anonymous
  • anonymous
Write (sin13+sin167+cos13+cos167)(sin13-sin167+cos13-cos167) in the form asinx. No calculators. Thank you!
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
sin 13 = sin 167 because sin is positive in second quad cos 13 + cos 167 = 0 because cos is negative in the second quad
anonymous
  • anonymous
i can get it down to 4sin13cos13 don't know how to put it solely in the form of asinx
anonymous
  • anonymous
so it becomes (sin13+sin167)(cos13-cos167), and then..

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anonymous
  • anonymous
sin 13 = sin 167 so (sin 13 +sin 167 ) = 2sin 13
anonymous
  • anonymous
cos13 = -cos167 so cos 13 - cos 167 = 2cos13
anonymous
  • anonymous
there's a reduction formula that says sin(0.5pi - theta) = costheta
anonymous
  • anonymous
this is where i have to get off. hope that helped.
anonymous
  • anonymous
yes it did. thanks!
anonymous
  • anonymous
sin(90-13) = cos13 is that right?
anonymous
  • anonymous
Yes, that's right.

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