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anonymous
 5 years ago
Write (sin13+sin167+cos13+cos167)(sin13sin167+cos13cos167) in the form asinx. No calculators.
Thank you!
anonymous
 5 years ago
Write (sin13+sin167+cos13+cos167)(sin13sin167+cos13cos167) in the form asinx. No calculators. Thank you!

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin 13 = sin 167 because sin is positive in second quad cos 13 + cos 167 = 0 because cos is negative in the second quad

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i can get it down to 4sin13cos13 don't know how to put it solely in the form of asinx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it becomes (sin13+sin167)(cos13cos167), and then..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin 13 = sin 167 so (sin 13 +sin 167 ) = 2sin 13

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cos13 = cos167 so cos 13  cos 167 = 2cos13

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there's a reduction formula that says sin(0.5pi  theta) = costheta

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is where i have to get off. hope that helped.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sin(9013) = cos13 is that right?
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