anonymous
  • anonymous
find the distinguisable permutations in the group of letters: C A L C U L U S
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
You're trying to find all possible combinations of the letters, without distinguishing between 'different' U's, C's and L's. If you have 8 letters (as here), the total number of permutations taken 8 at a time is 8!. But, you have C, L and U's counted 2! times each (you can arrange C, 2! ways, for example). You must undo this excess counting, so you have\[\frac{8!}{2!^3}=\frac{8 \times 7!}{8}=7!=5040\]distinguishable permutations.
anonymous
  • anonymous
so after i work out the problem ill have my answr? or do i leave it as is
anonymous
  • anonymous
Oh, I think you're being asked to find the number of distinguishable permutations. It would take you forever to write them all out (there's 5040 of them!).

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anonymous
  • anonymous
so the answers 5040? (:
anonymous
  • anonymous
Yes.
anonymous
  • anonymous
im sorry! im terrible at math, im more of a science gal, but thank you soo much!
anonymous
  • anonymous
no probs :)

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