A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
How do I solve for #12? I've attached the problem.
anonymous
 5 years ago
How do I solve for #12? I've attached the problem.

This Question is Closed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0t = 8 is the maximum acceleration

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0haha thanks do you know how to do #12?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0acceleration is any change in velocity; where the velocity is level, there is no acceleration.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we have the velocity changing at a rate of 1 in the first part. zero in the next segment; 6/3 in the next = 2 and 4/1 in the last part. so maybe between 8 and 9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer to 12 is D if that helps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i think your looking at #10

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0lol....without knowing what D stands for, it aint much help ;)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0oh.... theres more if you scroll it lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at t=8 the objects position was at x=10 ?? how do they figure that?

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0ok for #12 find equation for line from t=5 and t=8 slope is 2 v= 2 when t=5 2=2*5 + b b = 12 v(t) = 2t +12 for 5<t<8 now we need position function x(t) so integrate v(t) x(t) = t^2+12t +c we know x(8) = 10 8^2 +12*8 +c = 10 c = 22 find x(5) 5^2 +12*5 22 = 13
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.