do I just plug the y into one of the equations? or both?
amistre64
  • amistre64
either one is fine; they both meet at a specific point if they are not parallel lines; and that point has y=1 in common; so use it in any of them to find the common x value
anonymous
  • anonymous
Ok, so if I plug it into the first equation I got x=1 is rhat right?
anonymous
  • anonymous
-1
amistre64
  • amistre64
-1 is good to me :) this is a generic setup so dont be fooled by the position of the solution in my graph.....
1 Attachment
anonymous
  • anonymous
Oh... thanks, but thankfully my teacher isnt making us graph :)
amistre64
  • amistre64
You see where the lines cross they have x and y in common right?
anonymous
  • anonymous
Yes, I do see that.
amistre64
  • amistre64
the solution to a set of equations is "where the lines have X and Y in common". Or at a single point.
anonymous
  • anonymous
Thanks for your help. I want to see if I can get the answer to the second one on my own. If I need help will you be around for a few?
amistre64
  • amistre64
i should be... :)
anonymous
  • anonymous
Which one should I try to cancel out? Does it matter?
amistre64
  • amistre64
doesnt matter; pick one and run with it :)
anonymous
  • anonymous
YAy... I think I got it (3,3) Can you help me with this one or tell me if I'm right. This one is using subsitution. 6x-y=5 y=11x I got x=-5 y=-55 I dont think its right?
amistre64
  • amistre64
6x - 11x = 5 -5x = 5 x = -1
amistre64
  • amistre64
since y = "11x" we substitute that value into the other equation: 6x -y = 5 6x - (11x) = 5 ...and solve
anonymous
  • anonymous
Thank you. I see where I went wrong.

Looking for something else?

Not the answer you are looking for? Search for more explanations.