## anonymous 5 years ago The volume of the solid that results when y=6/7x^2 and y=13/7-x^2 is rotated around the x-axis.

1. anonymous

okay i think this it: $\int\limits_{-1}^{1}$ (13/7 - x^2)^2 - (6/7 x^2)^2 dx

2. anonymous

oh yeah then multiply by pi

3. amistre64

didja get that :)

4. anonymous

Thankssss

5. amistre64

you should only do the righthalf tho; from 0 to 1 otherwise it might give you a zero

6. anonymous

Actually, I had to find the points of intersection and that's what the integral had to be from and to.

7. anonymous

Thanks, guys. I really appreciate it.