The volume of the solid that results when y=6/7x^2 and y=13/7-x^2 is rotated around the x-axis.

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The volume of the solid that results when y=6/7x^2 and y=13/7-x^2 is rotated around the x-axis.

Mathematics
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okay i think this it: \[\int\limits_{-1}^{1}\] (13/7 - x^2)^2 - (6/7 x^2)^2 dx
oh yeah then multiply by pi
didja get that :)

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Thankssss
you should only do the righthalf tho; from 0 to 1 otherwise it might give you a zero
Actually, I had to find the points of intersection and that's what the integral had to be from and to.
Thanks, guys. I really appreciate it.

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