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anonymous

  • 5 years ago

I am in need of help with algebra and graphing linear equations.

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  1. anonymous
    • 5 years ago
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    What is the equation?

  2. anonymous
    • 5 years ago
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    I have to graph the equation and identify the y intercept: x+2y=6

  3. anonymous
    • 5 years ago
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    It's always easier to change into slope intercept form. y=mx+b, so your equation becomes y=6/2-x/2----> y=(-1/2)x + 3, and b is always your y intercept, so to graph, make a point at your b value, and go rise over run from your slope taking into consideration of the minus value

  4. anonymous
    • 5 years ago
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    I am not understanding this

  5. anonymous
    • 5 years ago
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    Do you know what and how to change into slope intercept form? so what I did was try to isolate y by itself on one side of the equation. Thus, first step is to subtract x to both sides, and divide by 2 by both sides. so you get y=(6-x)/2. To simplify, you can then split up the division part of the equation to get y=6/2 - x/2. I swapped the two values on the left side of the equation to get a form that is similar to slope intercept form. y=(-x/2) + 3. This is your slope intercept form because you got y=mx(slope) + b(y-intercept). To graph, you plot your y intercept, or your b value to point (0,3). Then, because the slope is negative, our line is going be diagonal down from left to right, with left points being higher than right points. Then because slope is rise over run, you go down (becuase negative) 1, and run right two points; if you choose to go up, then run two points to the left, and vice versa if slope was positve

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