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anonymous
 5 years ago
Can someone please help me. I need help "solving the system"
2x+y+z=9
xy+z=1
3xy+z=9
anonymous
 5 years ago
Can someone please help me. I need help "solving the system" 2x+y+z=9 xy+z=1 3xy+z=9

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Start off by adding line one and line two; and now you have at least the y disappearing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I did that. I did it with 1st and 3rd to get 5x+2z=9

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then I went and did it to the 1st and 2nd. Giving me x+2z=10

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, you have infinitely many choices and your classmates may go about a different way. in x+2z=10 Let z=0. It is your equation you can do what ever you want. So when z=0 in your eq x=10. So x=10, z=0, punch those values in the third eq and solve for y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0?? Thanks. sorry, but you lost me.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Its not what our teacher said to do, and I know I will be required to show my work.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The proof is you can plug in the values of x,y,z and see if it equals what is on the other side. Math has a lot of different methods. Tell me specifically what you don't understand.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I came up with (2,1,4) and it fits into the equation. Am I right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Let's test it with the second equation xy+z=1 21+4=1 1=1 You are exactly right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:)) Yay!!!!!! Thanks!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can also test them with the others to make sure it wasn't a fluke, but you are doing great.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, if I can get the next one...lol!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0UGH... This one isnt working out right... Can I explain (the best I know how) what I am doing????

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry I had signed out to watch basketball. Hope you figured it out.
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