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anonymous

  • 5 years ago

Suppose that a ball is thrown straight up into the air and its height after t seconds is 5 + 32t – 16t^2 feet. Determine the maximum height of the ball.

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  1. anonymous
    • 5 years ago
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    well the easy way to do this would be to plug in the equation in a graphing calculator

  2. anonymous
    • 5 years ago
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    the time of the maximum height is given by -b/ 2a in this prob b =32 and a = -16. find this value for t and plug it into the quadratic and you got your max height

  3. anonymous
    • 5 years ago
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    differentiate to find velocity and we know that when height is max v = 0 so find time then replug into the height equation gives you time is 1 when max and height is 21

  4. anonymous
    • 5 years ago
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    Okay, I keep getting the wrong answer, what do you have?

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