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anonymous

  • 5 years ago

find the distinguisable permutations in the group of letters: C A L C U L U S

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  1. anonymous
    • 5 years ago
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    You're trying to find all possible combinations of the letters, without distinguishing between 'different' U's, C's and L's. If you have 8 letters (as here), the total number of permutations taken 8 at a time is 8!. But, you have C, L and U's counted 2! times each (you can arrange C, 2! ways, for example). You must undo this excess counting, so you have\[\frac{8!}{2!^3}=\frac{8 \times 7!}{8}=7!=5040\]distinguishable permutations.

  2. anonymous
    • 5 years ago
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    so after i work out the problem ill have my answr? or do i leave it as is

  3. anonymous
    • 5 years ago
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    Oh, I think you're being asked to find the number of distinguishable permutations. It would take you forever to write them all out (there's 5040 of them!).

  4. anonymous
    • 5 years ago
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    so the answers 5040? (:

  5. anonymous
    • 5 years ago
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    Yes.

  6. anonymous
    • 5 years ago
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    im sorry! im terrible at math, im more of a science gal, but thank you soo much!

  7. anonymous
    • 5 years ago
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    no probs :)

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