## anonymous 5 years ago find the distinguisable permutations in the group of letters: C A L C U L U S

1. anonymous

You're trying to find all possible combinations of the letters, without distinguishing between 'different' U's, C's and L's. If you have 8 letters (as here), the total number of permutations taken 8 at a time is 8!. But, you have C, L and U's counted 2! times each (you can arrange C, 2! ways, for example). You must undo this excess counting, so you have$\frac{8!}{2!^3}=\frac{8 \times 7!}{8}=7!=5040$distinguishable permutations.

2. anonymous

so after i work out the problem ill have my answr? or do i leave it as is

3. anonymous

Oh, I think you're being asked to find the number of distinguishable permutations. It would take you forever to write them all out (there's 5040 of them!).

4. anonymous

5. anonymous

Yes.

6. anonymous

im sorry! im terrible at math, im more of a science gal, but thank you soo much!

7. anonymous

no probs :)