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anonymous

  • 5 years ago

Write (sin13+sin167+cos13+cos167)(sin13-sin167+cos13-cos167) in the form asinx. No calculators. Thank you!

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  1. anonymous
    • 5 years ago
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    sin 13 = sin 167 because sin is positive in second quad cos 13 + cos 167 = 0 because cos is negative in the second quad

  2. anonymous
    • 5 years ago
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    i can get it down to 4sin13cos13 don't know how to put it solely in the form of asinx

  3. anonymous
    • 5 years ago
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    so it becomes (sin13+sin167)(cos13-cos167), and then..

  4. anonymous
    • 5 years ago
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    sin 13 = sin 167 so (sin 13 +sin 167 ) = 2sin 13

  5. anonymous
    • 5 years ago
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    cos13 = -cos167 so cos 13 - cos 167 = 2cos13

  6. anonymous
    • 5 years ago
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    there's a reduction formula that says sin(0.5pi - theta) = costheta

  7. anonymous
    • 5 years ago
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    this is where i have to get off. hope that helped.

  8. anonymous
    • 5 years ago
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    yes it did. thanks!

  9. anonymous
    • 5 years ago
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    sin(90-13) = cos13 is that right?

  10. anonymous
    • 5 years ago
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    Yes, that's right.

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